Java 正在解析仅包含“0”的JSON响应；“行”；及；“列”；到波乔

即使响应只发回行和列，也可以解析对POJO的JSON响应吗

我从一个API得到这样的响应：

{
"rows": [
[
  "FIRST NATIONAL BANK OF OMAHA",
  36644,
  "COM",
  44527,
  198809,
  "SH",
  -1.5631,
  "Put",
  "2019-09-30"
],
[
  "WAYNE HUMMER INVESTMENTS L.L.C.",
  49096,
  "COM",
  17975,
  90817,
  "SH",
  2.8971,
  "Put",
  "2019-06-30"
]
],
"columns": [
"Institution Name",
"Institution CIK",
"Class of Security Held",
"Value of Security Held",
"Volume of Security Held",
"Type of Security Held",
"Quarterly Change in Security Held",
"Put/Call",
"Report Date"
]
}

这是我正在使用的代码，为简洁起见，将其缩短，以连接到API并获取JSON响应，我使用Gson通过反序列化器类传递JSON响应：

public static void requestResponse(){

   URL apiURL = new URL("http://apilink.com/api/getSomething.json?T=gnbuweiogh9y89234y&symbol=GOOG");

   String readLine = null;

   HttpConnection apiConnection =  (HttpConnection) apiURL.openConnection();

   apiConnection.setRequestMethod("GET");

   int responseCode = apiConnection.getResponseCode();

   if(responseCode == HttpConnection.HTTP_OK) {

       BufferedReader in = new BufferedReader(new InputStreamReader(apiConnection.getInputStream()));

       StringBuffer response = new StringBuffer();

       while((readLine = in.readLine()) != null) {
           response.append(readLine);
       }
       in.close();

       String jsonResponse = response.toString();

       Deserializer deSerializer = new Gson().fromJson(jsonResponse, Deserializer .class);
       List<String> columns = deSerializer.getColumns;
       // Do something with the data
   }
}

很抱歉写了这么长的文章，但是反序列化POJO响应的最佳方法是什么

---

非常感谢。

您可以通过将以下帮助程序方法添加到您的

反序列化程序

类，将其转换为所需的格式：

public List<Map<String, Object>> asListOfMaps() {
    List<Map<String, Object>> list = new ArrayList<>(this.rows.size());
    for (List<Object> data : this.rows) {
        Map<String, Object> row = new LinkedHashMap<>(this.columns.size());
        for (int i = 0; i < this.columns.size(); i++)
            row.put(this.columns.get(i), data.get(i));
        list.add(row);
    }
    return list;
}

公共列表aslistofmap（）{
List List=newarraylist（this.rows.size（））；
for（列表数据：this.rows）{
Map row=newlinkedhashmap（this.columns.size（））；
对于（int i=0；i

谢谢你的回答。我将阅读更多关于将字符串列表映射到对象列表的内容，也许这就是我想要的。我感谢你的帮助，并将接受你的答复。

{
 "data": [{
"Institution Name": "FIRST NATIONAL BANK OF OMAHA",
"Institution CIK": 36644,
"Class of Security Held": "COM",
"Value of Security Held": 44527
 } ]
}

public List<Map<String, Object>> asListOfMaps() {
    List<Map<String, Object>> list = new ArrayList<>(this.rows.size());
    for (List<Object> data : this.rows) {
        Map<String, Object> row = new LinkedHashMap<>(this.columns.size());
        for (int i = 0; i < this.columns.size(); i++)
            row.put(this.columns.get(i), data.get(i));
        list.add(row);
    }
    return list;
}