Ios 如何计算textView中的单词和字符总数？

我使用下面的代码来计算单词总数

-(NSInteger) getTotalWords{
    NSLog(@"Total Word %lu",[[_editor.attributedText string]length]);
    if ([[_editor.attributedText string]length]==0) {
        return 0;
    }

    NSString *str  =[_editor textInRange:[_editor textRangeWithRange:[self visibleRangeOfTextView:_editor]]];

    NSInteger sepWord = [[[str stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]]componentsSeparatedByString:@" "] count];
    sepWord += [[[str stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]]componentsSeparatedByString:@"\n"] count];
    sepWord=sepWord-2;
    return sepWord;
}

这是整个字符的代码

 -(NSInteger) getTotalChars{

        NSString *str  =[_editor textInRange:[_editor textRangeWithRange:[self visibleRangeOfTextView:_editor]]];

        NSLog(@"%@",str);

        NSInteger charCount= [[str stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]]length];

        return charCount=charCount-1;

    }

但是当我输入超过两行时，我并没有得到完美的计数。它以新行作为单词

请帮帮我

对于字数计算

NSString *str = @"this is a sample string....";
NSScanner *scanner = [NSScanner scannerWithString:str];
NSCharacterSet *whiteSpace = [NSCharacterSet whitespaceAndNewlineCharacterSet];
NSCharacterSet *nonWhitespace = [whiteSpace invertedSet];
int wordcount = 0;

while(![scanner isAtEnd])
{
    [scanner scanUpToCharactersFromSet:nonWhitespace intoString:nil];
    [scanner scanUpToCharactersFromSet:whitespace intoString:nil];
    wordcount++;
}

你可以简单地做：

NSString *text = @"Lorem ...";

NSArray *words = [text componentsSeparatedByCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]];
NSInteger wordCount = [words count];

NSInteger characterCount = 0;
for (NSString *word in words) {
   characterCount += [word length];
}

---

如果你真的想计算单词数（即“foo，bar”应计算为2个单词，并加上 6个字符）然后 您可以使用

EnumerateStringsRange

的

NSStringEnumerationByWords

选项， 自动处理所有空格和分词符：

NSString *string = @"Hello world.\nfoo,bar.";

__block int wordCount = 0;
__block int charCount = 0;
[string enumerateSubstringsInRange:NSMakeRange(0, [string length])
               options:NSStringEnumerationByWords
            usingBlock:^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop) {
                wordCount += 1;
                charCount += substringRange.length;
            }];
NSLog(@"%d", wordCount); // Output: 4
NSLog(@"%d", charCount); // Output: 16

要获得字数，请使用-

NSArray *array = [txtView.text componentsSeparatedByString:@" "];
int wordCount = [array count];

for(int i = 0; i < [array count]; i++){
    characterCount = characterCount + [[array objectAtIndex:i] length];
}

NSLog(@"characterCount : %i",characterCount);
NSLog(@"wordCount : %i",wordCount);

NSArray*array=[txtView.text组件由字符串分隔：@”“；
int wordCount=[array count]；
对于（int i=0；i<[数组计数]；i++）{
characterCount=characterCount+[[array objectAtIndex:i]length]；
}
NSLog（@“characterCount:%i”，characterCount）；
NSLog（@“字数：%i”，字数）；

str=textView.text；
NSArray*wordArray=[str componentsSeparatedByString:@']；
int wordCount=[wordArray count]；
int charCount=0；
对于（int i=0；i<[wordArray count]；i++）
{
charCount=charCount+[[wordArray objectAtIndex:0]长度]；
}

像这样尝试一次

 NSString *string = @"123 1 2\n234\nponies";
    NSArray *chunks = [string componentsSeparatedByCharactersInSet:[NSCharacterSet characterSetWithCharactersInString:@" \n"]];
    NSLog(@"%d",[chunks count]);

---

myString=[mystringstringbyreplacingoccurrencesofstring:@“\n”with string:@”“这是一个完美的答案。。。有很多副本。谢谢。。这对我来说很管用，不过这也算是个词。
    str = textView.text;

    NSArray *wordArray = [str componentsSeparatedByString:@" "];

    int wordCount = [wordArray count];
    int charCount=0;

    for (int i=0 ; i < [wordArray count]; i++)
    {
        charCount = charCount + [[wordArray objectAtIndex:0] length];
    }

 NSString *string = @"123 1 2\n234\nponies";
    NSArray *chunks = [string componentsSeparatedByCharactersInSet:[NSCharacterSet characterSetWithCharactersInString:@" \n"]];
    NSLog(@"%d",[chunks count]);