Ios 在Swift中格式化电话号码
一旦用户开始将电话号码键入此格式类型,我将格式化我的文本文件,该格式类型为Ios 在Swift中格式化电话号码,ios,string,swift,uitextfield,string-formatting,Ios,String,Swift,Uitextfield,String Formatting,一旦用户开始将电话号码键入此格式类型,我将格式化我的文本文件,该格式类型为0(555)444 66 77,工作正常,但一旦我从服务器上获取号码,我就会像这样获取该号码05554446677,因此,请告诉我,一旦从服务器上获取该号码,如何以相同格式编辑该号码 我的代码一旦开始键入: func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string
0(555)444 66 77
,工作正常,但一旦我从服务器上获取号码,我就会像这样获取该号码05554446677
,因此,请告诉我,一旦从服务器上获取该号码,如何以相同格式编辑该号码
我的代码一旦开始键入:
func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {
if textField == phoneNumberTextField{
var newString = (textField.text as NSString).stringByReplacingCharactersInRange(range, withString: string)
var components = newString.componentsSeparatedByCharactersInSet(NSCharacterSet.decimalDigitCharacterSet().invertedSet)
var decimalString = "".join(components) as NSString
var length = decimalString.length
var hasLeadingOne = length > 0 && decimalString.characterAtIndex(0) == (1 as unichar)
if length == 0 || (length > 11 && !hasLeadingOne) || length > 12{
var newLength = (textField.text as NSString).length + (string as NSString).length - range.length as Int
return (newLength > 11) ? false : true
}
var index = 0 as Int
var formattedString = NSMutableString()
if hasLeadingOne{
formattedString.appendString("1 ")
index += 1
}
if (length - index) > 1{
var zeroNumber = decimalString.substringWithRange(NSMakeRange(index, 1))
formattedString.appendFormat("%@ ", zeroNumber)
index += 1
}
if (length - index) > 3{
var areaCode = decimalString.substringWithRange(NSMakeRange(index, 3))
formattedString.appendFormat("(%@) ", areaCode)
index += 3
}
if (length - index) > 3{
var prefix = decimalString.substringWithRange(NSMakeRange(index, 3))
formattedString.appendFormat("%@ ", prefix)
index += 3
}
if (length - index) > 3{
var prefix = decimalString.substringWithRange(NSMakeRange(index, 2))
formattedString.appendFormat("%@ ", prefix)
index += 2
}
var remainder = decimalString.substringFromIndex(index)
formattedString.appendString(remainder)
textField.text = formattedString as String
return false
}else{
return true
}
}
使用字符串中的字符进行操作不是很简单。您需要以下信息: Swift 2.1
let s = "05554446677"
let s2 = String(format: "%@ (%@) %@ %@ %@", s.substringToIndex(s.startIndex.advancedBy(1)),
s.substringWithRange(s.startIndex.advancedBy(1) ... s.startIndex.advancedBy(3)),
s.substringWithRange(s.startIndex.advancedBy(4) ... s.startIndex.advancedBy(6)),
s.substringWithRange(s.startIndex.advancedBy(7) ... s.startIndex.advancedBy(8)),
s.substringWithRange(s.startIndex.advancedBy(9) ... s.startIndex.advancedBy(10))
)
Swift 2.0
let s = "05554446677"
let s2 = String(format: "%@ (%@) %@ %@ %@", s.substringToIndex(advance(s.startIndex, 1)),
s.substringWithRange(advance(s.startIndex, 1) ... advance(s.startIndex, 3)),
s.substringWithRange(advance(s.startIndex, 4) ... advance(s.startIndex, 6)),
s.substringWithRange(advance(s.startIndex, 7) ... advance(s.startIndex, 8)),
s.substringWithRange(advance(s.startIndex, 9) ... advance(s.startIndex, 10))
