Ios didFinishPickingMediaWithInfo未调用

我有一个

UITableViewCell

按钮来拍摄图像并将其放回单元格中。当我调用

UIImagePickerController

并拍摄图像时，它不会调用以下委托：

func imagePickerController(picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [NSObject : AnyObject], sender:AnyObject)

这是我的

UITableViewController

中的

takePhotoFunction

：

@IBAction func takePhoto(sender: AnyObject) {
let imagePickerController = UIImagePickerController()
imagePickerController.delegate = self
imagePickerController.allowsEditing = true

let actionSheet = UIAlertController(title: "Choose image souruce", message: nil, preferredStyle: UIAlertControllerStyle.ActionSheet)

actionSheet.addAction(UIAlertAction(title: "Take Image", style: UIAlertActionStyle.Default, handler: { (alert:UIAlertAction!) -> Void in
    imagePickerController.sourceType = UIImagePickerControllerSourceType.Camera
    self.presentViewController(imagePickerController, animated: true, completion: nil)
}))

actionSheet.addAction(UIAlertAction(title: "Photo Library", style: UIAlertActionStyle.Default, handler: { (alert:UIAlertAction!) -> Void in
    imagePickerController.sourceType = UIImagePickerControllerSourceType.PhotoLibrary
    self.presentViewController(imagePickerController, animated: true, completion: nil)
}))
actionSheet.addAction(UIAlertAction(title: "Cancel", style: UIAlertActionStyle.Cancel, handler: nil))
self.presentViewController(actionSheet, animated: true, completion: nil)}

---

您必须以这种方式使用该方法，因为您没有声明任何委托方法：

func imagePickerController(picker: UIImagePickerController!, didFinishPickingMediaWithInfo info:[NSObject : AnyObject]) {
        println("Calling")       
}

---

Apple文档参考：

委托方法现在称为

func imagePickerController（picker:UIImagePickerController，didFinishPickingMediaWithInfo:[String:AnyObject]）

---

我看到您的

imagePickerController。委托

设置正确，因此我假设您在Swift 3中将

didFinishPickingMediaWithInfo

代码意外放置在ViewController类之外，此委托方法现在被称为：

func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [String : Any])

区别在于：

选择器前面有一条下划线

末尾的信息类型从[String:AnyObject]更改为[String:Any]

---

我也有同样的问题，当我做出这些改变时，它起了作用。

1。别忘了添加

UIImagePickerControllerDelegate、UINavigationControllerDelegate

2.在您的

viewDidLoad（）

add

picker.delegate=self

3.添加代理方法

public func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [String : Any]) {
        let chosenImage = info[UIImagePickerControllerOriginalImage] as! UIImage 
        userImageView.contentMode = .scaleAspectFit
        userImageView.image = chosenImage
        dismiss(animated:true, completion: nil)
    }

public func imagePickerControllerDidCancel(_ picker: UIImagePickerController) {self.dismiss(animated: true, completion: nil)
}

---

希望有帮助：）

在Swift 4.2中使用以下方法：

public func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [UIImagePickerController.InfoKey : Any]){
}

---

对于SWIFT 4.2

当程序没有调用委托方法时，我也遇到了类似的问题

imagePicker.delegate=self

在viewDidLoad（）方法中应该是而不是，而是在打开gallery的方法中。像这样：

func openGallery()
    {
        let imagePicker = UIImagePickerController()
        imagePicker.delegate = self

        imagePicker.sourceType = .photoLibrary

        self.present(imagePicker, animated: true, completion: nil)
   }

对于swift 4.2

func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [UIImagePickerController.InfoKey : Any]) {
   if let chosenImage = info[.originalImage] as? UIImage{
        //use image
    }
}

---

对于Swift 4.2

此方法已重命名，现在应按如下方式调用。我遇到了这个委托方法没有调用的问题，但在这之后，我的问题解决了

func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [UIImagePickerController.InfoKey : Any]) {

}

对于Swift 5，我们略有更新

下面是我创建的一个单屏幕示例，用iOS 12.2来测试这一点

import UIKit


class ViewController: UIViewController, UIImagePickerControllerDelegate, UINavigationControllerDelegate {

    @IBOutlet weak var imageView: UIImageView!

    override func viewDidLoad() {
        super.viewDidLoad()
    }

    //MARK: Open Photos Galley Button Action method
    @IBAction func openPhotosGallery(_ sender: Any) {

        if UIImagePickerController.isSourceTypeAvailable(.photoLibrary){
            let myPickerController = UIImagePickerController()
            myPickerController.delegate = self;
            myPickerController.sourceType = .photoLibrary
            self.present(myPickerController, animated: true, completion: nil)
        }
    }

    //MARK: ImagePicker Controller Delegate methods
    func imagePickerControllerDidCancel(_ picker: UIImagePickerController) {
        self.dismiss(animated: true, completion: nil)
    }

    func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [UIImagePickerController.InfoKey : Any]) {
        let chosenImage = info[UIImagePickerController.InfoKey.originalImage] as! UIImage
        imageView.image = chosenImage
        dismiss(animated:true, completion: nil)
    }
}

---

如果UIImagePickerController（）对象的allowsEditing属性设置为true，则应在委托方法中获取图像，如下所示：

如果

allowsdediting==true

func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [UIImagePickerController.InfoKey : Any]) {

        if let pickedImage = info[.editedImage] as? UIImage {

              //do something with image

        }

           dismiss(animated: true, completion: nil)

    }

如果

allowsdediting==false

func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [UIImagePickerController.InfoKey : Any]) {

            if let pickedImage = info[.originalImage] as? UIImage {

                  //do something with image

            }

               dismiss(animated: true, completion: nil)

        }

---

也许有时是电弧引起的？ 我在下面为iOS14之前的版本声明了适配器变量（存在

UIImagePickerController

，或在控制器中为iOS14+声明了

PHPickerViewController

）。 它对我有用

var adapter: PHPickerAdapter?

@objc func openGallery(recognizer: UITapGestureRecognizer) {
    adapter = PHPickerAdapter()
    adapter?.delegate = self
    adapter?.showPhotoPicker(.photoLibrary, from: self)
}

---

你好，谢谢你的回答。我已经实现了委托方法，但在imagpepickercontroller完成后，不会调用此方法。您是否使用了我提到的委托方法，因为您的委托方法不正确，并且没有您声明的委托方法。

UIImage？无法转换为“UIImage”

从“Slice”强制转换而来（也称为“切片”）到不相关类型的“UIImage”总是失败