Ethereum 坚固性：合同调用另一个合同和地址不同，为什么？

我有一个包装器契约，它实例化并调用另一个契约，我的测试用例说所有者（msg.sender）不匹配。为什么?

合同A

pragma solidity ^0.4.4;

contract A {

    address public owner;

    function A() {
         owner = msg.sender;
    }

    function createB(string name) {
        return new B(msg.sender, name);
    }
}

合同B

pragma solidity ^0.4.4;

contract B {
    address public owner;
    string public name;

    function B(address _owner, string _name) {
        owner = _owner;
        name = _name;
    }
}

测试用例

pragma solidity ^0.4.0;

import "truffle/Assert.sol";
import "truffle/DeployedAddresses.sol";
import "../contracts/B.sol";

contract TestB {
    B testB;
    A testA;

    function beforeEach() {
        A = A(DeployedAddresses.A());
        B = testA.createB("test");
    }

    function testOwnerIsSet() {
        Assert.equal(address(A), address(B), "Owner's address does not match");
    }
}

测试结果

 1) TestB testOwnerIsSet:
     Error: Owner's address does not match
      at /Users/xxx/.config/yarn/global/node_modules/truffle/build/cli.bundled.js:214233:17
      at Array.forEach (native)
      at processResult (/Users/xxx/.config/yarn/global/node_modules/truffle/build/cli.bundled.js:214231:19)
      at process._tickCallback (internal/process/next_tick.js:109:7)

编辑

我已将

地址公共所有者

添加到

合同A

。并在

合同B

中公开了

所有者

现在我的TestB合同如下所示：

pragma solidity ^0.4.0;

import "truffle/Assert.sol";
import "truffle/DeployedAddresses.sol";
import "../contracts/B.sol";

contract TestB {
    B testB;
    A testA;

    function beforeEach() {
        A = A(DeployedAddresses.A());
        B = testA.createB("test");
    }

    function testOwnerIsSet() {
        address aOwner = A.owner();
        address bOwner = B.owner();
        Assert.equal(aOwner, bOwner, "Owner's address does not match");
    }
}

---

根据你所展示的，我假设你用的是块菌？老实说，我很惊讶这一点

当你打电话时

B = testA.createB("test");

您正在从

TestB

调用它

msg.sender

将是

TestB

的地址

function createB(string name) {
    return new B(msg.sender, name); // msg.sender = TestB instance address
}

---

可能有助于实现您的目标。

根据您的演示，我假设您正在使用块菌？老实说，我很惊讶这一点

当你打电话时

B = testA.createB("test");

您正在从

TestB

调用它

msg.sender

将是

TestB

的地址

function createB(string name) {
    return new B(msg.sender, name); // msg.sender = TestB instance address
}

可能有助于实现您正在尝试的目标