Java 点击"；rel"；使用selenium的属性

我试图使用java和selenium从站点的下拉菜单中选择一个选项。由于类名的唯一性，我可以单击大小7。但是，我无法像我希望的那样单击9号或10.5号。所以我想知道我是否能够基于rel属性单击

<li class="nsg-form--drop-down--option  first-in-row upper-left" rel="3161894:7"> 7 </li>
<li class="nsg-form--drop-down--option" rel="3161895:7.5"> 7.5 </li>
<li class="nsg-form--drop-down--option last-in-row upper-right" rel="3161896:8"> 8 </li>
<li class="nsg-form--drop-down--option first-in-row" rel="3161897:8.5"> 8.5 </li>
<li class="nsg-form--drop-down--option" rel="3161898:9"> 9 </li>
<li class="nsg-form--drop-down--option last-in-row" rel="3161899:9.5"> 9.5 </li>
<li class="nsg-form--drop-down--option first-in-row" rel="3161900:10"> 10 </li>
<li class="nsg-form--drop-down--option" rel="3161901:10.5"> 10.5 </li>
<li class="nsg-form--drop-down--option last-in-row" rel="3161902:11"> 11 </li>
<li class="nsg-form--drop-down--option first-in-row" rel="3161903:11.5"> 11.5 </li>

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我不太熟悉Selenium RC，但您应该在这里尝试CSS选择器或XPath

// CSS Selector
selenium.click("css=li.nsg-form--drop-down--option[rel$=':9']"); // rel ends with :9
selenium.click("css=li.nsg-form--drop-down--option[rel^='3161898']"); // rel starts with 3161898

// XPath
selenium.click("xpath=//li[contains(@class, 'nsg-form--drop-down--option') and contains(@rel, ':9')]");
selenium.click("xpath=//li[contains(@class, 'nsg-form--drop-down--option') and starts-with(@rel, '3161898')]");

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我觉得如果它是下拉菜单中的一个元素，那么使用以下语法选择该元素：

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selenium.select（“下拉列表的定位器”，“索引=索引号”）

对xpath一点也不熟悉，但这很有效！谢谢你的帮助！

// CSS Selector
selenium.click("css=li.nsg-form--drop-down--option[rel$=':9']"); // rel ends with :9
selenium.click("css=li.nsg-form--drop-down--option[rel^='3161898']"); // rel starts with 3161898

// XPath
selenium.click("xpath=//li[contains(@class, 'nsg-form--drop-down--option') and contains(@rel, ':9')]");
selenium.click("xpath=//li[contains(@class, 'nsg-form--drop-down--option') and starts-with(@rel, '3161898')]");