Java 为什么列出Recyclerview在所有位置返回相同的项目？

在我的android应用程序中，我使用recycler视图显示项目

（注意：这不是一个重复的问题，因为我尝试了stackoverflow的许多答案，但没有找到解决方案。）

我的问题
显示重复项目的回收器视图。单个项重复多次，即使它在源数据库中只出现一次

我检查了原因并注意到Adapter类中的List对象在所有迭代中返回相同的值。但将列表对象发送到具有唯一值的适配器类的片段

但只有在接收到列表对象后，适配器类才包含重复项

我尝试过的解决方案

• 我检查了Stackoverflow，并在适配器类中添加了getItemId（int位置）和getItemViewType（int位置），但没有解决方案

• 我检查了数据库和列表视图发送类都没有重复的项

我的代码：

InboxHostFragment.java=此类将列表对象发送到回收器视图的适配器类：

在上面的代码中，feedItemList返回重复的值，即使源clas Inboxfragment.java中的movieList列表包含唯一的值

请帮我解决这个问题。我在Stackoverflow中尝试了许多答案，但我找不到解决方案。我想不出这个问题。

使用此代码

  for (int i = 0; i < contact.length(); i++) {
   JSONObject obj1 = contact.optJSONObject(i);
   ListFeed movie = new ListFeed();

   movie.getuserby(obj1.getString("userby"));
   movie.resid(obj1.getString("reservation_id"));
   movie.setresidinbox(obj1.getString("reservation_id"));
   System.out.println("reservation iddgdsds" + obj1.getString("reservation_id"));
   movie.setuserbys(obj1.getString("userby"));
   movie.setuserto(obj1.getString("userto"));
   movie.setid(obj1.getString("room_id"));
   movie.getid1(obj1.getString("id"));
   movie.userto(obj1.getString("userto"));
   movie.isread(obj1.getString("isread"));
   movie.userbyname(obj1.getString("userbyname"));
   country_symbol = obj1.getString("currency_code");
   Currency c = Currency.getInstance(country_symbol);
   country_symbol = c.getSymbol();
   movie.setsymbol(country_symbol);


   movie.setTitle(obj1.getString("title"));
   movie.setThumbnailUrl(obj1.getString("profile_pic"));
   movie.setstatus(obj1.getString("status"));
   movie.setcheckin(obj1.getString("checkin"));
   movie.setcheckout(obj1.getString("checkout"));
   movie.setcreated(obj1.getString("created"));
   movie.guest(obj1.getString("guest"));
   movie.userbyname(obj1.getString("username"));
   movie.getprice(obj1.getString("price"));
   String msg = obj1.getString("message");
   msg = msg.replaceAll("<b>You have a new contact request from  ", "");
   msg = msg.replaceAll("</b><br><br", "");
   msg = msg.replaceAll("\\w*\\>", "");
   movie.message(msg);

   movieList.add(movie);
   System.out.println(movieList.get(i).message()); // returning unique value

  }

for（int i=0；i”，”）；
电影讯息(msg),；
movieList.add（电影）；
System.out.println（movieList.get（i.message（））；//返回唯一值
}

声明

ListFeed movie=newlistfeed（）进入
for循环
并移除
适配器。notifyDataSetChanged（）来自循环的

我认为这对您有帮助。
使用此代码

  for (int i = 0; i < contact.length(); i++) {
   JSONObject obj1 = contact.optJSONObject(i);
   ListFeed movie = new ListFeed();

   movie.getuserby(obj1.getString("userby"));
   movie.resid(obj1.getString("reservation_id"));
   movie.setresidinbox(obj1.getString("reservation_id"));
   System.out.println("reservation iddgdsds" + obj1.getString("reservation_id"));
   movie.setuserbys(obj1.getString("userby"));
   movie.setuserto(obj1.getString("userto"));
   movie.setid(obj1.getString("room_id"));
   movie.getid1(obj1.getString("id"));
   movie.userto(obj1.getString("userto"));
   movie.isread(obj1.getString("isread"));
   movie.userbyname(obj1.getString("userbyname"));
   country_symbol = obj1.getString("currency_code");
   Currency c = Currency.getInstance(country_symbol);
   country_symbol = c.getSymbol();
   movie.setsymbol(country_symbol);


