Function 网页包不'；无法识别功能参数

我已经定义了一个函数，希望使用节点将所有内容打包到webpack中。以下是函数：

var makeReq = require('./makeReq.js');
var api = "sampleApi";

function videosDetails(videos) {

    var n = videos.length;
    var ids;

    for (var i = 0; i < n; i++) {
        var id = videos[i];
        ids += id.toString() + ','  ;
    };

    var url = api.concat(ids);
    var req = makeReq.makeReq(url);

    for (var i = 0; i < n; i++) {
        videos[i].details = req.items[i].contentDetails;
        videos[i].details = req.items[i].statistics;
    };

    return videos;
};

module.exports = {
    videosDetails: videosDetails()
}

var makeReq=require（'./makeReq.js'）；
var api=“sampleApi”；
功能视频详细信息（视频）{
var n=视频长度；
变量ID；
对于（变量i=0；i

在Chrome的控制台上编译时出现错误：

Uncaught TypeError: Cannot read property 'length' of undefined
at videosDetails (app.bundle.js:197)
at Object.<anonymous> (app.bundle.js:217)
at __webpack_require__ (app.bundle.js:20)

Uncaught TypeError:无法读取未定义的属性'length'
在videosDetails（app.bundle.js:197）
反对。（app.bundle.js:217）
at\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuwpack\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu

---

不理解当它是函数参数时为什么不能识别。提前感谢您的时间。

您正在呼叫

videosDetails（）

，没有任何参数：

module.exports = {
    videosDetails: videosDetails()
}

module.exports = {
    videosDetails: videosDetails
}

导出的是

videosDetails

的返回值，而不是函数本身。当您在没有参数的情况下调用它时，

视频

将是未定义的

您可能想要导出函数：

var makeReq = require('./makeReq.js');
var api = "sampleApi";

function videosDetails(videos) {

    var n = videos.length;
    var ids;

    for (var i = 0; i < n; i++) {
        var id = videos[i];
        ids += id.toString() + ','  ;
    };

    var url = api.concat(ids);
    var req = makeReq.makeReq(url);

    for (var i = 0; i < n; i++) {
        videos[i].details = req.items[i].contentDetails;
        videos[i].details = req.items[i].statistics;
    };

    return videos;
};

module.exports = {
    videosDetails: videosDetails()
}