Java Joda time查找小时之间的差异
我有一个日期字符串:Java Joda time查找小时之间的差异,java,android,datetime,jodatime,Java,Android,Datetime,Jodatime,我有一个日期字符串: Thu, 15 Jan 2015, 9:56 AM 我将其转换为日期变量: Thu Jan 15 09:56:00 GMT+05:30 2015 使用: String pattern = "EEE, d MMM yyyy, hh:mm a"; try { date = new SimpleDateFormat(pattern).parse(getPref("refresh", getApplicationContext()));
Thu, 15 Jan 2015, 9:56 AM
我将其转换为日期变量:
Thu Jan 15 09:56:00 GMT+05:30 2015
使用:
String pattern = "EEE, d MMM yyyy, hh:mm a";
try {
date = new SimpleDateFormat(pattern).parse(getPref("refresh", getApplicationContext()));
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
现在,我有了以下函数,并将日期变量传递给以下函数:
public static int getDiffHour(Date first) {
int hoursBetween = Hours.hoursBetween(new LocalDate(first), new LocalDate()).getHours();
return hoursBetween;
}
它总是返回0。可能的原因是什么 请尝试以下代码:-
public static void main(String[] args) {
String dateStart = "01/14/2012 09:29:58";
String dateStop = "01/15/2012 10:31:48";
//HH converts hour in 24 hours format (0-23), day calculation
SimpleDateFormat format = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss");
Date d1 = null;
Date d2 = null;
try {
d1 = format.parse(dateStart);
d2 = format.parse(dateStop);
//in milliseconds
long diff = d2.getTime() - d1.getTime();
long diffSeconds = diff / 1000 % 60;
long diffMinutes = diff / (60 * 1000) % 60;
long diffHours = diff / (60 * 60 * 1000) % 24;
long diffDays = diff / (24 * 60 * 60 * 1000);
System.out.print(diffDays + " days, ");
System.out.print(diffHours + " hours, ");
System.out.print(diffMinutes + " minutes, ");
System.out.print(diffSeconds + " seconds.");
} catch (Exception e) {
e.printStackTrace();
}
}
有关更多信息,请参阅以下链接:-
像这样试试
int diff_hrs = getDiffHours(date,new Date());// pass your date object as startDate and pass current date as your endDate
public int getDiffHours(Date startDate, Date endDate){
Interval interval = new Interval(startDate.getTime(), endDate.getTime());
Period period = interval.toPeriod();
return period.getHours();
}
请检查此链接如果endDate是currentdate怎么办?它不允许我执行新的LocalDate().getTime。您可能会遇到问题,因为解析日期时使用了不同的格式,而不是
JodaTime的LocalDate
所使用的格式。所以我会坚持让你按照我的回答来解析它。就像一个符咒一样:)谢谢你,伙计!
int diff_hrs = getDiffHours(date,new Date());// pass your date object as startDate and pass current date as your endDate
public int getDiffHours(Date startDate, Date endDate){
Interval interval = new Interval(startDate.getTime(), endDate.getTime());
Period period = interval.toPeriod();
return period.getHours();
}