   movie.setTitle(obj1.getString("title"));
   movie.setThumbnailUrl(obj1.getString("profile_pic"));
   movie.setstatus(obj1.getString("status"));
   movie.setcheckin(obj1.getString("checkin"));
   movie.setcheckout(obj1.getString("checkout"));
   movie.setcreated(obj1.getString("created"));
   movie.guest(obj1.getString("guest"));
   movie.userbyname(obj1.getString("username"));
   movie.getprice(obj1.getString("price"));
   String msg = obj1.getString("message");
   msg = msg.replaceAll("<b>You have a new contact request from  ", "");
   msg = msg.replaceAll("</b><br><br", "");
   msg = msg.replaceAll("\\w*\\>", "");
   movie.message(msg);

   movieList.add(movie);
   System.out.println(movieList.get(i).message()); // returning unique value

  }

for（int i=0；i”，”）；
电影讯息(msg),；
movieList.add（电影）；
System.out.println（movieList.get（i.message（））；//返回唯一值
}

声明
ListFeed movie=newlistfeed（）进入
for循环
并移除
适配器。notifyDataSetChanged（）来自循环的

我认为这对您有帮助。
代码中的recyclerview在哪里？我不知道上面有什么，但请参阅的CustomAdapter类了解如何设置recyclerview！并查看片段以查看其调用方式。@Ragesh D Antony if（listFeed.guest（）.equals（“1”）{holder.guest.setText（listFeed.guest（）+activity.getResources（）.getString（R.string.guests））；}else{holder.guest.setText（listFeed.guest（）+activity.getResources（）.getString（R.string.guests））；}在正确和错误的部分，您正在做同样的事情。您能告诉我们创建InboxHostAdapter“public InboxHostAdapter（上下文活动，ListfeedItemList，String标记）”的调用方代码吗。我想看看你是如何得到“feedItemList”的。这个问题是通过@SSALPHAX在下面的回答中提到的步骤解决的。谢谢你的回答你的代码里有回收视图吗？我不知道那是什么
  for (int i = 0; i < contact.length(); i++) {
   JSONObject obj1 = contact.optJSONObject(i);
   ListFeed movie = new ListFeed();

   movie.getuserby(obj1.getString("userby"));
   movie.resid(obj1.getString("reservation_id"));
   movie.setresidinbox(obj1.getString("reservation_id"));
   System.out.println("reservation iddgdsds" + obj1.getString("reservation_id"));
   movie.setuserbys(obj1.getString("userby"));
   movie.setuserto(obj1.getString("userto"));
   movie.setid(obj1.getString("room_id"));
   movie.getid1(obj1.getString("id"));
   movie.userto(obj1.getString("userto"));
   movie.isread(obj1.getString("isread"));
   movie.userbyname(obj1.getString("userbyname"));
   country_symbol = obj1.getString("currency_code");
   Currency c = Currency.getInstance(country_symbol);
   country_symbol = c.getSymbol();
   movie.setsymbol(country_symbol);


   movie.setTitle(obj1.getString("title"));
   movie.setThumbnailUrl(obj1.getString("profile_pic"));
   movie.setstatus(obj1.getString("status"));
   movie.setcheckin(obj1.getString("checkin"));
   movie.setcheckout(obj1.getString("checkout"));
   movie.setcreated(obj1.getString("created"));
   movie.guest(obj1.getString("guest"));
   movie.userbyname(obj1.getString("username"));
   movie.getprice(obj1.getString("price"));
   String msg = obj1.getString("message");
   msg = msg.replaceAll("<b>You have a new contact request from  ", "");
   msg = msg.replaceAll("</b><br><br", "");
   msg = msg.replaceAll("\\w*\\>", "");
   movie.message(msg);

   movieList.add(movie);
   System.out.println(movieList.get(i).message()); // returning unique value

  }