Ios 如何使用AVFundation以00:00:00格式打印音频时间
在我的应用程序中,我使用Ios 如何使用AVFundation以00:00:00格式打印音频时间,ios,iphone,swift,time,avfoundation,Ios,Iphone,Swift,Time,Avfoundation,在我的应用程序中,我使用AVFoundation调用函数showCurrentAudioProgress()使用NSTimer.scheduledTimerWithTimeInterval(0.1,目标:self,选择器:“showCurrentAudioProgress”,userInfo:nil,repeats:true)在viewDidLoad中。我想返回这种时间格式00:00:00,但我有一个大问题。整个函数如下所示: var musicPlayer = AVAudioPLayer()
AVFoundation
调用函数showCurrentAudioProgress()
使用NSTimer.scheduledTimerWithTimeInterval(0.1,目标:self,选择器:“showCurrentAudioProgress”,userInfo:nil,repeats:true)
在viewDidLoad
中。我想返回这种时间格式00:00:00,但我有一个大问题。整个函数如下所示:
var musicPlayer = AVAudioPLayer()
func showCurrentAudioProgress() {
self.totalTimeOfAudio = self.musicPlayer.duration
self.currentTimeOfAudio = self.musicPlayer.currentTime
let progressToShow = Float(self.currentTimeOfAudio) / Float(self.totalTimeOfAudio)
self.audioProgress.progress = progressToShow
var totalTime = self.musicPlayer.duration
totalTime -= self.currentTimeOfAudio
self.currentTimeTimer.text = "\(currentTimeOfAudio)"
self.AudioDurationTime.text = "\(totalTime)"
}
如何将使用
AVAudioPlayer
获得的时间转换为00:00:00?最简单的解决方案是分别获得小时
、分钟
和秒
,并合并为一个字符串。为了提高性能,您可以将其放入字符串类别或扩展名中
let totalTimeOfAudio = 26343 // number of seconds just for an example
let secondsInMinute = 60
let minuteInHour = 60
let secondsInHour = secondsInMinute * minuteInHour
let hours = Float(totalTimeOfAudio / (secondsInHour))
let minutes = Float(totalTimeOfAudio / minuteInHour % minuteInHour)
let seconds = Float(totalTimeOfAudio % secondsInMinute)
let string: NSString = NSString(format: "%02.f:%02.f:%02.f", hours, minutes, seconds)
最简单的解决方案是分别获得
小时
、分钟
和秒
,并合并成一个字符串。为了提高性能,您可以将其放入字符串类别或扩展名中
let totalTimeOfAudio = 26343 // number of seconds just for an example
let secondsInMinute = 60
let minuteInHour = 60
let secondsInHour = secondsInMinute * minuteInHour
let hours = Float(totalTimeOfAudio / (secondsInHour))
let minutes = Float(totalTimeOfAudio / minuteInHour % minuteInHour)
let seconds = Float(totalTimeOfAudio % secondsInMinute)
let string: NSString = NSString(format: "%02.f:%02.f:%02.f", hours, minutes, seconds)
您可以使用NSDateComponentsFormatter.Positional样式和zeroFormattingBehavior.Pad按如下方式显示时间间隔:
extension NSTimeInterval {
struct DateComponents {
static let formatterPositional: NSDateComponentsFormatter = {
let formatter = NSDateComponentsFormatter()
formatter.allowedUnits = [.Hour,.Minute,.Second]
formatter.unitsStyle = .Positional
formatter.zeroFormattingBehavior = .Pad
return formatter
}()
}
var positionalTime: String {
return DateComponents.formatterPositional.stringFromTimeInterval(self) ?? ""
}
}
print(120.positionalTime) // 0:02:00
如果你想使用字符串格式初始化器,你可以看看这个 您可以使用NSDateComponentsFormatter.Positional style和zeroFormattingBehavior.Pad显示时间间隔,如下所示:
extension NSTimeInterval {
struct DateComponents {
static let formatterPositional: NSDateComponentsFormatter = {
let formatter = NSDateComponentsFormatter()
formatter.allowedUnits = [.Hour,.Minute,.Second]
formatter.unitsStyle = .Positional
formatter.zeroFormattingBehavior = .Pad
return formatter
}()
}
var positionalTime: String {
return DateComponents.formatterPositional.stringFromTimeInterval(self) ?? ""
}
}
print(120.positionalTime) // 0:02:00
如果你想使用字符串格式初始化器,你可以看看这个
minutes中出现错误是因为下一分钟它仍然是相同的值minutes中出现错误是因为下一分钟它仍然是相同的值