Ios 在简单的计算器应用程序中删除不必要的零

我做了一个简单的计算器，每次我点击calculate，它都会给出一个答案，但会给出六个不必要的零，我的问题是，我如何删除这些零

NSString *firstString = textfieldone.text;
NSString *secondString = textfieldtwo.text;

NSString *LEGAL = @"0123456789";
NSCharacterSet *characterSet = [[NSCharacterSet characterSetWithCharactersInString:LEGAL] invertedSet];
NSString *filteredOne = [[firstString componentsSeparatedByCharactersInSet:characterSet] 
                         componentsJoinedByString:@""];
NSString *filteredTwo = [[secondString componentsSeparatedByCharactersInSet:characterSet] 
                         componentsJoinedByString:@""];
firstString = filteredOne;
secondString = filteredTwo;

//Here we are creating three doubles
double num1;
double num2;
double output;
//Here we are assigning the values 
num1 = [firstString doubleValue];
num2 = [secondString doubleValue];

output = num1 + num2;

label.text = [NSString stringWithFormat:@"%f",output];

例如：

---

15+15=30.000000

如果使用字符串显示，请检查以下方法

NSString

NSString * display = [NSString stringWithFormat:@"%f", number];
//This approach will return 30.0000000

NSString * display = [NSString stringWithFormat:@"%.2f", number];
//While this approach will return 30.00

注意：您可以通过在“f”之前添加点和数字来指定要返回的小数位数

-已编辑- 在您的情况下，请使用以下方法：

label.text = [NSString stringWithFormat:@"%.0f", output];
//This will display your result with 0 decimal places, thus giving you '30'

---

如果使用字符串来显示，请检查以下方法

NSString

NSString * display = [NSString stringWithFormat:@"%f", number];
//This approach will return 30.0000000

NSString * display = [NSString stringWithFormat:@"%.2f", number];
//While this approach will return 30.00

注意：您可以通过在“f”之前添加点和数字来指定要返回的小数位数

-已编辑- 在您的情况下，请使用以下方法：

label.text = [NSString stringWithFormat:@"%.0f", output];
//This will display your result with 0 decimal places, thus giving you '30'

---

请试试这个。这应该完全符合您的要求

NSString * String1 = [NSString stringWithFormat:@"%f",output];
NSArray *arrayString = [String1 componentsSeperatedByString:@"."];

float decimalpart = 0.0f;
if([arrayString  count]>1)
{
   decimalpart =  [[arrayString objectAtIndex:1] floatValue];
}

//This will check if the decimal part is 00 like in case of 30.0000, only in that case it would strip values after decimal point. So output will be 30
if(decimalpart == 0.0f)
{
   label.text = [NSString stringWithFormat:@"%.0f", output];
}
else if(decimalpart > 0.0f) //This will check if the decimal part is 00 like in case of 30.123456, only in that case it would shows values upto 2 digits after decimal point. So output will be 30.12
{
   label.text = [NSString stringWithFormat:@"%.02f",output];
}

如果你需要更多的帮助，请告诉我

---

希望这对您有所帮助。

请尝试一下。这应该完全符合您的要求

NSString * String1 = [NSString stringWithFormat:@"%f",output];
NSArray *arrayString = [String1 componentsSeperatedByString:@"."];

float decimalpart = 0.0f;
if([arrayString  count]>1)
{
   decimalpart =  [[arrayString objectAtIndex:1] floatValue];
}

//This will check if the decimal part is 00 like in case of 30.0000, only in that case it would strip values after decimal point. So output will be 30
if(decimalpart == 0.0f)
{
   label.text = [NSString stringWithFormat:@"%.0f", output];
}
else if(decimalpart > 0.0f) //This will check if the decimal part is 00 like in case of 30.123456, only in that case it would shows values upto 2 digits after decimal point. So output will be 30.12
{
   label.text = [NSString stringWithFormat:@"%.02f",output];
}

如果你需要更多的帮助，请告诉我

---

希望这对您有所帮助。

我想补充一点，如果您使用

%g

说明符，这些都是不必要的。

我想补充一点，如果您使用

%g

说明符，这些都是不必要的。

使用NSDecimalNumber，它没有那些精度错误。使用NSDecimalNumber，它没有那些精度错误。