解析数据org.json.JSONException时出现另一个错误：Value<；！无法将java.lang.String类型的DOCTYPE转换为JSONObject

我对这件事非常生气。我可以使用相同的代码（除了INSERT into命令）写入数据库，但这不起作用

PHP:

$id = $_POST['id'];
//$id = '000000000002';
$uri = $_POST['uri'];
//$uri='sdfgdsfg';
try {

    $stmt = $conn->prepare("UPDATE USERS SET PHOTO=? WHERE ID=?");
    $stmt->execute(array($uri, $id));
    $response["success"] = 1;
    } catch(PDOException $e) {
    echo 'ERROR: ' . $e->getMessage();
    $response["success"] = 0;
}

echo json_encode($response);

try {
                        paramsC = new ArrayList<NameValuePair>();
                        paramsC.add(new BasicNameValuePair("id", userid));
                        paramsC.add(new BasicNameValuePair("uri", "hello"));

                        JSONParser jsonParser; jsonParser = new JSONParser();
                        JSONObject json = jsonParser.makeHttpRequest(set_profile_photo_uri, "POST", paramsC);

                        try {
                            int success = json.getInt("success"); //error points to this line
                            if (success == 1) {
                                // successfully updated
                                Log.d("SIGNUP", "success");
                            } else {
                                Log.d("SIGNUP", "fail");
                            }
                        }catch(JSONException e){
                            //Log.e("log_tag", "Error parsing data "+e.toString());
                            //Log.e("log_tag", "Failed data was:\n");
                        }
                    } catch (Exception e) {
                        e.printStackTrace();
                    }

try {
        $stmt = $conn->prepare("INSERT INTO USERS (USERNAME, PASSWORD, NAME, EMAIL, GENDER, DATEOFREG_PHONE, DATEOFREG_SV) VALUES
        (:username, :password, :name, :email, :gender, :dateofreg_phone, :dateofreg_sv)");
            $query_params = array( 
                ':username' => $username,
                ':password' => $password,
                ':name' => $name,
                ':email' => $email,
                ':gender' => $gender,
                ':dateofreg_phone' => $dateofreg_phone,
                ':dateofreg_sv' => $dateofreg_sv
            );  
        $stmt->execute($query_params); 
        $response["success"] = 1;
        } catch(PDOException $e) {
        echo 'ERROR: ' . $e->getMessage();
        $response["success"] = 0;
    }

    echo json_encode($response);

JAVA:

$id = $_POST['id'];
//$id = '000000000002';
$uri = $_POST['uri'];
//$uri='sdfgdsfg';
try {

    $stmt = $conn->prepare("UPDATE USERS SET PHOTO=? WHERE ID=?");
    $stmt->execute(array($uri, $id));
    $response["success"] = 1;
    } catch(PDOException $e) {
    echo 'ERROR: ' . $e->getMessage();
    $response["success"] = 0;
}

echo json_encode($response);

try {
                        paramsC = new ArrayList<NameValuePair>();
                        paramsC.add(new BasicNameValuePair("id", userid));
                        paramsC.add(new BasicNameValuePair("uri", "hello"));

                        JSONParser jsonParser; jsonParser = new JSONParser();
                        JSONObject json = jsonParser.makeHttpRequest(set_profile_photo_uri, "POST", paramsC);

                        try {
                            int success = json.getInt("success"); //error points to this line
                            if (success == 1) {
                                // successfully updated
                                Log.d("SIGNUP", "success");
                            } else {
                                Log.d("SIGNUP", "fail");
                            }
                        }catch(JSONException e){
                            //Log.e("log_tag", "Error parsing data "+e.toString());
                            //Log.e("log_tag", "Failed data was:\n");
                        }
                    } catch (Exception e) {
                        e.printStackTrace();
                    }

try {
        $stmt = $conn->prepare("INSERT INTO USERS (USERNAME, PASSWORD, NAME, EMAIL, GENDER, DATEOFREG_PHONE, DATEOFREG_SV) VALUES
        (:username, :password, :name, :email, :gender, :dateofreg_phone, :dateofreg_sv)");
            $query_params = array( 
                ':username' => $username,
                ':password' => $password,
                ':name' => $name,
                ':email' => $email,
                ':gender' => $gender,
                ':dateofreg_phone' => $dateofreg_phone,
                ':dateofreg_sv' => $dateofreg_sv
            );  
        $stmt->execute($query_params); 
        $response["success"] = 1;
        } catch(PDOException $e) {
        echo 'ERROR: ' . $e->getMessage();
        $response["success"] = 0;
    }

    echo json_encode($response);

---

当我将PHP代码输入浏览器时，它可以正常工作。

从注释中回答以结束此问题：确保您将查询发送到正确的URL。

我将查看HTTP响应包含的内容。看起来您正在尝试将HTML解析为JSON。令人惊讶的是，HTML不是JSON。我的代码中根本没有HTML。您的服务器使用HTML页面而不是JSON进行响应。只要看看你的错误信息。。。