Ios 对于'；没有可见的@界面；联系方式'；声明选择器'；initWithName:缩略图：电子邮件：'；

我的代码怎么了

我已经在谷歌上查看了更多关于错误的信息，但找不到任何解决问题的方法。谁能帮我解决这个问题

错误发生在以下行中：

self=[self initWithName:dic[@“name”]缩略图：dic[@“缩略图”] 电子邮件：dic[@“电子邮件”]

self=[self initWithName:@“未定义” 缩略图：@“未定义”电子邮件：@“未定义”] Contact.h

//
//  Contact.h
//  Teste
//
//  Created by Samuel Neiva on 13/04/16.
//  Copyright (c) 2016 Samuel Neiva. All rights reserved.
//

#import <Foundation/Foundation.h>

@interface Contact : NSObject

@property (strong, nonatomic) NSString *name;
@property (strong, nonatomic) NSString *thumbnail;
@property (strong, nonatomic) NSString *email;

- (id)initWithName:(NSString *)aName
         thumbnail:(NSString *)aThumbnail
             photo:(NSString *)aEmail;

- (id)initWithDictionary:(NSDictionary *)dic;

@end

---

Contact

没有声明该方法，正如警告所说。它声明

initWithName:thumbnail:photo

这一定是复制粘贴错误：

photo:（NSString*）aEmail

->

email:（NSString*）aEmail

//
//  Contact.m
//  Teste
//
//  Created by Samuel Neiva on 13/04/16.
//  Copyright (c) 2016 Samuel Neiva. All rights reserved.
//

#import "Contact.h"

@implementation Contact

- (id)initWithDictionary:(NSDictionary *)dic {
    self = [self initWithName:dic[@"name"] thumbnail:dic[@"thumbnail"] email:dic[@"email"]];
    return self;
}

- (id)init {
    self = [self initWithName:@"Undifined" thumbnail:@"Undifined" email:@"Undifined"];
    return self;
}

//The designated initializer
- (id)initWithName:(NSString *)aName
         thumbnail:(NSString *)aThumbnail
             photo:(NSString *)aEmail {

    self = [super init];

    if (self) {
        self.name = aName;
        self.thumbnail = aThumbnail;
        self.email = aEmail;
    }

    return self;
}

- (NSString *)description {
    return [NSString stringWithFormat:@"%@ : %@", self.name, self.description];
}


@end