Ios Swift中UIImagePickerController之后的UIImage为零

当iImage的值被打印出来时，它会显示：“大小{30244032}方向3比例1.000000”，但随后我得到了错误：“致命错误：在下一行展开可选值时意外发现了nil”。我刚刚得到的图像怎么可能是零

func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [String : Any]) {
        let iImage = info[UIImagePickerControllerOriginalImage] as! UIImage
        print(iImage)
        createEvent(iImage)//where it is saved to cloudkit with location and title
        EventPageViewController().eventPic.image = iImage
        self.dismiss(animated: true, completion: nil);
    }

func mapView(_ mapView: MKMapView, annotationView view: MKAnnotationView, calloutAccessoryControlTapped control: UIControl) {

        let eventPageViewController:EventPageViewController = storyboard?.instantiateViewController(withIdentifier: "EventPage") as! EventPageViewController
        self.present(eventPageViewController, animated: true, completion: nil)
    }

func loadEvent(_ completion: @escaping (_ error:NSError?, _ records:[CKRecord]?) -> Void)
    {
        let date = NSDate(timeInterval: -60.0 * 180, since: NSDate() as Date)
        let predicate = NSPredicate(format: "creationDate > %@", date)
        let query = CKQuery(recordType: "Event", predicate: predicate)
        CKContainer.default().publicCloudDatabase.perform(query, inZoneWith: nil){
            (records, error) in
            if error != nil {
                print("error fetching events: \(error)")
                completion(error as NSError?, nil)
            } else {
                print("found events")
                completion(nil, records)
                guard let records = records else {
                    return
                }
                for record in records
                {
                    self.drawEvents(record["LocationF"] as! CLLocation, title1: record["StringF"] as! String)

                    if let asset = record["Picture"] as? CKAsset,
                        let data = NSData(contentsOf: asset.fileURL),
                        let image1 = UIImage(data: data as Data)
                    {
                        //EventPageViewController().eventPic.image = image1
                    }
                }
            }
        }
    }

func drawEvents(_ loc: CLLocation, title1: String)
    {
        mapView.delegate = self
        let center = CLLocationCoordinate2D(latitude: loc.coordinate.latitude, longitude: loc.coordinate.longitude)
        let lat: CLLocationDegrees = center.latitude
        let long: CLLocationDegrees = center.longitude
        self.pointAnnotation1 = MKPointAnnotation()
        self.pointAnnotation1.title = title1
        self.pointAnnotation1.subtitle = "Event"
        self.pointAnnotation1.coordinate = CLLocationCoordinate2D(latitude: lat, longitude: long)

        self.pinAnnotationView = MKPinAnnotationView(annotation: self.pointAnnotation1, reuseIdentifier: nil)
        self.mapView.addAnnotation(self.pinAnnotationView.annotation!)
    }

---

这是因为您正在此处创建ViewController的新实例

EventPageViewController（）

。如果此委托方法位于

EventPageViewController

中，您可以调用

self.eventPic.image=iImage

，它看起来像

eventPic

是一个

UIImageView

作为

IBOutlet

。因此，

EventPageViewController

的实例尚未完成加载其视图和连接插座

您应该在

EventPageViewController

中具有UIImage属性

class EventPageViewController {
  var eventImage: UIImage?
  @IBOutlet var eventPic:UIImageView! //you should have better name like eventImageView

  func viewDidLoad() {
    super.viewDidLoad()
    eventPic?.image = eventImage
    ///rest goes here
  }
}

因此，您可以通过选择器代理访问以下内容：

let eventPageViewController = EventPageViewController()
eventPageViewController.eventImage = iImage

---

希望这有帮助。

您确定错误来自iImage吗？您确定eventPic不是nil吗？它不是当前的ViewController。它是注释上的“信息”按钮打开时显示的ViewControllerclicked@Steve那么这个委托方法是如何被激发的呢？

EventPageViewController

的总体布局是什么？当用户单击按钮时，FirstViewController会打开相机。上面没有包含另一行代码，它调用一个执行pin的方法。单击批注上的“信息”按钮时，它会打开EventPageViewController（我希望图片显示在这里）。所有这些都会保存到cloudkit，以便其他用户可以下载PIN。我需要每个pin都有自己的EventPageViewController实例，以便每个pin都有自己不同的图片@普拉蒂克Patel@Steve因此，您需要将图像传回

FirstViewController

，然后使用segue或任何必须打开

EventPageViewController

的机制将其传递。