如何在ios中请求包含空格和圆点的url？

我试图请求下面的URL，但我收到一个错误，说“数据参数为零”。我发现“卖方名称”有空格，“金额”有点（.）。我认为这就是URL导致的问题。那么，有没有什么方法可以在不丢失信息的情况下发送有空格和圆点的URL呢

NSURL *url1 = [[NSURL alloc]initWithString:[NSString stringWithFormat:@"192.168.1.85/localex_postsale.html?contactid=%@&exchangeid=%@&token=%@&buyerid=%@&seller_name=%@&desc=%@&amount=%@&sellerid=%@",contactid,exchangeid,token,buyervalue,sellers,_Description,_Amount,contactid]];
NSError *errors1;
NSData *data1 = [NSData dataWithContentsOfURL:url1];
NSDictionary *json1 = (NSDictionary *)[NSJSONSerialization JSONObjectWithData:data1 options:kNilOptions error:&errors1];

---

查看

NSString

中的

-stringbyaddingpercentescapesusingencode:

方法，例如：

---

参考：Apple。

之所以发生这种情况，是因为URL不应包含空格。如果有空格，则应将其编码为

%20

。我们可以使用

NSUTF8StringEncoding

对

NSString

中的空格和特殊字符进行编码，如下所示

NSString *string = [[NSString stringWithFormat:@"192.168.1.85/localex_postsale.html?contactid=%@&exchangeid=%@&token=%@&buyerid=%@&seller_name=%@&desc=%@&amount=%@&sellerid=%@",contactid,exchangeid,token,buyervalue,sellers,_Description,_Amount,contactid]stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSURL *url1 = [[NSURL alloc]initWithString:string];
NSError *errors1;
NSData *data1 = [NSData dataWithContentsOfURL:url1];
NSDictionary *json1 = (NSDictionary *)[NSJSONSerialization JSONObjectWithData:data1 options:kNilOptions error:&errors1]; 

NSString *string = [[NSString stringWithFormat:@"192.168.1.85/localex_postsale.html?contactid=%@&exchangeid=%@&token=%@&buyerid=%@&seller_name=%@&desc=%@&amount=%@&sellerid=%@",contactid,exchangeid,token,buyervalue,sellers,_Description,_Amount,contactid]stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSURL *url1 = [[NSURL alloc]initWithString:string];
NSError *errors1;
NSData *data1 = [NSData dataWithContentsOfURL:url1];
NSDictionary *json1 = (NSDictionary *)[NSJSONSerialization JSONObjectWithData:data1 options:kNilOptions error:&errors1];