hibernate查询语言
请在hql中转换sql SQL语句:从useraccout where email=“参数值”中选择用户名 更多说明: 运行代码时,我遇到以下错误:hibernate查询语言,hibernate,hql,Hibernate,Hql,请在hql中转换sql SQL语句:从useraccout where email=“参数值”中选择用户名 更多说明: 运行代码时,我遇到以下错误: public List dispUser(String email){ Query query = em.createQuery("SELECT u.username FROM Useraccout u WHERE u.email=:email)"); query.setParameter(email, email); L
public List dispUser(String email){
Query query = em.createQuery("SELECT u.username FROM Useraccout u WHERE u.email=:email)");
query.setParameter(email, email);
List search = query.getResultList();
return search;
}
运行代码时,我遇到以下错误
java.lang.IllegalArgumentException: org.hibernate.hql.ast.QuerySyntaxException:
Useraccout is not mapped [SELECT u.username FROM Useraccout u WHERE u.email=:email1)]
at org.hibernate.ejb.AbstractEntityManagerImpl.throwPersistenceException(AbstractEntityManagerImpl.java:624)
at org.hibernate.ejb.AbstractEntityManagerImpl.createQuery(AbstractEntityManagerImpl.java:96)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
似乎您尚未映射名为
Useraccount
的类。我的猜测是:
- 您映射了一个名为
的类,并且在查询中键入的此类名称不正确Useraccount
- 您尚未映射任何类。这表明您不了解Hibernate的基础知识。简而言之,映射到数据库表的每个类都需要使用XML文件或注释定义此映射