Ios Can'；不要在Alamofire中使用公共枚举

我有以下代码：

import Alamofire

extension Alamofire.Request {
public func responseObject<T: ResponseJSONObjectSerializable>(completionHandler:(NSURLRequest?,NSHTTPURLResponse?, Result<T>) -> Void) -> Self {
let responseSerializer = GenericResponseSerializer<T> { request, response, data in

guard let responseData = data else {

    let failureReason = "Object could not be serialized because input data was nil."
    let error = Error.errorWithCode( .DataserializableFailed, failureReason: failureReason)
    //Error: Type of expression is ambiguous without more context

    return .Failure(data, error)

}}}

如果我把

code

放在

.dataserializablefiled

前面，它会说：使用未解析标识符“code”

---

怎么了

显然你的大写字母/拼写不同。它应该是

.DataSerializationFailed

，而不是

.dataserializablefiled

---

或者您可以参考

Error.code.DataSerializationFailed

@Rob问题已解决，谢谢！但是我想知道为什么在我把

.code

放在

.DataSerializationFailed

之前时仍然有bug。你可以引用完全限定值

Error.code.DataSerializationFailed

，或者如果可以推断类型

Error.code

，你可以使用“点语法”，只引用枚举值，例如。，

.DataSerializationFailed

。虽然如果编译器能够推断出您所说的

.code.DataSerializationFailed

，这可能是一种优雅的方式，但它没有这样做并不奇怪。

public struct Error {
public enum Code: Int {
    case InputStreamReadFailed           = -6000
    case OutputStreamWriteFailed         = -6001
    case ContentTypeValidationFailed     = -6002
    case StatusCodeValidationFailed      = -6003
    case DataSerializationFailed         = -6004
    case StringSerializationFailed       = -6005
    case JSONSerializationFailed         = -6006
    case PropertyListSerializationFailed = -6007
}
}