在ios swift 3.0中解析json对象的数组

正在尝试在iOS swift 3.0中解析JSON数组。但在XCode中，我总是看到这个错误：

类型“NSFastEnumerationIterator.Element”（也称为“Any”）没有下标成员

我试图分析的数组如下所示：

[{"area_code":1,"area_name":"value"},{"area_code":2,"area_name":"value"},{"area_code":3,"area_name":"value"},{"area_code":4,"area_name":"value"}]

iOS的代码片段如下所示

let json = try!JSONSerialization.jsonObject(with: data!, options: .mutableLeaves) as? NSArray

            // The JSONObjectWithData constructor didn't return an error. But, we should still
            // check and make sure that json has a value using optional binding.
            if let parseJSON = json {
                for dayData in parseJSON{

                    let areaObj = AreaCode()

                    if let areaCode = dayData["area_code"] as? Int{
                        areaObj.areaCode = areaCode
                    }
                    if let areaName = dayData["area_name"] as? String{
                        areaObj.areaName = areaName
                    }
                    areaCodeArray.append(areaObj)
                }
                DispatchQueue.main.async(execute: {
                    // perform on main
                    self.onGetAreaList("Success");
                });
            }

---

用

[[String:Any]]

代替

NSArray

let json = try! JSONSerialization.jsonObject(with: data!, options: []) as? [[String:Any]]

     for dayData in json{
          let areaObj = AreaCode()

          if let areaCode = dayData["area_code"] as? Int{
              areaObj.areaCode = areaCode
          }

          if let areaName = dayData["area_name"] as? String{
               areaObj.areaName = areaName
          }

          areaCodeArray.append(areaObj)

---

@你救了我一天。谢谢。为什么要将选项作为[]传递？如果不想使用任何选项，请使用空数组@Zain，因为选项需要一种类型的数组来传递