)
代码将被打印出来
0(555)4446677
Swift 3&4
此解决方案在应用格式之前删除所有非数字字符。如果无法根据假设格式化源电话号码,则返回nil
斯威夫特4
Swift 4解决方案解释了CharacterView的不受欢迎以及Sting与CharacterView一样成为字符集合的原因
import Foundation
func format(phoneNumber sourcePhoneNumber: String) -> String? {
// Remove any character that is not a number
let numbersOnly = sourcePhoneNumber.components(separatedBy: CharacterSet.decimalDigits.inverted).joined()
let length = numbersOnly.count
let hasLeadingOne = numbersOnly.hasPrefix("1")
// Check for supported phone number length
guard length == 7 || (length == 10 && !hasLeadingOne) || (length == 11 && hasLeadingOne) else {
return nil
}
let hasAreaCode = (length >= 10)
var sourceIndex = 0
// Leading 1
var leadingOne = ""
if hasLeadingOne {
leadingOne = "1 "
sourceIndex += 1
}
// Area code
var areaCode = ""
if hasAreaCode {
let areaCodeLength = 3
guard let areaCodeSubstring = numbersOnly.substring(start: sourceIndex, offsetBy: areaCodeLength) else {
return nil
}
areaCode = String(format: "(%@) ", areaCodeSubstring)
sourceIndex += areaCodeLength
}
// Prefix, 3 characters
let prefixLength = 3
guard let prefix = numbersOnly.substring(start: sourceIndex, offsetBy: prefixLength) else {
return nil
}
sourceIndex += prefixLength
// Suffix, 4 characters
let suffixLength = 4
guard let suffix = numbersOnly.substring(start: sourceIndex, offsetBy: suffixLength) else {
return nil
}
return leadingOne + areaCode + prefix + "-" + suffix
}
extension String {
/// This method makes it easier extract a substring by character index where a character is viewed as a human-readable character (grapheme cluster).
internal func substring(start: Int, offsetBy: Int) -> String? {
guard let substringStartIndex = self.index(startIndex, offsetBy: start, limitedBy: endIndex) else {
return nil
}
guard let substringEndIndex = self.index(startIndex, offsetBy: start + offsetBy, limitedBy: endIndex) else {
return nil
}
return String(self[substringStartIndex ..< substringEndIndex])
}
}
示例输出
蒙面数字打字
所以,这是更好的工作
"" => ""
"0" => "+0"
"412" => "+4 (12"
"12345678901" => "+1 (234) 567-8901"
"a1_b2-c3=d4 e5&f6|g7h8" => "+1 (234) 567-8"
Swift 3,但也应可翻译为Swift 4
enum PhoneNumberFormattingError: Error {
case wrongCharactersInPhoneNumber
case phoneNumberLongerThanPatternAllowes
}
enum PhoneNumberFormattingPatterns: String {
case mobile = "+xx (yxx) xxxxxxxxxxx"
case home = "+xx (yxxx) xxxx-xxx"
}
/**
Formats a phone-number to correct format
- Parameter pattern: The pattern to format the phone-number.
- Example:
- x: Says that this should be a digit.
- y: Says that this digit cannot be a "0".
- The length of the pattern restricts also the length of allowed phone-number digits.
- phone-number: "+4306641234567"
- pattern: "+xx (yxx) xxxxxxxxxxx"
- result: "+43 (664) 1234567"
- Throws:
- PhoneNumberFormattingError
- wrongCharactersInPhoneNumber: if phone-number contains other characters than digits.
- phoneNumberLongerThanPatternAllowes: if phone-number is longer than pattern allows.
- Returns:
- The formatted phone-number due to the pattern.
