Ios Swift字典UIPickerView（键）和（值）Swift

我目前正在使用Swift开发一个应用程序，其中我使用UIPickerView。我想在pickerView（myPickerView）中设置值

这是来自服务器的响应，我想在pickerView中显示组ListOfGrooc

代码如下：-

在

viewDidLoad

中，我有：

Picker.delegate = self
Picker.dataSource = self

那么我有必要的方法：

func numberOfComponentsInPickerView(pickerView: UIPickerView) -> Int {
            return 1
        }

func pickerView(_ pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int {
            return PickerData.count
        }

func pickerView(pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String? {
            return PickerData[row] trying to show SSSSS,DDDDD,GGGGG
        }

func pickerView(pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {
       print(PickerData[row]) expecting only id Int Value
    }

问题：-请有人向我解释如何在选择器视图标题中设置dict值，以及何时单击didSelectRow get dict键。任何帮助都将不胜感激

---

提前感谢。

根据您的数据，我创建了新的对象名CustomObject，并解析将在picker中显示的数据

这是我的密码：

struct CustomObject {
    let id: String
    let name: String
    init(id: String, name: String) {
        self.id = id
        self.name = name
    }
}
class FirstViewController: UIViewController, UIPickerViewDelegate, UIPickerViewDataSource {

    let PickerData: [String : Any] = ["listOfGrouoc": ["1": "DDDDD","2": "SDDDDD","3": "TTTT"],"TypeOfGrpos": ["STTTTT","TTTTT"],"SubTypp": ["333": "Shh","334": "SSS","543": " dfdf"],"GropName": ["1": "test","2": "test"]]
    var listOfGrouoc: [CustomObject] = []


    override func viewDidLoad() {
        super.viewDidLoad()

        let picker = UIPickerView(frame: CGRect(x: 0, y: 50, width: 300, height: 200))
        picker.dataSource = self
        picker.delegate = self
        self.view.addSubview(picker)

        if let list = PickerData["listOfGrouoc"] as? [String: String] {
            for objectID in list.keys {
                if let name = list[objectID] {
                    self.listOfGrouoc.append(CustomObject(id: objectID, name: name))
                }
            }
        }
        //Sort here
        self.listOfGrouoc.sort(by: { $0.id < $1.id})
    }

    func numberOfComponents(in pickerView: UIPickerView) -> Int {
        1
    }

    func pickerView(_ pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int {
        return listOfGrouoc.count
    }

    func pickerView(_ pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String? {
        return listOfGrouoc[row].name
    }

    func pickerView(_ pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {
        print(listOfGrouoc[row].id)
    }
}

struct自定义对象{
let id:String
let name:String
init（id:String，name:String）{
self.id=id
self.name=名称
}
}
类FirstViewController:UIViewController、UIPickerViewDeleteGate、UIPickerViewDataSource{
让PickerData:[String:Any]=[“ListofGroooc”：[“1”：“DDDDD”，“2”：“SDDDDD”，“3”：“TTTT”]，“TypeOfGrops”：[“STTTTT”，“TTTTTTT”]，“SubTypp”：[“333”：“Shh”，“334”：“SSS”，“543”：“DFDFDF”]，“GropName”：[“1”：“测试”，“2”：“测试”]
var LISTOGFROOC:[CustomObject]=[]
重写func viewDidLoad（）{
super.viewDidLoad（）
让picker=UIPickerView（帧：CGRect（x:0，y:50，宽度：300，高度：200））
picker.dataSource=self
picker.delegate=self
self.view.addSubview（选择器）
如果let list=PickerData[“ListOfGrooc”]as？[String:String]{
对于list.keys中的objectID{
如果let name=list[objectID]{
self.listofGroooc.append（CustomObject（id:objectID，name:name））
}
}
}
//在这里分类
self.listofGroooc.sort（按：{$0.id<$1.id}）
}
func numberOfComponents（在pickerView:UIPickerView中）->Int{
1.
}
func pickerView（pickerView:UIPickerView，numberOfRowsInComponent:Int）->Int{
返回listofGroooc.count
}
func pickerView（pickerView:UIPickerView，titleForRow行：Int，forComponent组件：Int）->String{
返回ListOfGrooc[row].name
}
func pickerView（pickerView:UIPickerView，didSelectRow行：Int，不完整组件：Int）{
打印（LISTOGFROOC[row].id）
}
}

您能否举例说明您试图在选择器中显示的数据的哪一部分，以及您希望在didSelectRow上获得的值？@elliott io请勾选“我试图仅显示名称”和“选择名称时获取Int value.Cool”。我发布了一个有效的答案。@elliott io好的，我会检查并更新您。感谢您的回复Hello Traj，是否有任何选项可以根据键值对该数组进行排序。因为我得到的是随机数组，但我想排序得更低higher@ShamDhiman请在viewDidLoad中检查我的更新。Bcz这是字典的特点，所以在生成数组后，我们需要按照您的预期对其重新排序。@traj谢谢您的回复，我已经尝试过了，但它对您不起作用me@traj我只想对子类型参数进行排序，比如3,6,9，当我对它进行排序时，它们会返回14,9,3,6，我不知道为什么，这对我来说没有任何解决方案？@ShamDhiman执行与

listogfrouoc

相同的操作，创建另一个对象并对其进行解析，然后再次排序。让我看看你试图对SubTypp排序的内容

struct CustomObject {
    let id: String
    let name: String
    init(id: String, name: String) {
        self.id = id
        self.name = name
    }
}
class FirstViewController: UIViewController, UIPickerViewDelegate, UIPickerViewDataSource {

    let PickerData: [String : Any] = ["listOfGrouoc": ["1": "DDDDD","2": "SDDDDD","3": "TTTT"],"TypeOfGrpos": ["STTTTT","TTTTT"],"SubTypp": ["333": "Shh","334": "SSS","543": " dfdf"],"GropName": ["1": "test","2": "test"]]
    var listOfGrouoc: [CustomObject] = []


    override func viewDidLoad() {
        super.viewDidLoad()

        let picker = UIPickerView(frame: CGRect(x: 0, y: 50, width: 300, height: 200))
        picker.dataSource = self
        picker.delegate = self
        self.view.addSubview(picker)

        if let list = PickerData["listOfGrouoc"] as? [String: String] {
            for objectID in list.keys {
                if let name = list[objectID] {
                    self.listOfGrouoc.append(CustomObject(id: objectID, name: name))
                }
            }
        }
        //Sort here
        self.listOfGrouoc.sort(by: { $0.id < $1.id})
    }

    func numberOfComponents(in pickerView: UIPickerView) -> Int {
        1
    }

    func pickerView(_ pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int {
        return listOfGrouoc.count
    }

    func pickerView(_ pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String? {
        return listOfGrouoc[row].name
    }

    func pickerView(_ pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {
        print(listOfGrouoc[row].id)
    }
}