Hive 蜂箱罐';t使用嵌套的avro模式创建表

Hive 蜂箱罐';t使用嵌套的avro模式创建表,hive,nested,schema,avro,Hive,Nested,Schema,Avro,我正在尝试使用嵌套的avro模式来创建配置单元表。但它不起作用。我正在使用cdh5.7.2中的Hive1.1 以下是我的嵌套avro模式: [ { "type": "record", "name": "Id", "namespace": "com.test.app_list", "doc": "Device ID", "fields": [ { "nam

我正在尝试使用嵌套的avro模式来创建配置单元表。但它不起作用。我正在使用cdh5.7.2中的Hive1.1

以下是我的嵌套avro模式:

[
    {
        "type": "record",
        "name": "Id",
        "namespace": "com.test.app_list",
        "doc": "Device ID",
        "fields": [
            {
                "name": "idType",
                "type": "int"
            },{
                "name": "id",
                "type": "string"
            }
        ]
    },

    {
        "type": "record",
        "name": "AppList",
        "namespace": "com.test.app_list",
        "doc": "",
        "fields": [
            {
                "name": "appId",
                "type": "string",
                "avro.java.string": "String"
            },
            {
                "name": "timestamp",
                "type":  "long"
            },

            {
                "name": "idList",
                "type": [{"type": "array", "items": "com.test.app_list.Id"}]
            }

        ]
    }
]
和我的sql来创建表:

CREATE EXTERNAL TABLE app_list
ROW FORMAT SERDE
'org.apache.hadoop.hive.serde2.avro.AvroSerDe'
STORED AS INPUTFORMAT
'org.apache.hadoop.hive.ql.io.avro.AvroContainerInputFormat'
OUTPUTFORMAT
'org.apache.hadoop.hive.ql.io.avro.AvroContainerOutputFormat'
TBLPROPERTIES (
'avro.schema.url'='/hive/schema/test_app_list.avsc');
但蜂巢给了我:

FAILED: Execution Error, return code 1 from org.apache.hadoop.hive.ql.exec.DDLTask. java.lang.RuntimeException: MetaException(message:org.apache.hadoop.hive.serde2.avro.AvroSerdeException Schema for table must be of type RECORD. Received type: UNION)
hive
doc显示:
支持任意嵌套的架构。
from:

数据样本:

{
    "appId":{"string":"com.test.app"},
    "timestamp":{"long":1495893601606},
    "idList":{
        "array":[
            {"idType":15,"id":"6c:5c:14:c3:a5:39"},
            {"idType":13,"id":"eb297afe56ff340b6bb7de5c5ab09193"}
        ]
    }

}

但我不知道怎么做。我需要一些帮助来解决这个问题。谢谢

avro模式的顶层应该是记录类型,这就是为什么Hive不允许这样做的原因。解决方法可以是将顶层创建为记录,内部创建两个字段作为记录类型

{ 
        "type": "record",
        "name": "myRecord",
        "namespace": "com.test.app_list"
          "fields": [
    {
        "type": "record",
        "name": "Id",
        "doc": "Device ID",
        "fields": [
            {
                "name": "idType",
                "type": "int"
            },{
                "name": "id",
                "type": "string"
            }
        ]
    },

    {
        "type": "record",
        "name": "AppList",
        "doc": "",
        "fields": [
            {
                "name": "appId",
                "type": "string",
                "avro.java.string": "String"
            },
            {
                "name": "timestamp",
                "type":  "long"
            },

            {
                "name": "idList",
                "type": [{"type": "array", "items": "com.test.app_list.Id"}]
            }

        ]
    }
    ]
}

已经添加了数据样本。谢谢你。我根据你的提示更改了模式。它是有效的。