Iphone 多维数组问题

我正在基于API中的json数据为节/行创建多维数组。查看日志，添加行和节看起来不错，但当我记录这些节时，它只显示最后一个对象的一堆。似乎没有将行添加到节中

让最后一个API对象显示在x部分中，我做错了什么？x表示json计数<代码>自我预约是一个

NSArray*

根据我的看法，它应该是有效的

NSDictionary *json = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error];
        NSMutableArray *sections = [[NSMutableArray alloc] init];
        NSMutableArray *rows = [[NSMutableArray alloc] init];
        NSString *lastDate = nil;
        for (NSDictionary *dict in [json objectForKey:@"data"]) {
            NSString *date = [dict objectForKey:@"date"];
            NSLog(@"Dates: %@ - %@", date, lastDate);
            if (date != lastDate) {
                if (lastDate == nil) {
                    NSLog(@"Adding Row 1");
                    [rows addObject:dict];
                    lastDate = date;
                } else {
                    NSLog(@"Adding Section 1");
                    NSLog(@"Adding #rows %i",[rows count]);
                    [sections addObject:rows];
                    [rows removeAllObjects];
                    NSLog(@"Adding Row 2 %@",[dict objectForKey:@"start_time"]);
                    [rows addObject:dict];
                    lastDate = date;
                }
            } else {
                NSLog(@"Adding Row 3");
                [rows addObject:dict];
            }
        }
        if (rows) {
            NSLog(@"Adding Section 2");
            NSLog(@"Adding #rows %i",[rows count]);
            [sections addObject:rows];
        }
        NSLog(@"Sections: %@", sections);

        self.appointments = [sections mutableCopy]; //I have also tried self.appointments = sections

        sections = nil;
        rows = nil;

日志显示

Sections: (
        (
                {
            abbrev = "";
            account = "";
            "addOnService_id" = "";
            alert = "";
            "appt_id" = 1839384;
            "appt_id_unique" = 1839384;
            "appt_status_description" = "";
            "appt_status_type" = "";
            "c_id" = 47;
            cost = "0.00";
            "coupon_id" = "";
            "creation_emp_id" = 2288;
            "creation_timestamp" = 201111040717;
            "customer_id" = 0;
            "customer_notes" = "";
            "customer_package_id" = "";
            date = 20121228;
            "employee_id" = 2288;
            "employee_notes" = "";
            employer = "";
            "end_time" = 570;
            "first_name" = "";
            "history_id" = 1830959;
            key = 134;
            "last_emp_id" = 2288;
            "last_name" = "";
            "last_timestamp" = 201111040717;
            "lead_description" = "";
            "link_id" = 0;
            "location_name" = "Telephonic Setup/Training";
            "make_id" = "";
            "middle_name" = "";
            "model_id" = "";
            "model_year" = "";
            name = "My Name ";
            odometer = "";
            "other_vehicle" = "";
            "package_name" = "";
            "payment_type_description" = "";
            "payment_type_id" = "";
            "pet_id" = "";
            "po_number" = "";
            reason = "B.O.B";
            "rebook_id" = "";
            "recur_id" = 20954;
            "rep_id" = "";
            "room_id" = 0;
            "room_name" = "";
            service = "";
            "service_id" = 0;
            "service_time_description" = "";
            spots = 1;
            "staff_screen_name" = "John Smith";
            "staff_type_id" = 0;
            "start_time" = 540;
            "status_id" = 0;
            tip = "";
            "type_id" = 8;
            vin = "";
        }
    ),
        (
                {
            abbrev = "";
            account = "";
            "addOnService_id" = "";
            alert = "";
            "appt_id" = 1839384;
            "appt_id_unique" = 1839384;
            "appt_status_description" = "";
            "appt_status_type" = "";
            "c_id" = 47;
            cost = "0.00";
            "coupon_id" = "";
            "creation_emp_id" = 2288;
            "creation_timestamp" = 201111040717;
            "customer_id" = 0;
            "customer_notes" = "";
            "customer_package_id" = "";
            date = 20121228;
            "employee_id" = 2288;
            "employee_notes" = "";
            employer = "";
            "end_time" = 570;
            "first_name" = "";
            "history_id" = 1830959;
            key = 134;
            "last_emp_id" = 2288;
            "last_name" = "";
            "last_timestamp" = 201111040717;
            "lead_description" = "";
            "link_id" = 0;
            "location_name" = "Telephonic Setup/Training";
            "make_id" = "";
            "middle_name" = "";
            "model_id" = "";
            "model_year" = "";
            name = "My Name ";
            odometer = "";
            "other_vehicle" = "";
            "package_name" = "";
            "payment_type_description" = "";
            "payment_type_id" = "";
            "pet_id" = "";
            "po_number" = "";
            reason = "B.O.B";
            "rebook_id" = "";
            "recur_id" = 20954;
            "rep_id" = "";
            "room_id" = 0;
            "room_name" = "";
            service = "";
            "service_id" = 0;
            "service_time_description" = "";
            spots = 1;
            "staff_screen_name" = "John Smith";
            "staff_type_id" = 0;
            "start_time" = 540;
            "status_id" = 0;
            tip = "";
            "type_id" = 8;
            vin = "";
        }
    ), ... over and over again.

