Ios 如何在Xcode控制台中漂亮地打印NSError对象?
我在Xcode控制台中打印了一个NSError对象(通过Ios 如何在Xcode控制台中漂亮地打印NSError对象?,ios,xcode,cocoa,macos,debugging,Ios,Xcode,Cocoa,Macos,Debugging,我在Xcode控制台中打印了一个NSError对象(通过NSLog(@“%@”,error);),对于某种类型的错误,我得到的结果如下: Domain=NSCocoaErrorDomain Code=133020 "The operation couldn’t be completed. (Cocoa error 133020.)" UserInfo=0xe939170 {conflictList=( "NSMergeConflict (0xe93cad0) for NSManagedO
NSLog(@“%@”,error);
),对于某种类型的错误,我得到的结果如下:
Domain=NSCocoaErrorDomain Code=133020 "The operation couldn’t be completed. (Cocoa error 133020.)" UserInfo=0xe939170 {conflictList=(
"NSMergeConflict (0xe93cad0) for NSManagedObject (0x5dba970) with objectID '0x5dc26f0 <x-coredata://775D53AE-58A4-4B18-BA52-D46781A183AE/SomeObject/p1>' with oldVersion = 2 and newVersion = 3 and old object snapshot = {\n creationDate = \"2011-08-24 06:52:22 +0000\";\n prop1 = \"a65e349a-b315-488e-b7f8-e459e353fd6e\";\n username = \"test-user\";\n password = \"foobar\";\n} and new cached row = {\n creationDate = \"2011-08-24 06:52:22 +0000\";\n prop1 = \"a65e349a-b315-488e-b7f8-e459e353fd6e\";\n username = \"test-user\";\n password = \"foobar\";\n}"
本例中错误对象的违规部分(从中打印\n和\)是错误的
用户信息
字典中冲突列表
键的值。不是很酷的解决方案-您可以为NSError类编写自己的类别,并根据需要表示文本。用户信息是NSError字典
NSLog(@" error => %@ ", [errorOrNil userInfo] )
给我印一些像这样的东西
error => {
NSLocalizedDescription = "User already exists";
NSLocalizedFailureReason = "";
NSLocalizedRecoverySuggestion = "Retry request based on information in `NSLocalizedFailureReasonErrorKey`";
kinveyErrorCode = UserAlreadyExists;
kinveyInternalErrorString = "";
kinveyRequestId = e5be0aed155e4925b3365d57de3dc5b2;
}
您也可以尝试:
NSLog(@" error => %@ ", [errorOrNil localizedDescription] )
打印出:
You got an error: User already exists
你试过简单的
NSLog(@“%@”,“error userInfo]);
或po[error userInfo]
?是的,我试过打印error的userInfo
。除了没有打印错误域和代码外,得到了与前一个相同的输出。po[error userInfo]
是什么意思?po[error userInfo]
是调试器打印用户信息字典的命令,类似于NSLog
语句。我认为您不会找到一个很好的通用解决方案。错误有不同的用户信息字典。有趣的解决方案--但我正在寻找一个更通用的解决方案,因为我不知道在t例如,在这种情况下,错误的userInfo
字典的@“conflictList”键是罪魁祸首。情况并非总是如此。
NSLog(@" error => %@ ", [errorOrNil localizedDescription] )
You got an error: User already exists