*/
extension String {
func vpToFormattedPhoneNumber(withPattern pattern: PhoneNumberFormattingPatterns) throws -> String {
let phoneNumber = self.replacingOccurrences(of: "+", with: "")
var retVal: String = ""
var index = 0
for char in pattern.rawValue.lowercased().characters {
guard index < phoneNumber.characters.count else {
return retVal
}
if char == "x" {
let charIndex = phoneNumber.index(phoneNumber.startIndex, offsetBy: index)
let phoneChar = phoneNumber[charIndex]
guard "0"..."9" ~= phoneChar else {
throw PhoneNumberFormattingError.wrongCharactersInPhoneNumber
}
retVal.append(phoneChar)
index += 1
} else if char == "y" {
var charIndex = phoneNumber.index(phoneNumber.startIndex, offsetBy: index)
var indexTemp = 1
while phoneNumber[charIndex] == "0" {
charIndex = phoneNumber.index(phoneNumber.startIndex, offsetBy: index + indexTemp)
indexTemp += 1
}
let phoneChar = phoneNumber[charIndex]
guard "0"..."9" ~= phoneChar else {
throw PhoneNumberFormattingError.wrongCharactersInPhoneNumber
}
retVal.append(phoneChar)
index += indexTemp
} else {
retVal.append(char)
}
}
if phoneNumber.endIndex > phoneNumber.index(phoneNumber.startIndex, offsetBy: index) {
throw PhoneNumberFormattingError.phoneNumberLongerThanPatternAllowes
}
return retVal
}
}
let phoneFormatter = DefaultTextFormatter(textPattern: "### (###) ###-##-##")
phoneFormatter.format("+123456789012") // +12 (345) 678-90-12
使用非常简单。这里有很多好的答案,但我采取了完全不同的方法,我想我会与大家分享,以防有帮助 首先,我将格式化步骤和组件分解为各自的职责 电话号码格式通常可分为本地、国内或国际格式类型,这些格式类型因字符串长度而异 我定义了类型:
/// Defines the three different types of formatting phone numbers use
///
/// - local: Numbers used locally.
/// - domestic: Numbers used locally including area codes.
/// - international: Numbers used internationally with country codes.
public enum PhoneFormatType {
case local
case domestic
case international
}
然后定义可用于格式化电话号码字符串的分隔符:
// Defines separators that are available for use in formatting
// phone number strings.
public enum PhoneFormatSeparator {
case hyphen
case plus
case space
case parenthesisLH
case parenthesisRH
case slash
case backslash
case pipe
case asterisk
public var value: String {
switch self {
case .hyphen: return "-"
case .plus: return "+"
case .space: return " "
case .parenthesisLH: return "("
case .parenthesisRH: return ")"
case .slash: return "/"
case .backslash: return "\\"
case .pipe: return "|"
case .asterisk: return "*"
}
}
}
接下来,我定义了格式规则,用于指定插入分隔符(如+、-)的索引(电话号码字符串)
// defines the separators that should be inserted in a phone number string
// and the indexes where they should be applied
public protocol PhoneNumberFormatRule {
// the index in a phone number where this separator should be applied
var index: Int { get set }
// the priority in which this rule should be applied. Sorted in inverse, 0 is highest priority, higher numbers are lower priority
var priority: Int { get set }
// the separator to use at this index
var separator: PhoneFormatSeparator { get set }
}
/// Default implementation of PhoneNumberFormatRule
open class PNFormatRule: PhoneNumberFormatRule {
public var index: Int
public var priority: Int
public var separator: PhoneFormatSeparator
public init(_ index: Int, separator: PhoneFormatSeparator, priority: Int = 0) {
self.index = index
self.separator = separator
self.priority = priority
}
}
定义了这些规则后,我创建了将规则与给定格式类型关联的规则集
/// Defines the rule sets associated with a given phone number type.
/// e.g. international/domestic/local
public protocol PhoneFormatRuleset {
/// The type of phone number formatting to which these rules apply
var type: PhoneFormatType { get set }
/// A collection of rules to apply for this phone number type.