与：

您不断添加相同的

行

对象，而不是新的，并不断更改内容，以便每次都显示最后的内容

尝试：

这样，每次都会添加一个新行

也许更好的是：

NSDictionary *json = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error];
NSMutableArray *sections = [NSMutableArray array];
NSMutableArray *rows = [NSMutableArray array];
NSString *lastDate = nil;
for (NSDictionary *dict in [json objectForKey:@"data"]) {
    NSString *date = [dict objectForKey:@"date"];
    if ([date isEqualToString:lastDate] == NO) {
        if (lastDate == nil) {
            [rows addObject:dict];
            lastDate = date;
        } else {
            [sections addObject:rows];
            rows = [NSMutableArray array];
            [rows addObject:dict];
            lastDate = date;
        }
        [rows addObject:dict];
    }
}
if (rows) {
    [sections addObject:rows];
}

self.appointments = sections;

请注意，将0指定给对象并不会释放它，

release

会释放它。但是，如果您使用方便的方法创建对象，那么它们将自动释放，无需采取进一步的操作来释放它们

---

还要注意，在比较字符串时，需要使用

IsequalString:

方法来比较内容，只需使用

=

或

=仅比较字符串的地址。
有效：）mutableCopy的确切用途是什么？另外，似乎在大约2个月的日期之后，它开始为每一行创建一个节，尽管节相同，但开始时间不同。我假设它设置了最后一个节，因为我使用了引用指针并取消了行数组的设置。正确吗？
mutableCopy
可能是
copy
，具体取决于进一步的使用。关键是创建一个新数组。向数组中添加对象只会添加点（并增加保留计数），多次添加同一对象只会添加同一指针，因此每次添加的内容都相同。最后一个内容就是所看到的内容。我编辑了您的代码帖子，其中包括
[sections addObject:[rows mutableCopy]]您前面提到过。在可能更好的代码中，不需要
[rows mutableCopy]
，因为下一行创建了一个新数组，这是示例的重点，并且创建对象的方便方法，然后自动删除它们。因此，我回滚了编辑。
[sections addObject:[rows mutableCopy]]; 
[rows removeAllObjects];
[rows addObject:dict];

NSDictionary *json = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error];
NSMutableArray *sections = [NSMutableArray array];
NSMutableArray *rows = [NSMutableArray array];
NSString *lastDate = nil;
for (NSDictionary *dict in [json objectForKey:@"data"]) {
    NSString *date = [dict objectForKey:@"date"];
    if ([date isEqualToString:lastDate] == NO) {
        if (lastDate == nil) {
            [rows addObject:dict];
            lastDate = date;
        } else {
            [sections addObject:rows];
            rows = [NSMutableArray array];
            [rows addObject:dict];
            lastDate = date;
        }
        [rows addObject:dict];
    }
}
if (rows) {
    [sections addObject:rows];
}

self.appointments = sections;