在iOS中通过编程方式将图像设置为imageView by ID

我正在开发一个iOS应用程序，我有一个for循环来创建图像。 当一个图像收到点击，我想改变图像的背景，只为该图像。我该怎么做

这是我的代码：

for (int i =0; i<dim; i++) {

likeImageImageview = [[UIImageView alloc] initWithFrame:CGRectMake(paddWidth*20,7.5,39.6,39.6)];

    img0 = [UIImage imageNamed:@"like"];
    [likeImageImageview setImage:img0];

    UITapGestureRecognizer *singleTap = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(tapImagesLike)];
    singleTap.numberOfTapsRequired = 1;                                                                                                 
    likeImageImageview.userInteractionEnabled = YES;                                                                                            //l'utente può cliccare
    [likeImageImageview setMultipleTouchEnabled:NO];                                                                                            //non è consentito il multitouch
    [likeImageImageview addGestureRecognizer:singleTap];

[row_like addSubview:likeImageImageview];

}

使用此代码，只有最后一个

imageview

更改其背景。如何像

ID

一样使用“I”

for loop

UIImageView *imageView = …

imageView.tag = i;

所以你需要得到被点击的视图

- (void)tapImagesLike:(UITapGestureRecognizer*)recognizer
{
    UIImageView *imageView = (UIImageView*)recognizer.view;
    int i = imageView.tag;
    // Then you can do the change you need to do here
}

---

这是在手势识别器点击时应该调用的方法。

它只显示最后一个图像，因为您正在for循环中创建一个新实例

试试这个

NSMutableArray *tempImageArray=[[NSMutableArray alloc]init];
for (int i =0; i<10; i++) {

   UIImageView *likeImageImageview = [[UIImageView alloc] initWithFrame:CGRectMake(20,7.5,39.6,39.6)];

   UIImage *img0 = [UIImage imageNamed:@"like"];
    [likeImageImageview setImage:img0];

    UITapGestureRecognizer *singleTap = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(tapImagesLike:)];
    singleTap.numberOfTapsRequired = 1;
    [self.view addGestureRecognizer:singleTap];
    [row_like addSubview:likeImageImageview];
    [tempImageArray addObject:likeImageImageview];
}
self.imageArray=tempImageArray;
[tempImageArray release];

---

这也要求您在创建手势时将

@selector（tapImagesLike）

更改为

@selector（tapImagesLike:）

。好的，现在它可以工作了，但我收到以下警告：不兼容的指针类型从“UIView”分配给“UIImageView”。那么，如何将参数“i”传递给该方法？因为我必须使用它。一种解决方案是使用图像视图的标记值并将其设置为i的值。第二种解决方案是使用objective c运行时并将该值与图像视图关联，第一种是最简单的方法。

NSMutableArray *tempImageArray=[[NSMutableArray alloc]init];
for (int i =0; i<10; i++) {

   UIImageView *likeImageImageview = [[UIImageView alloc] initWithFrame:CGRectMake(20,7.5,39.6,39.6)];

   UIImage *img0 = [UIImage imageNamed:@"like"];
    [likeImageImageview setImage:img0];

    UITapGestureRecognizer *singleTap = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(tapImagesLike:)];
    singleTap.numberOfTapsRequired = 1;
    [self.view addGestureRecognizer:singleTap];
    [row_like addSubview:likeImageImageview];
    [tempImageArray addObject:likeImageImageview];
}
self.imageArray=tempImageArray;
[tempImageArray release];

- (void)tapImagesLike:(UITapGestureRecognizer*)recognizer{
     UIImageView *imageView = (UIImageView *)[self.imageArray objectAtIndex:0];
     imageView.image=[UIImage imageNamed:@"0.png"];  
}