var rules: [PhoneNumberFormatRule] { get set }
/// The maximum length a number using this format ruleset should be. (Inclusive)
var maxLength: Int { get set }
}
使用这种方式定义的所有内容,您可以快速设置规则集以适合您需要的任何格式
下面是一个规则集示例,该规则集为美国常用的连字符格式的电话号码字符串定义了3条规则:
// Formats phone numbers:
// .local: 123-4567
// .domestic: 123-456-7890
// .international: +1 234-567-8901
static func usHyphen() -> [PhoneFormatRuleset] {
return [
PNFormatRuleset(.local, rules: [
PNFormatRule(3, separator: .hyphen)
], maxLength: 7),
PNFormatRuleset(.domestic, rules: [
PNFormatRule(3, separator: .hyphen),
PNFormatRule(6, separator: .hyphen)
], maxLength: 10),
PNFormatRuleset(.international, rules: [
PNFormatRule(0, separator: .plus),
PNFormatRule(1, separator: .space),
PNFormatRule(4, separator: .hyphen),
PNFormatRule(7, separator: .hyphen)
], maxLength: 11)
]
}
格式化逻辑的繁重工作(并非如此)发生在这里:
// formats a string using the format rule provided at initialization
public func format(number: String) -> String {
// strip non numeric characters
let n = number.components(separatedBy: CharacterSet.decimalDigits.inverted).joined()
// bail if we have an empty string, or if no ruleset is defined to handle formatting
guard n.count > 0, let type = type(for: n.count), let ruleset = ruleset(for: type) else {
return n
}
// this is the string we'll return
var formatted = ""
// enumerate the numeric string
for (i,character) in n.enumerated() {
// bail if user entered more numbers than allowed for our formatting ruleset
guard i <= ruleset.maxLength else {
break
}
// if there is a separator defined to be inserted at this index then add it to the formatted string
if let separator = ruleset.separator(for: i) {
formatted+=separator
}
// now append the character
formatted+="\(character)"
}
return formatted
}
然后使用它:
import SwiftPhoneFormat
var formatter = PhoneFormatter(rulesets: PNFormatRuleset.usParethesis())
let formatted = formatter.format(number: numberString)
非常简单的解决方案:
extension String {
func applyPatternOnNumbers(pattern: String, replacementCharacter: Character) -> String {
var pureNumber = self.replacingOccurrences( of: "[^0-9]", with: "", options: .regularExpression)
for index in 0 ..< pattern.count {
guard index < pureNumber.count else { return pureNumber }
let stringIndex = String.Index(utf16Offset: index, in: pattern)
let patternCharacter = pattern[stringIndex]
guard patternCharacter != replacementCharacter else { continue }
pureNumber.insert(patternCharacter, at: stringIndex)
}
return pureNumber
}
}
Swift 4 创建此函数并调用文本字段事件编辑更改
private func formatPhone(_ number: String) -> String {
let cleanNumber = number.components(separatedBy: CharacterSet.decimalDigits.inverted).joined()
let format: [Character] = ["X", "X", "X", "-", "X", "X", "X", "-", "X", "X", "X", "X"]
var result = ""
var index = cleanNumber.startIndex
for ch in format {
if index == cleanNumber.endIndex {
break
}
if ch == "X" {
result.append(cleanNumber[index])
index = cleanNumber.index(after: index)
} else {
result.append(ch)
}
}
return result
}
此扩展将完全满足您的要求:
extension String {
func convertToInternationalFormat() -> String {
let isMoreThanTenDigit = self.count > 10
_ = self.startIndex
var newstr = ""
if isMoreThanTenDigit {
newstr = "\(self.dropFirst(self.count - 10))"
}
else if self.count == 10{
newstr = "\(self)"
}
else {
return "number has only \(self.count) digits"
}
if newstr.count == 10 {
let internationalString = "(\(newstr.dropLast(7))) \(newstr.dropLast(4).dropFirst(3)) \(newstr.dropFirst(6).dropLast(2)) \(newstr.dropFirst(8))"
