Ios 在Swift中设置警报时有关日期设置的问题

我使用选项创建了一个SchedulePicker

在此之后，我还创建了一个函数，该函数将从0到127的天数转换为字符串

struct WeekDay {
  let rawValue: Int
  let name: String

  static let mon = WeekDay(rawValue: 1, name: "Monday")
  static let tue = WeekDay(rawValue: 1<<1, name: "Tuesday")
  static let wed = WeekDay(rawValue: 1<<2, name: "Wednesday")
  static let thu = WeekDay(rawValue: 1<<3, name: "Thursday")
  static let fri = WeekDay(rawValue: 1<<4, name: "Friday")
  static let sat = WeekDay(rawValue: 1<<5, name: "Saturday")
  static let sun = WeekDay(rawValue: 1<<6, name: "Sunday")

  static let all: [WeekDay] = [.mon, .tue, .wed, .thu, .fri, .sat, .sun]
  func isIncluded(in schedule: Int) -> Bool {
    return schedule & rawValue == rawValue
  }
}

fileprivate func convertSchedule(_ schedule: Int) -> String {
  var daysToRepeat = WeekDay.all.filter({ $0.isIncluded(in: schedule) })

  if daysToRepeat.count == 0 {
    return "none"
  } else if daysToRepeat.count == 1 {
    return "Every \(daysToRepeat[0].name)"
  } else {
    return daysToRepeat.map({ $0.name }).joined(separator: ",")
  }
}

struct工作日{
让rawValue:Int
let name:String
静态let mon=WeekDay（原始值：1，名称：“星期一”）
静态let tue=WeekDay（rawValue:1我想知道问题是否不是表示的初始选择。我会这样做：

enum Weekday : Int, CaseIterable {
    case mon = 1
    case tue
    case wed
    case thu
    case fri
    case sat
    case sun
    var name : String {
        let greg = Calendar(identifier: .gregorian)
        let dayNames = greg.weekdaySymbols
        return dayNames[self.rawValue]
    }
}

这使得操作信息非常容易：

let weekdaysChosen : [Weekday] = [.mon, .tue, .fri] // example
let namesOfWeekdays = weekdaysChosen.map{$0.name}.joined(separator: ", ")
print(namesOfWeekdays) // "Mon, Tue, Fri"
let numbersOfWeekdays = weekdaysChosen.map{$0.rawValue}
print(numbersOfWeekdays) // [1, 2, 5]

不清楚问题是什么。如果您知道日期，您知道工作日，那么问题是什么？请重新措辞，或者提供示例输入和输出，最好两者都提供。我的问题是如何将已知的
计划日期（0~127）
替换为
日期组件（）
工作日