Ios 带有移动到UIView之外的触摸的UIGestureRecognitor
我有一个Ios 带有移动到UIView之外的触摸的UIGestureRecognitor,ios,objective-c,uigesturerecognizer,Ios,Objective C,Uigesturerecognizer,我有一个ui长按手势识别器,最小按长为0秒。在UIgestureRecognitizerStateStart上,我更改UIView。在UIgestureRecognitizerStateEnded上,我运行了媒体应该执行的操作的代码 -(IBAction)longPressDetected:(UILongPressGestureRecognizer *)recognizer { static NSTimer *timer = nil; if (recognizer.st
ui长按手势识别器
,最小按长为0秒。在UIgestureRecognitizerStateStart
上,我更改UIView。在UIgestureRecognitizerStateEnded
上,我运行了媒体应该执行的操作的代码
-(IBAction)longPressDetected:(UILongPressGestureRecognizer *)recognizer {
static NSTimer *timer = nil;
if (recognizer.state == UIGestureRecognizerStateBegan) {
// alter look of UIView
}
else if (recognizer.state == UIGestureRecognizerStateEnded) {
// do something
// change look back to original state
}
}
我遇到了一个问题,如果触摸在UIView
上启动,并且如果触摸被拖到UIView
之外并被提起,则uigestureRecognitizerStateEnded
仍会触发
我需要能够在ui视图
内处理触摸,用户将其拖动到ui视图
外并取消触摸
我知道一个ui按钮可以做到这一点,但它不能满足我的所有需求
如果触摸被拖动到ui视图
之外,如何取消触摸?添加触摸位置检查。这种方法可以是七倍的
-(CGPoint)位置视图:(UIView*)视图