newstr = internationalString
}
return newstr
}
}
INPUT :
var str1 = "9253248954"
var str2 = "+19253248954"
var str3 = "19253248954"
OUTPUT :
str1.convertToInternationalFormat() // "(925) 324 89 54"
str2.convertToInternationalFormat() // "(925) 324 89 54"
str3.convertToInternationalFormat() // "(925) 324 89 54"
Swift 5.1更新БааіПаааааПаааааа
extension String {
func applyPatternOnNumbers(pattern: String, replacmentCharacter: Character) -> String {
var pureNumber = self.replacingOccurrences( of: "[^0-9]", with: "", options: .regularExpression)
for index in 0 ..< pattern.count {
guard index < pureNumber.count else { return pureNumber }
let stringIndex = String.Index(utf16Offset: index, in: self)
let patternCharacter = pattern[stringIndex]
guard patternCharacter != replacmentCharacter else { continue }
pureNumber.insert(patternCharacter, at: stringIndex)
}
return pureNumber
}
}
如果你不想使用图书馆的话。 这里有一个链接到最佳示例,或者您可以使用下面的代码 在Swift 5.0中设置10位电话号码格式的简单代码段,不包括一个大型库,只需实现一个委托函数和一个格式化函数:
- UITextFieldDelegate函数
- 格式化功能:
func格式(电话号码:String,shouldRemoveLastDigit:Bool=false)->String{
guard!phoneNumber.isEmpty else{return”“}
guard let regex=try?NSRegularExpression(模式:“[\\s-\\(\\)]”,选项:。不区分大小写)else{return”“}
设r=NSString(字符串:phoneNumber)。范围(of:phoneNumber)
var number=regex.stringByReplacingMatches(in:phoneNumber,options:.init(rawValue:0),范围:r,withTemplate:)
如果number.count>10{
设tenthDigitIndex=number.index(number.startIndex,偏移量:10)
数字=字符串(数字[number.startIndex..Swift 5
String(
format: "(%@) %@-%@",
rawNumber.subString(from: 0, to: 2),
rawNumber.subString(from: 3, to: 5),
rawNumber.subString(from: 6, to: 9)
)
我不知道为什么,但这对我不起作用。我将textInputController.textInput设置为我的UITextField。我还在故事板的Identity inspector中设置其类TexInputField,并进行适当的转换。Field不是实时格式化的。这应该是正确的解决方案。提供了更大的灵活性,可以放置在自己的类中,并在整个过程中使用应用程序。我相信输入111222333会崩溃。虽然它不是一个有效的电话号码,但用户仍然可以输入它。感谢@sanch指出以“1”开头的10位数字的示例。这样的输入将使它通过“//检查支持的电话号码长度”下的保护。我没有考虑过这样的电话号码输入。我测试了Swift 4代码,谢天谢地,由于注释“//后缀,4个字符下的guard语句,它返回了一个零。“@sanch,我改进了代码以更好地处理以“1”开头的10个号码输入。现在guard在“//下检查支持的电话号码长度”明确拒绝这样的输入。我在示例和我自己的代码单元测试中添加了“111222333”。谢谢。恭喜!这是我见过的最好的解决方案!最好的模式解决方案如何将其用于阿拉伯数字?这绝对是我最喜欢的问题解决方案。谢谢!init(encodedOffset:)'已弃用:encodedOffset已弃用,因为最常见的用法是不正确的。电话号码极其复杂。您对其格式的任何假设都纯粹是本地的,并且肯定有大量的异常和边缘案例。请改用一个库,该库已将所有这些异常编码为国际通用。例如:Wil我在编辑中间的号码时效果不好。不幸的是,这将使用电话号码建议来阻止iOS功能。这是一个优雅的解决方案。当我想根据数字数对电话号码进行不同的格式设置时,我只是根据电话串数使用了不同的掩码。适用于Swift 4.2,只是为了在创建o时添加这一点wn掩码,如(XXX)XXX-XXXX
,它也会工作。此外,如果您需要返回普通字符串,只需创建一个类似于xxxxxxxxx
的普通掩码,它会将格式化的电话号码转换回普通字符串。若要允许此操作与电话号码建议一起工作,只需将上次返回=false更改为:返回字符串=“”
.iOS自动完成a
pod 'SwiftPhoneFormat', '1.0.0'
import SwiftPhoneFormat
var formatter = PhoneFormatter(rulesets: PNFormatRuleset.usParethesis())
let formatted = formatter.format(number: numberString)
extension String {
func applyPatternOnNumbers(pattern: String, replacementCharacter: Character) -> String {
var pureNumber = self.replacingOccurrences( of: "[^0-9]", with: "", options: .regularExpression)
for index in 0 ..< pattern.count {
guard index < pureNumber.count else { return pureNumber }
let stringIndex = String.Index(utf16Offset: index, in: pattern)
let patternCharacter = pattern[stringIndex]
guard patternCharacter != replacementCharacter else { continue }
pureNumber.insert(patternCharacter, at: stringIndex)
}
return pureNumber
}
}
guard let text = textField.text else { return }
textField.text = text.applyPatternOnNumbers(pattern: "+# (###) ###-####", replacmentCharacter: "#")
private func formatPhone(_ number: String) -> String {
let cleanNumber = number.components(separatedBy: CharacterSet.decimalDigits.inverted).joined()
