Excel 打印标题从一个位置导入到另一个位置

我创建了一个vba脚本来解析不同帖子的

标题

，以及来自网站的这些帖子的

编辑状态

。我现在想做的是让我的脚本从它的登录页解析

标题

，但在打印

编辑状态

的同时打印

标题

。我不希望为此任务创建两个sub。我甚至不知道这在vba中是否可行。但是，如果有任何不清楚的地方，请查看我脚本中的评论

Sub ImportTitleFromAnotherLocation()
    Const LINK$ = "https://stackoverflow.com/questions/tagged/web-scraping"
    Const prefix$ = "https://stackoverflow.com"
    Dim Http As New XMLHTTP60, Html As New HTMLDocument
    Dim editInfo As Object, I&, targetUrl$, postTile$

    With Http
        .Open "GET", LINK, False
        .send
        Html.body.innerHTML = .responseText
    End With

    With Html.querySelectorAll(".summary .question-hyperlink")
        For I = 0 To .Length - 1

            postTitle = .item(I).innerText 'I like this line to be transferred to the location below

            targetUrl = Replace(.item(I).getAttribute("href"), "about:", prefix)
            With Http
                .Open "GET", targetUrl, False
                .send
                Html.body.innerHTML = .responseText
            End With

            R = R + 1: Cells(R, 1) = postTitle 'here I wish to use the above line like this

            Set editInfo = Html.querySelector(".user-action-time > a")
            If Not editInfo Is Nothing Then
                Cells(R, 2) = editInfo.innerText
            End If
        Next I
    End With
End Sub

---

您正在覆盖循环中的html文档。一个简单的方法是使用第二个htmldocument变量。更详细的方法是在循环之前存储标题，例如在附加循环期间存储在数组中，然后使用i变量索引到该数组中，以在现有循环期间检索每个标题

Sub ImportTitleFromAnotherLocation()
    Const LINK$ = "https://stackoverflow.com/questions/tagged/web-scraping"
    Const prefix$ = "https://stackoverflow.com"
    Dim Http As New XMLHTTP60, Html As New HTMLDocument, Html2 As New HTMLDocument

    Dim editInfo As Object, I&, targetUrl$, postTile$
    Dim postTitle As String, r As Long
    With Http
        .Open "GET", LINK, False
        .send
        Html.body.innerHTML = .responseText
    End With

    With Html.querySelectorAll(".summary .question-hyperlink")
        For I = 0 To .Length - 1
            postTitle = .item(I).innerText 'I like this line to be transferred to the location below
            targetUrl = Replace$(.item(I).getAttribute("href"), "about:", prefix)

            With Http
                .Open "GET", targetUrl, False
                .send
                Html2.body.innerHTML = .responseText
            End With

            r = r + 1: ActiveSheet.Cells(r, 1) = postTitle 'here I wish to use the above line like this

            Set editInfo = Html2.querySelector(".user-action-time > a")
            If Not editInfo Is Nothing Then
                ActiveSheet.Cells(r, 2) = editInfo.innerText
            End If
        Next I
    End With
End Sub