Ios Swift-推送警报操作以显示新的ViewController

当按钮处于警报状态时，如何显示或链接到新的ViewController

这是我的密码

let alert = UIAlertController(title: validateQRObj.responseDescription, message: validateQRObj.productName, preferredStyle: .alert)
let action = UIAlertAction(title: "OK", style: .default) { (action) -> Void in
    let viewController = self.storyboard?.instantiateViewController(withIdentifier: "ProductDetialViewController")
    self.present(viewController!, animated: true, completion: nil)
}
alert.addAction(action)
self.present(alert, animated: true, completion: nil)

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控制从视图控制器1（黄点）拖动到视图控制器2上的任何位置，然后单击该段。显示属性检查器，并在序列图像板序列标识符名称下显示标识符VC2

如果这是你一直在寻找的答案，别忘了回答

func alert(){

    let alertController = UIAlertController(title: "Open View Controller. ", message: "Press  Ok  to open View Controller number 2.", preferredStyle: UIAlertControllerStyle.alert)
    let ok = UIAlertAction(title: "Ok", style: UIAlertActionStyle.default, handler: {(action) -> Void in
    //The (withIdentifier: "VC2") is the Storyboard Segue identifier.
    self.performSegue(withIdentifier: "VC2", sender: self)
 })

    alertController.addAction(ok)
    self.present(alertController, animated: true, completion: nil)
}

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对我来说，它不起作用。我提出：

    func alert(){
    let storyboard = UIStoryboard(name: "Main", bundle: nil)
    let twop = storyboard.instantiateViewController(withIdentifier: "Accueil") as! Accueil
    let alertController = UIAlertController(title: "Open new View !", message: "Clic to ok", preferredStyle: UIAlertControllerStyle.alert)
    let ok = UIAlertAction(title: "Ok", style: UIAlertActionStyle.default, handler: {(action) -> Void in
        self.navigationController?.show(twop, sender: self)
    })

    alertController.addAction(ok)
    self.present(alertController, animated: true, completion: nil)
}

---

现在它开始工作了

你发布的代码有什么问题？