Ios 使用所选键解析.com关系查询

Ios 使用所选键解析.com关系查询,ios,swift,parse-platform,key,Ios,Swift,Parse Platform,Key,我试图用一些键进行关系查询,但它返回所有键。 我做错了什么 query.getObjectInBackgroundWithId(objectId) { (object:PFObject?, error:NSError?) -> Void in if error == nil { var relation: PFRelation = object!.relationForKey("MenuDetails") relation

我试图用一些键进行关系查询,但它返回所有键。 我做错了什么

query.getObjectInBackgroundWithId(objectId) { (object:PFObject?, error:NSError?) -> Void in
        if error == nil {

            var relation: PFRelation = object!.relationForKey("MenuDetails")

            relation.query()!.selectKeys(["Receipe_Lvl1"])

            var testArray = NSMutableArray()

            relation.query()!.findObjectsInBackgroundWithBlock {
                (objects: [AnyObject]?, error: NSError?) -> Void in
                if error == nil {
                    if let objects = objects as? [PFObject] {
                        for object in objects {
                            testArray.addObject(object)
                        }
                    }
                } else {

                }

            }

        }


    }

感谢您的帮助

我从未使用过Parse,但我认为您应该链接方法

query.getObjectInBackgroundWithId(objectId) { (object:PFObject?, error:NSError?) -> Void in
        if error == nil {

            var relation: PFRelation = object!.relationForKey("MenuDetails")


            var testArray = NSMutableArray()

           relation.query()!.selectKeys(["Receipe_Lvl1"]).findObjectsInBackgroundWithBlock {
                (objects: [AnyObject]?, error: NSError?) -> Void in
                if error == nil {
                    if let objects = objects as? [PFObject] {
                        for object in objects {
                            testArray.addObject(object)
                        }
                    }
                } else {

                }

            }

        }


    }