Java for循环中的if语句打印多次

我在2d数组中搜索3个数字，第三个数字不在数组中，当它向用户输出该数字不在数组中时，它会打印10次，我猜，因为for循环增加到10。如何使语句“8675不在数组中”只打印一次

public class MultiDimensionalArray {

public static void main(String[] args) {

    int[][] oned = {
            { 1115, 7307, 1004, 8820, 4322, 2286, 6183, 8455, 5569, 9930 },
            { 1155, 7749, 8582, 1180, 4463, 3107, 8838, 9842, 2308, 3453 },
            { 6229, 5449, 1967, 2501, 9610, 5600, 6996, 7375, 5629, 35 },
            { 6677, 2464, 5017, 5881, 639, 2772, 3465, 8718, 7747, 5621 },
            { 1646, 8533, 4250, 8119, 8163, 1236, 4433, 4093, 7834, 3037 },
            { 7069, 6522, 9604, 1609, 5725, 6255, 438, 274, 7978, 3358 },
            { 6631, 3401, 5975, 108, 3696, 2773, 1697, 9803, 7056, 4996 },
            { 7109, 4895, 5930, 7634, 7070, 5265, 7456, 5223, 9725, 368 },
            { 1201, 7776, 9000, 8654, 9635, 922, 2932, 4814, 1624, 1062 },
            { 7561, 6587, 7398, 4254, 5797, 7325, 4368, 5830, 8937, 5726 },
            { 7740, 8238, 7761, 6142, 4643, 7416, 2062, 5563, 1298, 7899 },
            { 1868, 6088, 3071, 7563, 7780, 2714, 7081, 2565, 3086, 766 },
            { 2284, 9931, 8664, 7248, 6768, 5657, 8404, 807, 7357, 2204 },
            { 9911, 6832, 8167, 546, 2709, 2046, 8465, 4171, 1841, 6106 },
            { 2123, 9005, 406, 6873, 3848, 4760, 2912, 1504, 9052, 270 },
            { 8700, 8182, 1153, 1154, 9288, 8227, 6165, 7257, 7908, 1769 },
            { 7355, 3880, 390, 1496, 6984, 7553, 981, 8049, 6948, 7312 },
            { 830, 4777, 5100, 897, 9941, 8513, 9318, 3146, 5298, 8452 },
            { 6678, 6535, 1471, 5225, 5513, 1912, 624, 8802, 5331, 4675 },
            { 4916, 2517, 4604, 4947, 9973, 9347, 9390, 8633, 60, 8983 },
            { 9977, 2505, 8436, 1285, 472, 568, 8696, 5198, 5630, 5087 },
            { 6287, 4834, 6184, 3761, 7922, 3163, 6836, 6621, 3338, 6575 },
            { 7105, 5863, 5113, 1346, 1223, 7733, 1323, 2301, 3021, 8612 },
            { 2976, 282, 271, 8111, 1320, 3441, 7129, 513, 4564, 7278 },
            { 3916, 7150, 9606, 8058, 7533, 8106, 539, 977, 32, 1074 },
            { 5859, 6361, 7489, 8347, 9441, 8281, 7728, 7944, 5272, 1598 },
            { 6078, 4624, 634, 9183, 7772, 6187, 3565, 4912, 2875, 8405 },
            { 1031, 1679, 8287, 689, 4855, 6386, 8616, 8608, 2842, 4986 },
            { 3321, 5150, 1410, 3159, 1328, 30, 191, 7133, 2797, 5334 },
            { 8610, 5512, 8141, 1398, 5918, 2641, 9014, 4475, 4590, 8672 } };

    // Is 8227 in the array?

    int number = 8227;
    for (int row = 0; row < 10; row++) {
        for (int column = 0; column < 30; column++) {
             if (oned[column][row] == number)
             {
                 System.out.println("8227 is in the array");
             }
        }
    }

// Is 9911 in the array?

    int check = 9911;
    for (int row = 0; row < 10; row++) {
        for (int column = 0; column < 30; column++) {
             if (oned[column][row] == check)
             {
                 System.out.println("9911 is in the array");
             }
        }
    }

// Is 8675 in the array?

    int look = 8675;
    for (int row = 0; row < 10; row++) {
        for (int column = 0; column < 30; column++) {
             if (oned[column][row] == look)
             {
                 System.out.println("8675 is in the array");
             } 
             else if (oned[column][row] != look)
             {
                 System.out.println("8675 is not in the array");
             }               
        }
    }
}
}

---

你的方式：

int look = 8675;
boolean found = false;
outer:
    for (int row = 0; row < 10; row++) {
        for (int column = 0; column < 30; column++) {
             found =(oned[column][row] == look);
             if(found){
                 break outer;
             }
         }
     }

 if(found){
       System.out.println("8675 is in the array");
 }else{
       System.out.println("8675 is not in the array");
 }    

您现在可以这样调用该函数：

boolean hasValue = searchInArray(oned, 8227);

该函数使用for循环迭代2d数组中的每个int数组。在for循环中，它迭代1d int数组的每个元素。如果元素与您搜索的元素相等，它将返回true。否则，它将在搜索整个二维数组后返回false

现在可以使用变量hasValue打印文本：

boolean hasValue = searchInArray(oned, 8227);
if(hasValue ){
   System.out.println("8227 is in the array");
}else{
   System.out.println("8227 is not in the array");
 }

像这样的事情：

   public void searchInt(int number){

    int[][] array= {
        {1115, 7307, 1004, 8820, 4322, 2286, 6183, 8455, 5569, 9930},....};

    for (int[] nmbres: array) {
      for (int num : nmbres) {
        if (number== num) {
          System.out.println(number +"is in the array");
        }
      }

    }
}

---

您需要在代码中添加两个中断来中断for循环

您只需要一个循环块来检查所有数字一位解释会使这个答案更好。@tobias_k当然；）我刚刚按下回车键提前：D@Conner没问题。

boolean hasValue = searchInArray(oned, 8227);
if(hasValue ){
   System.out.println("8227 is in the array");
}else{
   System.out.println("8227 is not in the array");
 }

   public void searchInt(int number){

    int[][] array= {
        {1115, 7307, 1004, 8820, 4322, 2286, 6183, 8455, 5569, 9930},....};

    for (int[] nmbres: array) {
      for (int num : nmbres) {
        if (number== num) {
          System.out.println(number +"is in the array");
        }
      }

    }
}