Ios admob间质ad从未准备就绪

我有这个游戏，我在gameviewcontroller中创建了3个函数，它们在这里

    func getInterstitialAd(){
    interstitial = GADInterstitial(adUnitID: "ca-app-pub-1782852253088296/5018877964")
    let requestInterstitial = GADRequest()
    interstitial.load(requestInterstitial)
}



func showAd() {

    if (interstitial.isReady == true){
        interstitial.present(fromRootViewController: GameViewController())
    }else{
        print("ad wasn't ready")
        interstitial = createAd()
    }



}

func createAd() -> GADInterstitial{
    let interstital = GADInterstitial(adUnitID: "ca-app-pub-1782852253088296/5018877964")
    interstitial.load(GADRequest())
    return interstital
}

在我的一个名为StartMenu的场景中，我调用了这些函数

   var viewController: GameViewController!

然后我调用函数

       viewController.getInterstitialAd()
        viewController.showAd()

但它总是返回ad not ready，对于INTERTINCAL，返回false。isReady， 但也总是调用getInterstitual函数

---

有人能帮忙吗请创建一个新的swift文件ADMOBDERegate:-

import UIKit
import GoogleMobileAds

class AdMobDelegate: NSObject, GADInterstitialDelegate {

    var interstitialView: GADInterstitial!

    func createAd() -> GADInterstitial {
        interstitialView = GADInterstitial(adUnitID: "Your Key")
        interstitialView.delegate = self
        let request = GADRequest()
        interstitialView.loadRequest(request)
        return interstitialView
    }

    func showAd() {
        if interstitialView != nil {
            if (interstitialView.isReady == true){
                interstitialView.present(fromRootViewController:currentVc)
            } else {
                print("ad wasn't ready")
                interstitialView = createAd()
            }
        } else {
            print("ad wasn't ready")
            interstitialView = createAd()
        }
    }

    func interstitialDidReceiveAd(ad: GADInterstitial!) {
        print("Ad Received")
        if ad.isReady {
            interstitialView.present(fromRootViewController: currentVc)
        }
   }

    func interstitialDidDismissScreen(ad: GADInterstitial!) {
        print("Did Dismiss Screen")
    }

    func interstitialWillDismissScreen(ad: GADInterstitial!) {
        print("Will Dismiss Screen")
    }

    func interstitialWillPresentScreen(ad: GADInterstitial!) {
        print("Will present screen")
    }

    func interstitialWillLeaveApplication(ad: GADInterstitial!) {
        print("Will leave application")
    }

    func interstitialDidFailToPresentScreen(ad: GADInterstitial!) {
        print("Failed to present screen")
    }

    func interstitial(ad: GADInterstitial!, didFailToReceiveAdWithError error: GADRequestError!) {
        print("\(ad) did fail to receive ad with error \(error)")
    }
}

现在，您可以在其他文件中使用此委托类的对象，如下所示：-

//Define admobdelegate as global variable
var admobDelegate = AdMobDelegate()

//Declare a global variable currentVc to hold reference to current view controller
var currentVc: UIViewController!

class abc1: UIViewController {

    override func viewdidload() {
        super.viewdidload()
        currentVc = self
        admobDelegate.showAd()
    }

    override func viewDidAppear() {
        super.viewDidAppear()
        currentVc = self
    }
}

class abc2: UIViewController {

    override func viewdidload() {
        super.viewdidload()
        currentVc = self
        admobDelegate.showAd()
    }

    override func viewDidAppear() {
        super.viewDidAppear()
        currentVc = self
    }
}

---

代码在Swift 2.2中。如果出现语法错误，请用swift 3编写您的等效代码。

@DanielStorm我确定没有，但我真的不知道如何解决此问题，请帮助。非常感谢您，终于开始工作了！！！我已经绞尽脑汁想了好几天了。还有一个问题，如果我想从另一个函数（如GameSecene）调用，我能做的最好的方法是什么？只需在该函数中调用showAd（）。在我的游戏场景中，我创建了一个对象变量viewController:GameViewController！然后像viewController.showAd（）那样调用它，但是游戏崩溃GameSecene是同一个类中的函数还是不同的类中的函数？