Iphone 使用NSPredicate获取核心数据对象时出现问题

在开始之前，让我向您介绍我的数据模型的外观：

然后，我有一个带有以下谓词的获取请求：

NSArray *allowedPackNames = @[@"success, happiness, free"];
            self.fetchedResultsController = [Author MR_fetchAllGroupedBy:nil
                                                           withPredicate:[NSPredicate predicateWithFormat:@"ANY quotes.quote.pack.packName IN %@", allowedPackNames]
                                                                sortedBy:AuthorKeys.name
                                                               ascending:YES
                                                                delegate:self];

我想把所有引用成功、幸福或自由的名言的作者都找来。 作者有一组引号，您可以在下面的关系表中看到。但是，当我执行此操作时，会出现以下错误：

CoreData: error: (1) I/O error for database at /Users/Abdul/Library/Application Support/iPhone Simulator/6.1/Applications/DA17421B-A54D-42E3-9694-FDCBFF7F8BA4/Library/Application Support/MyCoolApp/MyCoolApp.sqlite.  SQLite error code:1, 'no such column: t2.ZQUOTE'
2013-04-05 15:26:47.175 MyCoolApp[78622:c07] Core Data: annotation: -executeRequest: encountered exception = I/O error for database at /Users/Aditya/Library/Application Support/iPhone Simulator/6.1/Applications/DA17421B-A54D-42E3-9694-FDCBFF7F8BA4/Library/Application Support/MyCoolApp/MyCoolApp.sqlite.  SQLite error code:1, 'no such column: t2.ZQUOTE' with userInfo = {
    NSFilePath = "/Users/Abdul/Library/Application Support/iPhone Simulator/6.1/Applications/DA17421B-A54D-42E3-9694-FDCBFF7F8BA4/Library/Application Support/MyCoolApp/MyCoolApp.sqlite";
    NSSQLiteErrorDomain = 1;
}

---

知道为什么吗？

如果我看对了，谓词应该是

[NSPredicate predicateWithFormat:@"ANY quotes.pack.packName IN %@", allowedPackNames]

---

i、 e.您必须删除“quote”，它是quote实体的一个属性，而不是关系。

如果我看对了，谓词应该是

[NSPredicate predicateWithFormat:@"ANY quotes.pack.packName IN %@", allowedPackNames]

i、 e.您必须删除“quote”，它是quote实体的属性，而不是关系