从Java代码转换的Python错误

我正在努力学习python。因此，我有一个下面的Java代码来打印输入的数字的因子列表。我试图在python中实现相同的逻辑。但是有一些错误。java代码如下所示：

public final class PrintFactors {

private PrintFactors() {}

public static void printFactors(int number) {
    if (number <= 0) throw new IllegalArgumentException("The number should be greater than 0.");
    printFactorsList(number, number + "*" + 1 + "\n", number);
}

private static void printFactorsList(int dividend, String factorString, int prevDivisor) {

    for (int divisor = dividend - 1; divisor >= 2; divisor--) {

        if (dividend % divisor != 0)
            continue;

        if (divisor > prevDivisor)
            continue;

        int quotient = dividend / divisor;


        if (quotient <= divisor) {
            if (quotient <= prevDivisor) {
                System.out.println(factorString + divisor + "*" + quotient);
            }
        }
        printFactorsList(quotient, factorString + divisor + "*", divisor);
    }
}

public static void main(String[] args) {
    printFactors(12);
    System.out.println();
    printFactors(32);
}

 $ java -cp . PrintFactors 32

def print_factors_list(dividend, factorstring, predivisor):

divisor = dividend - 1
for i in range(int(divisor), 2, -1 ):
    if dividend % i != 0:
        continue

    if divisor > predivisor:
        continue

    quotient = dividend / divisor


    if quotient <= divisor:
        if quotient <= predivisor:
            print factorstring + str(divisor) + "*" + str(quotient)


print_factors_list(quotient, str(factorstring) + str(divisor) + "*", divisor)


def print_factors(x):
if (x < 0):
    print "Enter a positive interger"
else:
    print_factors_list(x, str(x) + "*" + str(1) + "\n", x )

num = int(input("Enter a number: "))
print_factors(num)

32*1

16*2

8*4

8*2*2

4*4*2

4*2*2*2

2*2*2*2*2

我的python代码如下所示：

public final class PrintFactors {

private PrintFactors() {}

public static void printFactors(int number) {
    if (number <= 0) throw new IllegalArgumentException("The number should be greater than 0.");
    printFactorsList(number, number + "*" + 1 + "\n", number);
}

private static void printFactorsList(int dividend, String factorString, int prevDivisor) {

    for (int divisor = dividend - 1; divisor >= 2; divisor--) {

        if (dividend % divisor != 0)
            continue;

        if (divisor > prevDivisor)
            continue;

        int quotient = dividend / divisor;


        if (quotient <= divisor) {
            if (quotient <= prevDivisor) {
                System.out.println(factorString + divisor + "*" + quotient);
            }
        }
        printFactorsList(quotient, factorString + divisor + "*", divisor);
    }
}

public static void main(String[] args) {
    printFactors(12);
    System.out.println();
    printFactors(32);
}

 $ java -cp . PrintFactors 32

def print_factors_list(dividend, factorstring, predivisor):

divisor = dividend - 1
for i in range(int(divisor), 2, -1 ):
    if dividend % i != 0:
        continue

    if divisor > predivisor:
        continue

    quotient = dividend / divisor


    if quotient <= divisor:
        if quotient <= predivisor:
            print factorstring + str(divisor) + "*" + str(quotient)


print_factors_list(quotient, str(factorstring) + str(divisor) + "*", divisor)


def print_factors(x):
if (x < 0):
    print "Enter a positive interger"
else:
    print_factors_list(x, str(x) + "*" + str(1) + "\n", x )

num = int(input("Enter a number: "))
print_factors(num)

---

请有人帮我解决这个问题，我哪里做错了。当我将这些步骤作为Java代码实现时，是否存在逻辑错误？谢谢

Python对缩进敏感。您的

print\u factors\u list

递归调用位于最外层缩进级别，因此它不在

for

循环的范围内。这与Java代码的行为不同。

请修复您的错误indentation@MattDMo仍然没有给出期望的输出？有什么建议吗有什么改变的建议吗？我试着把它放在循环中。它没有给我想要的输出