Java 从Servlet调用JSP页面

Java 从Servlet调用JSP页面,java,jsp,servlets,Java,Jsp,Servlets,有人能告诉我,除了RequestDispatcher之外,是否还有其他方法可以从我的servlet调用jsp页面?因为我尝试了很多,但都没有成功 我的servlet工作正常,并从jsp中恢复了所有数据。当用户正确输入用户名和密码时,我只需要重定向到另一个页面 我的代码: 首先是我的servlet登录 protected void processRequest(HttpServletRequest request,HttpServletResponse response) thro

有人能告诉我,除了RequestDispatcher之外,是否还有其他方法可以从我的servlet调用jsp页面?因为我尝试了很多,但都没有成功

我的servlet工作正常,并从jsp中恢复了所有数据。当用户正确输入用户名和密码时,我只需要重定向到另一个页面

我的代码:

首先是我的servlet登录

protected void processRequest(HttpServletRequest request,HttpServletResponse response)
        throws ServletException, IOException {
    response.setContentType("text/html;charset=UTF-8");
    PrintWriter out = response.getWriter();

}


  protected void doGet(HttpServletRequest request, HttpServletResponse      response)
        throws ServletException, IOException {
    processRequest(request, response);
}


    protected void doPost(HttpServletRequest request, HttpServletResponse response)
        throws ServletException, IOException {
    try {
        String user = request.getParameter("username");
        String pass = request.getParameter("password");         
      System.out.println(" le user est "+user+ " le mot de passe est " + pass);

          String query = "SELECT * FROM users WHERE username = '"+user+"' and password='"+pass+"'";

      dbconn = new DBAccess();
      Connection conn = dbconn.connect();

         stmt = conn.createStatement();
         ResultSet res = stmt.executeQuery(query);

            if(res.next()){
              ServletContext sc = this.getServletContext();
              RequestDispatcher rd =sc.getRequestDispatcher( "inscreption.jsp");
              rd.forward(request, response);   
                 System.out.println(" il existe");

            }else { 
           ServletContext sc = this.getServletContext();
            RequestDispatcher rd = sc.getRequestDispatcher("index.jsp");
             //   RequestDispatcher rd =request.getRequestDispatcher("index.jsp");
                rd.forward(request, response);   
                System.out.println("not found");


      }
    } catch (SQLException ex) {
        Logger.getLogger(login.class.getName()).log(Level.SEVERE, null, ex);
    }


    finally{
        System.out.close();
    }





    }}
    /**
     * Returns a short description of the servlet.
     *
     * @return a String containing servlet description
      */
   /* @Override
    public String getServletInfo() {
        return "Short description";
    }// </editor-fold>
我希望重定向到的jsp

<html>
<head>
    <!--local jquery-->
    <script  src="jQuerys/jquery-1.9.1.min.js"></script>
    <script  src="jQuerys/jquery.mobile-1.3.1.min.js"></script>
    <link rel ="stylesheet" type="text/css" href="css/jqueryMobile-1.3.1.css"/>
    <!--/local jquery-->
      </head>

      <body>
<div data-role="page" id="inscription">
<div data-role="header" data-theme="b">
    <center>CERIST</center>
</div>
                  <form id="insc" method="post" action="login">

  <div data-role="content">
    <div data-role="fieldcontain">
        <label for="identifiant">Identifiant </label>
        <input type="text" id="identifiant"/>
    </div>
    <div data-role="fieldcontain">
        <label for="password1">Mot de passe </label>
        <input type="password" id="password1"/>
    </div>
    <div data-role="fieldcontain">
        <label for="password2">Confirmation</label>
        <input type="password" id="password2"/>
    </div>
    <div data-role="fieldcontain">
        <fieldset data-role="controlgroup">
            <legend>Vous &ecirc;tes :</legend>
                <input type="radio" name="profil" id="radio-choice-1" value="Candidat" />
                <label for="radio-choice-1">Utilisateur</label>

                <input type="radio" name="profil" id="radio-choice-2" value="Entreprise"  />
                <label for="radio-choice-2">Administrateur</label>
        </fieldset>
    </div>
    <br/>
    <a href="#" data-role="button" onclick="">S'inscrire</a>

        </form>

  </div>
 </div>
      </body>
</html>
index.jsp:
您可以在想要发送请求的地方创建两个以上的页面,所以我在这里创建了两个以上的jsp页面名称:right.jsp和error.jsp。如果用户名和密码正确,那么它将向前移动到right.jsp页面。如果用户名和密码错误,它将请求向前移动到right.jsp页面。

部署相关的jsp文件存储在哪里?另外,请阅读中的小Bobby表。为什么要从servlet调用JSP?来填写另一个form@AbdelbakiElfodil,共享给定servlet的url模式和关于web文件夹的jsp路径。还可以分享重定向到jspif时遇到的错误。如果存在除RequestDispatcher=>no以外的任何方法,则没有其他方法。这听起来像一个例子。如果需要从servlet向JSP传递数据,请使用。这些可以从JSP访问,例如通过。仍然不起作用。你不会认为我的url路径有问题吗?请检查这一行rd=request.getRequestDispatcher/inscreption.JSP;并检查web.xml文件,其中
<form action="Myservlet" method="post"><br>
            User name`<`input type="text" name="username"`>`<br>
            Password `<`input type="password" name="password"><br>
            `<`input type="submit" value="Submit" `>`

</form>
protected void processRequest(HttpServletRequest request, HttpServletResponse response)
        throws ServletException, IOException {
    response.setContentType("text/html;charset=UTF-8");
    PrintWriter out = response.getWriter();
    out.print("Oppos!!!");

}

@Override
protected void doGet(HttpServletRequest request, HttpServletResponse response)
        throws ServletException, IOException {
    processRequest(request, response);
}

@Override
protected void doPost(HttpServletRequest request, HttpServletResponse response)
        throws ServletException, IOException {
    String user = request.getParameter("username");
    String pass = request.getParameter("password");
    RequestDispatcher rd;
    if (user.equals("username") && pass.equals("password")) {
        rd = request.getRequestDispatcher("/inscreption.jsp");
        rd.forward(request, response);
    } else {
        rd = request.getRequestDispatcher("/wrong.jsp");
        rd.forward(request, response);

    }
}