Ios 使用UITableView发出分页
我试图使用UITableView和AFNetworking在Instagram中创建一个无限滚动类型的东西,但是当我到达视图底部时,我遇到了这个错误:Ios 使用UITableView发出分页,ios,iphone,objective-c,uitableview,uiscrollview,Ios,Iphone,Objective C,Uitableview,Uiscrollview,我试图使用UITableView和AFNetworking在Instagram中创建一个无限滚动类型的东西,但是当我到达视图底部时,我遇到了这个错误: CRASH : -[__NSCFArray insertObject:atIndex:]: mutating method sent to immutable object 2014-01-05 20:51:41.627 Floadt[1579:70b] STACK TRACE : ( 0 CoreFoundation
CRASH :
-[__NSCFArray insertObject:atIndex:]: mutating method sent to immutable object
2014-01-05 20:51:41.627 Floadt[1579:70b] STACK TRACE :
(
0 CoreFoundation 0x02b775e4 __exceptionPreprocess + 180
1 libobjc.A.dylib 0x027a38b6 objc_exception_throw + 44
2 CoreFoundation 0x02b773bb +[NSException raise:format:] + 139
3 CoreFoundation 0x02bfe365 -[__NSCFArray insertObject:atIndex:] + 101
4 CoreFoundation 0x02b3b2d0 -[NSMutableArray insertObjects:count:atIndex:] + 208
5 CoreFoundation 0x02b3af69 -[NSMutableArray insertObjectsFromArray:range:atIndex:] + 425
6 CoreFoundation 0x02b3ad15 -[NSMutableArray addObjectsFromArray:] + 661
7 Floadt 0x0003f5ec __42-[StreamViewController nextInstagramPage:]_block_invoke + 284
8 Floadt 0x0001edfb __64-[AFJSONRequestOperation setCompletionBlockWithSuccess:failure:]_block_invoke91 + 43
9 libdispatch.dylib 0x035247f8 _dispatch_call_block_and_release + 15
10 libdispatch.dylib 0x035394b0 _dispatch_client_callout + 14
11 libdispatch.dylib 0x0352775e _dispatch_main_queue_callback_4CF + 340
12 CoreFoundation 0x02bdca5e __CFRUNLOOP_IS_SERVICING_THE_MAIN_DISPATCH_QUEUE__ + 14
13 CoreFoundation 0x02b1d6bb __CFRunLoopRun + 1963
14 CoreFoundation 0x02b1cac3 CFRunLoopRunSpecific + 467
15 CoreFoundation 0x02b1c8db CFRunLoopRunInMode + 123
16 GraphicsServices 0x0453c9e2 GSEventRunModal + 192
17 GraphicsServices 0x0453c809 GSEventRun + 104
18 UIKit 0x01936d3b UIApplicationMain + 1225
19 Floadt 0x0006646d main + 141
20 libdyld.dylib 0x037cb70d start + 1
21 ??? 0x00000001 0x0 + 1
)
下面是我如何编写代码的过程,让我困惑的是,我的所有数组都是可变的,但它声明了变异方法被发送到了一个不可变的对象:
- (void)scrollViewDidScroll:(UIScrollView *)scrollView
{
if (scrollView.contentOffset.y == roundf(scrollView.contentSize.height-scrollView.frame.size.height)) {
NSDictionary *page = instagramResponse[@"pagination"];
NSString *nextPage = page[@"next_url"];
[[InstagramClient sharedClient] getPath:[NSString stringWithFormat:@"%@",nextPage] parameters:nil success:^(AFHTTPRequestOperation *operation, id responseObject) {
instagramResponse = [responseObject mutableCopy];
[instagramResponse addEntriesFromDictionary:responseObject];
[instaPics addObjectsFromArray:responseObject[@"data"]];
[self.tableView reloadData];
} failure:^(AFHTTPRequestOperation *operation, NSError *error) {
NSLog(@"Failure: %@", error);
}];
}
}
在
addEntriesFromDictionary
之前,字典的副本如下
NSDictionary *copyOfDic = [[NSDictionary alloc] initWithDictionary: originalDic copyItems: YES];
if (copyOfDic ) {
[destination addEntriesFromDictionary: copyOfDic ];
[copyOfDic release];
}
或
或
您的@property yourarray使用NSArray或声明的副本初始化
因为两者都会导致此错误/异常消息,因为支持ivar将指向(不可变)NSArray
如果您已将属性声明为NSMUTABLEARRY类型,请使用strong作为存储修饰符,而不是copy。我尝试执行您所述的操作,但遇到相同的错误。NSMutableArray已经很强。您会在NSZombie中遇到哪一行异常。请告诉我错误发生在
[instaPics addObjectsFromArray:responseObject[@“data]”行中代码>我编辑了我试图在应用程序内翻页的方式[instaPics addObjectsFromArray:[responseObject[@“data”]可变副本]];你试过了吗?堆栈跟踪不存在。在[StreamViewController nextInstagramPage:
中的block方法中查找addObjectsFromArray:
调用。找到数组的名称后,查找可能设置为不可变对象的位置。
[instaPics addObjectsFromArray:[responseObject[@"data"]mutable copy]];