let format: [Character] = ["X", "X", "X", "-", "X", "X", "X", "-", "X", "X", "X", "X"]
var result = ""
var index = cleanNumber.startIndex
for ch in format {
if index == cleanNumber.endIndex {
break
}
if ch == "X" {
result.append(cleanNumber[index])
index = cleanNumber.index(after: index)
} else {
result.append(ch)
}
}
return result
}
extension String {
func convertToInternationalFormat() -> String {
let isMoreThanTenDigit = self.count > 10
_ = self.startIndex
var newstr = ""
if isMoreThanTenDigit {
newstr = "\(self.dropFirst(self.count - 10))"
}
else if self.count == 10{
newstr = "\(self)"
}
else {
return "number has only \(self.count) digits"
}
if newstr.count == 10 {
let internationalString = "(\(newstr.dropLast(7))) \(newstr.dropLast(4).dropFirst(3)) \(newstr.dropFirst(6).dropLast(2)) \(newstr.dropFirst(8))"
newstr = internationalString
}
return newstr
}
}
INPUT :
var str1 = "9253248954"
var str2 = "+19253248954"
var str3 = "19253248954"
OUTPUT :
str1.convertToInternationalFormat() // "(925) 324 89 54"
str2.convertToInternationalFormat() // "(925) 324 89 54"
str3.convertToInternationalFormat() // "(925) 324 89 54"
extension String {
func applyPatternOnNumbers(pattern: String, replacmentCharacter: Character) -> String {
var pureNumber = self.replacingOccurrences( of: "[^0-9]", with: "", options: .regularExpression)
for index in 0 ..< pattern.count {
guard index < pureNumber.count else { return pureNumber }
let stringIndex = String.Index(utf16Offset: index, in: self)
let patternCharacter = pattern[stringIndex]
guard patternCharacter != replacmentCharacter else { continue }
pureNumber.insert(patternCharacter, at: stringIndex)
}
return pureNumber
}
}
let formattedText = text.applyPatternOnNumbers(pattern: "+# (###) ###-####", replacmentCharacter: "#")
func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {
var fullString = textField.text ?? ""
fullString.append(string)
if range.length == 1 {
textField.text = format(phoneNumber: fullString, shouldRemoveLastDigit: true)
} else {
textField.text = format(phoneNumber: fullString)
}
return false
}
func format(phoneNumber: String, shouldRemoveLastDigit: Bool = false) -> String {
guard !phoneNumber.isEmpty else { return "" }
guard let regex = try? NSRegularExpression(pattern: "[\\s-\\(\\)]", options: .caseInsensitive) else { return "" }
let r = NSString(string: phoneNumber).range(of: phoneNumber)
var number = regex.stringByReplacingMatches(in: phoneNumber, options: .init(rawValue: 0), range: r, withTemplate: "")
if number.count > 10 {
let tenthDigitIndex = number.index(number.startIndex, offsetBy: 10)
number = String(number[number.startIndex..<tenthDigitIndex])
}
if shouldRemoveLastDigit {
let end = number.index(number.startIndex, offsetBy: number.count-1)
number = String(number[number.startIndex..<end])
}
if number.count < 7 {
let end = number.index(number.startIndex, offsetBy: number.count)
let range = number.startIndex..<end
number = number.replacingOccurrences(of: "(\\d{3})(\\d+)", with: "($1) $2", options: .regularExpression, range: range)
} else {
let end = number.index(number.startIndex, offsetBy: number.count)
let range = number.startIndex..<end
number = number.replacingOccurrences(of: "(\\d{3})(\\d{3})(\\d+)", with: "($1) $2-$3", options: .regularExpression, range: range)
}
return number
}
String(
format: "(%@) %@-%@",
rawNumber.subString(from: 0, to: 2),
rawNumber.subString(from: 3, to: 5),
rawNumber.subString(from: 6, to: 9)
)