Ios 如何从数组中的dictionary中的value中获取key?
这是数组中的字典Ios 如何从数组中的dictionary中的value中获取key?,ios,objective-c,arrays,key,nsdictionary,Ios,Objective C,Arrays,Key,Nsdictionary,这是数组中的字典 array With Dict : ( { id = 1; name = Arjun; }, { id = 2; name = Karan; }, { id = 3; name = Ajit; }, { id = 4; name = Prashant; },
array With Dict : (
{
id = 1;
name = Arjun;
},
{
id = 2;
name = Karan;
},
{
id = 3;
name = Ajit;
},
{
id = 4;
name = Prashant;
},
{
id = 5;
name = Sushant;
}
)
当我选择任何“值”时,我想获取与该值关联的“键”
例如:
假设我选择了“Prashant”,我想要它的“id”,即4
如何从“值”中获取“键”?您可以在数组中循环查找匹配的条目-您要查找的值。然后获取它的键。您可以在数组中循环,找到您要查找的匹配项-值。然后拿到它的钥匙。试试答案…………试试答案…………这对我也很有用。谢谢,塞尔吉奥。但我已经接受了前面的答案。这对我来说也适用。谢谢,塞尔吉奥。但我已经接受了前面的答案。
for (NSDictionary*dic in array)
{
NSString * name = dic[@"name"];
if([name isEqual:currentSelectedName])
{
NSString * id = dic[@"id"];
NSLog(@"id is : %@",id);
}
}
NSString *myName = @"Prashant";
for (NSDictionary *dict in array) {
if ([dict[@"name"] isEqualToString:myName]) {
NSLog(@"%@", dict[@"id"]);
break;
}
}