如何获取当前_日期和Hive中存档的时间之间的天数？

mytable中有两个时间戳：

“regdate”的格式为bigint，例如“20120719044326”； “subscr_date”，例如“

2012-07-19 04:43:26

”的格式为不同的国家字符

我想将当前_日期和regdate之间的天数作为reg_天数；当前日期和子CRU日期之间的天数为子CRU天

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那么如何在配置单元中编写查询呢？

如果regdate和subscr\u date是字符串：

select datediff(current_date,from_unixtime(unix_timestamp(unix_timestamp(regdate, 'yyyyMMddhhmmss'), 'yyyy-MM-dd')) as reg_days,
datediff(current_date,from_unixtime(unix_timestamp(subscr_date, 'yyyy-MM-dd hh:mm:ss'), 'yyyy-MM-dd')) as subscr_days
from mytable;

如果regdate是BigInt，subscr_date是字符串：

select datediff(current_date,from_unixtime(unix_timestamp(unix_timestamp(CAST(regdate AS STRING), 'yyyyMMddhhmmss'), 'yyyy-MM-dd')) as reg_days,
datediff(current_date,from_unixtime(unix_timestamp(subscr_date, 'yyyy-MM-dd hh:mm:ss'), 'yyyy-MM-dd')) as subscr_days
from mytable;

如果登记日期和子登记日期为2012-07-19，而当前日期为2016-09-01，则结果为：

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注册日1504子注册日1504

如果注册日和子注册日为字符串：

select datediff(current_date,from_unixtime(unix_timestamp(unix_timestamp(regdate, 'yyyyMMddhhmmss'), 'yyyy-MM-dd')) as reg_days,
datediff(current_date,from_unixtime(unix_timestamp(subscr_date, 'yyyy-MM-dd hh:mm:ss'), 'yyyy-MM-dd')) as subscr_days
from mytable;

如果regdate是BigInt，subscr_date是字符串：

select datediff(current_date,from_unixtime(unix_timestamp(unix_timestamp(CAST(regdate AS STRING), 'yyyyMMddhhmmss'), 'yyyy-MM-dd')) as reg_days,
datediff(current_date,from_unixtime(unix_timestamp(subscr_date, 'yyyy-MM-dd hh:mm:ss'), 'yyyy-MM-dd')) as subscr_days
from mytable;

如果登记日期和子登记日期为2012-07-19，而当前日期为2016-09-01，则结果为：

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reg_天1504subscr_天1504

两个regdate和subscr_日期指示相同的日期？两个regdate和subscr_日期指示相同的日期？