Google bigquery 在Bigquery中同时给出两个值（在“then”和“else”中的值）的Case语句。怎么了？

我想在Bigquery中创建一个标志，当为真时返回1，当为假时返回0。当语句必须返回0的“else”值时，它可以正常工作。但是，当它满足条件时，它返回两行，其中包含1和0。为什么会这样

以下是使用的代码：

table AS(
  SELECT
    id,
    month,
    ROUND((text/(month_days/7)), 2) AS value
    FROM (SELECT id, extract(month FROM date) AS month,
   (32 - EXTRACT(DAY FROM DATE_ADD(DATE_TRUNC(DATE(date), MONTH), INTERVAL 31 DAY))) AS month_days,
    sum(text_sent) AS text
    FROM table1
    WHERE date BETWEEN '2020-01-01 00:00:00 UTC' AND '2020-06-30 00:00:00 UTC'
    GROUP BY 1,2,3)),
    
table_flag AS(
SELECT
id,
CASE
WHEN month = 1 AND value > 100 THEN 1
WHEN month = 2 AND value > 150 THEN 1
WHEN month = 3 AND value > 130 THEN 1
WHEN month = 4 AND value > 200 THEN 1
WHEN month = 5 AND value > 235 THEN 1
WHEN month = 6 AND value > 125 THEN 1
WHEN month = 7 AND value > 324 THEN 1
WHEN month = 8 AND value > 160 THEN 1
WHEN month = 9 AND value > 350 THEN 1
WHEN month = 10 AND value > 80 THEN 1
WHEN month = 11 AND value > 245 THEN 1
ELSE 0
END AS value_flag
FROM
table)

SELECT
  t.id,
  t.value,
  t.month,
  tf.value_flag
  FROM
  table t
 LEFT JOIN
  table_flag tf
  ON
  t.id = tf.id
  WHERE t.id IS NOT NULL
   GROUP BY 1,2,3,4
   ORDER BY 1

我也尝试过嵌套IF，但也不起作用：

SELECT DISTINCT(id),
(IF((month = 1 AND value > 100), 1,
(IF((month = 2 AND value > 150), 1,
(IF((month = 3 AND value > 130), 1,
(IF((month = 4 AND value > 200), 1,
(IF((month = 5 AND value > 235), 1,
(IF((month = 6 AND value > 125), 1,
(IF((month = 7 AND value > 324), 1,
(IF((month = 8 AND value > 160), 1,
(IF((month = 9 AND value > 350), 1,
(IF((month = 10 AND value > 80), 1,
(IF((month = 11 AND value > 245), 1,0))))))))))))))))))))))
AS value_flag
FROM table)

这就是输出现在的样子（这不是我想要的）：

输出完全错误。请建议替代方法（如有）

---

注：这是我的第一个问题，如果需要其他信息，请告诉我。提前感谢您的帮助

table和

table\u flag

都有多行具有相同的

id

。对

表中的每一行进行BigQuery

可以在

表\u标志

中找到几行。要删除重复项，我们可以将

month

添加到

table_flag

和

ON

子句中。但是我们实际上不需要最后一个

左连接。试试这个：

WITH table AS(
  SELECT
    id,
    month,
    ROUND((text/(month_days/7)), 2) AS value
  FROM (
    SELECT 
      id, 
      extract(month FROM date) AS month,
      (32 - EXTRACT(DAY FROM DATE_ADD(DATE_TRUNC(DATE(date), MONTH), INTERVAL 31 DAY))) AS month_days,
      sum(text_sent) AS text
    FROM table1
    WHERE 
      date BETWEEN '2020-01-01 00:00:00 UTC' AND '2020-06-30 00:00:00 UTC'
      AND id IS NOT NULL
    GROUP BY 1,2,3
  )
)
SELECT
  id,
  value,
  month,
  CASE
    WHEN month = 1 AND value > 100 THEN 1
    WHEN month = 2 AND value > 150 THEN 1
    WHEN month = 3 AND value > 130 THEN 1
    WHEN month = 4 AND value > 200 THEN 1
    WHEN month = 5 AND value > 235 THEN 1
    WHEN month = 6 AND value > 125 THEN 1
    WHEN month = 7 AND value > 324 THEN 1
    WHEN month = 8 AND value > 160 THEN 1
    WHEN month = 9 AND value > 350 THEN 1
    WHEN month = 10 AND value > 80 THEN 1
    WHEN month = 11 AND value > 245 THEN 1
    ELSE 0
  END AS value_flag
FROM table
ORDER BY 1

或者这个：

SELECT
  id,
  month,
  ROUND((text/(month_days/7)), 2) AS value,
  CASE
    WHEN month = 1 AND ROUND((text/(month_days/7)), 2) > 100 THEN 1
    WHEN month = 2 AND ROUND((text/(month_days/7)), 2) > 150 THEN 1
    WHEN month = 3 AND ROUND((text/(month_days/7)), 2) > 130 THEN 1
    WHEN month = 4 AND ROUND((text/(month_days/7)), 2) > 200 THEN 1
    WHEN month = 5 AND ROUND((text/(month_days/7)), 2) > 235 THEN 1
    WHEN month = 6 AND ROUND((text/(month_days/7)), 2) > 125 THEN 1
    WHEN month = 7 AND ROUND((text/(month_days/7)), 2) > 324 THEN 1
    WHEN month = 8 AND ROUND((text/(month_days/7)), 2) > 160 THEN 1
    WHEN month = 9 AND ROUND((text/(month_days/7)), 2) > 350 THEN 1
    WHEN month = 10 AND ROUND((text/(month_days/7)), 2) > 80 THEN 1
    WHEN month = 11 AND ROUND((text/(month_days/7)), 2) > 245 THEN 1
    ELSE 0
  END AS value_flag
FROM (
  SELECT 
    id, 
    extract(month FROM date) AS month,
    (32 - EXTRACT(DAY FROM DATE_ADD(DATE_TRUNC(DATE(date), MONTH), INTERVAL 31 DAY))) AS month_days,
    sum(text_sent) AS text
  FROM table1
  WHERE 
    date BETWEEN '2020-01-01 00:00:00 UTC' AND '2020-06-30 00:00:00 UTC'
    AND id IS NOT NULL
  GROUP BY 1,2,3
)
ORDER BY 1

我已经编辑了我的问题，请看一看！更新了有效的答案！我之所以有连接，是因为我还有一个表要添加，这可能就是导致问题的原因。非常感谢你的帮助！考虑接受和投票：