Ios 使用sqlite数据在地图上显示线

我想从sqlite数据中检索经度和纬度，然后将这些数据添加到数组中，并使用这些数组数据作为假位置来显示用户的位置

为了解决这个问题，我发送了我所有的类TLocationManager.m文件代码 -（id）init{ pointsArray=[[result componentsSeparatedByCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]]保留]；

---

NSLog（@“这是一个好主意，应该有%@”，pointsArray）； pointsArrayIndex=0； //NSLog（@“%@”，PointsRayIndex）； oldLocationsIndex=0

    [result release];

    oldLocations = [[NSMutableArray alloc] init];
    return self;
}

作为你的第一个警告

[locations addObject:[NSString stringWithFormat:"%@,%@",dLongitude,dLatitude]];//over here i am getting warring  passing argument 1 of 'stringWithFormat:'from incompatible pointer type

换成

[locations addObject:[NSString stringWithFormat:@"%@,%@",dLongitude,dLatitude]];//over here i am getting warring  passing argument 1 of 'stringWithFormat:'from incompatible pointer type

result = [locations componentsJoinedByString:@" "];

第二，您从哪里获得NSMutableArray的componentsByJoiningString函数

 //Over here getting warring 'NSMutableArray' may not respond to'-componentsByJoiningString'    
 result = [locations componentsByJoiningString:@" "]; // same as `fake_location`function

换成

[locations addObject:[NSString stringWithFormat:@"%@,%@",dLongitude,dLatitude]];//over here i am getting warring  passing argument 1 of 'stringWithFormat:'from incompatible pointer type

result = [locations componentsJoinedByString:@" "];

---

请参见NSArray..

这是一个好主意（空）它显示在控制台中我的数组仍在获取空值我想显示sqlite数据，如下42.336845，-71.12623942.336953，-71.1263942.337103，-71.1265442.337275，-71.126711 42.337457，-71.126883 42.337629，-71.127076 42.3378，-71.12726942.337908，-71.127419 42.338026，-71.12757 42.338079，-71.127656在结果中你的意思是这样吗“result=[locations componentsJoinedByString:@（”）；“请参阅我的编辑..如果要插入coma（，）put'，”。如果要插入空格put space（”），仍然显示空值。我认为sqlite数据获取空值的方式存在问题。它没有执行sqlite select语句。”