Java 我正在编写一个程序，为twitch流媒体应用程序的eq生成随机比赛/等级

好的，所以我想做的是得到一个程序，可以从旧游戏everquest中创建一个随机的职业/种族组合。我想确保课程考虑到了班级比赛的限制。所以我做了一堆字符串，我似乎无法得到一个基于随机比赛的随机类

所以它应该是这样工作的 程序选择一个种族，并随机选择一个只有该种族才能玩的类。因此，所有的字符串。请任何帮助将不胜感激，这样我就可以进入这个项目的第二阶段

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还有一个旁注：如何使按钮保持在顶部，并在其下方显示弹出的文本？

如果我理解正确，您可以使用2d数组。例如

import javax.swing.*;
import java.awt.*;
import java.awt.event.*;

public class ClassNameGenerator {

    private static JLabel label;
    private static JLabel label2;

    public static void main (String[] args){

        JFrame frame = new JFrame("EQStreamTool");
        frame.setVisible(true);
        frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
        frame.setSize(400,350);
        JPanel panel = new JPanel (new FlowLayout(FlowLayout.CENTER, 20, 5));
        for (int i =0; i <10; i++) {
        }
        frame.add(panel);
        JButton button = new JButton("Generate Class/Race");
        panel.add(button);
        label = new JLabel();
        panel.add(label);
        button.addActionListener(new Action());
        label2 = new JLabel();
        panel.add(label2);
        button.addActionListener(new Action());
    }

    static class Action implements ActionListener{

        public void actionPerformed (ActionEvent e){
            String[] races = {"Barbarian", "Dark Elf", "Dwarf", "Erudite", "Gnome", "Ogre", "Troll", "Wood Elf", "Half Elf", "Halfling", "High Elf", "Human", "Iksar"};
            String[] classes = {"Bard", "Druid", "Cleric", "Enchanter", "Magician", "Monk", "Necromancer", "Paladin", "Ranger", "Rogue", "Shadowknight", "Warrior", "wizard"};
            String[] barbClasses = {"Rogue", "Shaman", "Warrior"};
            String[] delfClasses = {"Cleric", "Enchanter", "Magician", "Necromancer", "Rogue", "Shadowknight", "Warrior", "Wizard"};
            String[] dwarfClasses = {"Rogue", "Paladin", "Warrior"};
            String[] eruditeClasses = {"Cleric", "Enchanter", "Magician", "Necromancer", "Paladin", "Shadowknight", "Wizard"};
            String[] gnomeClasses = {"Cleric", "Enchanter", "Magician", "Necromancer", "Paladin", "Rogue", "Shadowknight", "Warrior", "Wizard"};
            String[] halfelfClasses = {"Bard", "Druid", "Paladin", "Ranger", "Rogue", "Shadowknight", "Warrior", "Wizard"};
            String[] halflingClasses = {"Rogue", "Cleric", "Warrior", "Druid", "Paladin", "Ranger"};
            String[] highelfClasses = {"Cleric", "Enchanter", "Magician", "Paladin", "Wizard"};
            String[] humanClasses = {"Rogue", "Bard", "Warrior", "Cleric", "Druid", "Enchanter", "Magician", "Monk", "Necromancer", "Paladin", "Ranger", "Shadowknight", "Wizard"};
            String[] iksarClasses = {"Monk", "Shaman", "Warrior", "Necromancer", "Shadowknight"};
            String[] ogreClasses = {"Shadowknight", "Shaman", "Warrior"};
            String[] trollClasses = {"Shadwknight", "Shaman", "Warrior"};
            String[] woodelfClasses = {"Bard", "Druid", "Ranger", "Rogue", "Warrior"};

            int random = (int) (Math.random()*races.length);
            int random2 = (int) (Math.random()*classes.length);

            label.setText("Your Race is: "  + races[random]); 
            label2.setText("Your Class is: " + classes[random2]);
        }
    }
}

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在一个数组中，您可以指定它拥有的所有种族。因此，当您随机选择一个类时，您可以选择一个相关的随机种族

我建议您解决的第一个问题是使用Enum。我已经创建了样本枚举类，类似于

String[][] raceAndClasses={{"Barbarian","Dark Elf","Dwarf"},{"Bard", "Druid", "Cleric"},{"Rogue", "Shaman", "Warrior"}};

}

现在，从上述代码中删除种族和类的字符串数组。相反，通过调用返回所有枚举数组的枚举类上的getEnumConstants，选择一个枚举作为您的比赛，而不是您一直在做的字符串，在您的情况下，所有比赛都具有有效的类。现在在这个枚举中调用get方法，它将返回您为该竞赛枚举输入的任何可能的类。您可以随机选择该类，因为它是字符串数组，并从中向前移动

上述课程的相关代码如下所示：

public enum RestrictedComboEnum {

Barbarian(new String[] { "bard", "druid" }), 
Dwarf(new String[] { "hello","trial" });

RestrictedComboEnum(String[] classes) {
    this.classes = classes;
}

String[] classes;

public String[] getClasses() {
    return this.classes;
}

在上面的例子中，当应用程序选择野蛮人作为种族时，可能的选择是吟游诗人或德鲁伊，而对于矮人来说则是hello和trial。因此，请根据需要填写枚举

从您的评论来看，您似乎对Java非常陌生，所以出于学习目的，您可以尝试使用Enum，因为您需要它们。

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当代码增长时，这将使您的生活比使用2d数组容易得多。

现在，它还会弹出一个随机种族和类，但它没有考虑到您不能将某些类作为特定种族。这就是我制作其他字符串的原因。你可以使用2d数组。我还应该说我对java知之甚少。我花了10个小时完成这项工作，我从几个不同的网站上获得了它。Java编码有点难，这可能会有所帮助，现在查看一下我将如何设置它，thanksi将给出更详细的示例@JeremyZavalayour right im new，very new。但我将研究更多的枚举和2d数组，只是为了熟悉它们。这就解决了它。非常感谢你。现在，如果我可以格式化jfram将东西放入框中的方式，那么在面板上添加标签时，需要提供标签的位置。查一查，这并不难。就我个人而言，我更喜欢网格包布局，这样我就可以在我想要的地方添加任何东西。

        RestrictedComboEnum[] combinations = RestrictedComboEnum.class
                .getEnumConstants();

        int random = (int) (Math.random() * combinations.length);

        RestrictedComboEnum selectedCombo = combinations[random];

        int random2 = (int) (Math.random() * selectedCombo.getClasses().length);

        label.setText("Your Race is: " + combinations[random]);
        label2.setText("Your Class is: "+ selectedCombo.getClasses()[random2]);