Ios 如何解析NSString

字符串是myAgent（9953593875）。金额：Rs.594并希望从中提取

9953593875

。以下是我尝试过的：

NSRange range  =  [feDetails rangeOfString:@"."];
NSString *truncatedFeDetails = [feDetails substringWithRange:NSMakeRange(0, range.location)];
NSLog(@"truncatedString-->%@",truncatedFeDetails);

这将输出：

truncatedString-->AmzAgent（9953593875）

您喜欢吗

步骤1

//首先根据

比如说

NSString *value = @"myAgent(9953593875).Amt:Rs.594.How I get 9953593875 only";

NSArray *arr = [value componentsSeparatedByString:@"."];

NSString * AmzAgent = [arr firstObject];  // or use  [arr firstObject];

NSLog(@"with name ==%@",AmzAgent);

在这里你可以得到myAgent（9953593875）的输出

步骤2

在这里使用替换字符串

AmzAgent = [AmzAgent stringByReplacingOccurrencesOfString:@"myAgent("
                                               withString:@""];
AmzAgent = [AmzAgent stringByReplacingOccurrencesOfString:@")"
                                               withString:@""];

 NSLog(@"final ==%@",AmzAgent);

最后您得到的输出是

9953593875

或者您喜欢这样做：

NSString *string = @"myAgent(9953593875).Amt:Rs.594.";

NSRange rangeOne = [string rangeOfString:@"("];
NSRange rangeTwo = [string rangeOfString:@")"];

if (rangeOne.location != NSNotFound && rangeTwo.location != NSNotFound) {
    NSString *truncatedFeDetails = [string substringWithRange:NSMakeRange(rangeOne.location + 1, rangeTwo.location - rangeOne.location - 1)];
    NSLog(@"%@",truncatedFeDetails);

}

试试这个

NSString *str = @"myAgent(9953593875).Amt:Rs.594.";
NSRegularExpression *regex = [NSRegularExpression
                              regularExpressionWithPattern:@"(?<=\\()\\d+(?=\\))"
                              options:NSRegularExpressionCaseInsensitive
                              error:nil];
NSString *result = [str substringWithRange:[regex firstMatchInString:str options:0 range:NSMakeRange(0, [str length])].range];
//result = 9953593875

NSString*str=@“我的代理人（9953593875）。金额：卢比594。”；
NSRegularExpression*regex=[NSRegularExpression
regularExpressionWithPattern:@“（？@“myAgent”是动态的。它可以更改。@akshay--哦，好吧，那么接受lovo的回答，它会帮助你，我不想覆盖代码bro