JAVA初学者：IF语句没有按预期工作-应该在什么时候调用代码体？

几周新的编码！我被指派制作一个方法，用户可以在上午9点到下午5点之间预约。我制作了一个大小为8的布尔数组，名为availability（0=9am，1=10am，2=11am，3=12am…8=17pm）。True表示时间可用，false表示时间不可用

该方法具有描述、小时和持续时间等参数。我的方法是在选定的时间预约

但是，比方说，我在上午9点预约了一个时间为1小时的约会。-->0现在为false。 接下来，我预订了上午11点的预约，预约时间为1小时。-->2现在是假的。 然后我在上午10点预约，预约时间为2小时。-->1（上午10点）应该保持不变，因为如果下一个小时（上午11点）已经预订，用户应该不能预订2小时，对吗

我试图在代码中实现这一点，但没有成功。我的代码仍然预定上午10点，并将插槽设置为false！从我收集的信息来看，我认为问题在于第96行，即检查持续时间内是否有任何时段为假的if语句

我尝试的是在代码开始时将布尔变量设置为true，如果if语句发现了false可用性，则将check变量设置为false。这将停止下一个代码块，其中IF语句检查“check”是否为true（如果持续时间内的所有插槽都为true，因为它没有设置为false）

我一直试图在不寻求外界支持的情况下找到问题并加以解决，但现在已经到了这样的地步：盯着电脑屏幕不是一种很好的学习方式，有人能指出一个我可以学习的问题是最好的选择

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如果我得到回复，谢谢！：）如果这篇文章有什么不允许的地方，对不起，第一次

您错过了结束括号，而不是整天循环检查它们是否已预订，而是只检查第一个，然后进行预约。它的工作，因为10显然是免费的-程序将不会检查11然后，即使你愿意

for (int i = booleanHour; i < booleanHour + duration; i++) { 
    if (availability[i] == false) {
      System.out.println("This has hour been booked, please choose another time. We open at 9am, and close at 5pm.");
      System.out.println(check);
      check = false;
      return false;
    } // this is the end of IF not FOR - only first element was checked!
    if (check) { // yup it's true because 10 is free...
      for (int b = booleanHour; b < booleanHour + duration; b++) {
        availability[b] = false; // here we are making all hours booked no matter they are booked or not already
        Appointment appoint = new Appointment(desc, duration, b + 9);
        schedule.put(b + 9, appoint);
      }
      return true;
    }
  } // and finally this is the end of FOR but it's too late

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您错过了结束括号，而不是整天循环检查它们是否已预订，而是只检查第一个，然后预约。它的工作，因为10显然是免费的-程序将不会检查11然后，即使你愿意

for (int i = booleanHour; i < booleanHour + duration; i++) { 
    if (availability[i] == false) {
      System.out.println("This has hour been booked, please choose another time. We open at 9am, and close at 5pm.");
      System.out.println(check);
      check = false;
      return false;
    } // this is the end of IF not FOR - only first element was checked!
    if (check) { // yup it's true because 10 is free...
      for (int b = booleanHour; b < booleanHour + duration; b++) {
        availability[b] = false; // here we are making all hours booked no matter they are booked or not already
        Appointment appoint = new Appointment(desc, duration, b + 9);
        schedule.put(b + 9, appoint);
      }
      return true;
    }
  } // and finally this is the end of FOR but it's too late

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啊，谢谢你！这真的有助于理解我的逻辑缺陷和我处理问题的方法！（确实需要记住return语句可能具有的效果）。祝你今天愉快。啊，谢谢你！这真的有助于理解我的逻辑缺陷和我处理问题的方法！（确实需要记住return语句可能具有的效果）。祝你有美好的一天。

for (int i = booleanHour; i < booleanHour + duration; i++) { 
    if (availability[i] == false) {
      System.out.println("This has hour been booked, please choose another time. We open at 9am, and close at 5pm.");
      System.out.println(check);
      check = false;
      return false;
    } // this is the end of IF not FOR - only first element was checked!
    if (check) { // yup it's true because 10 is free...
      for (int b = booleanHour; b < booleanHour + duration; b++) {
        availability[b] = false; // here we are making all hours booked no matter they are booked or not already
        Appointment appoint = new Appointment(desc, duration, b + 9);
        schedule.put(b + 9, appoint);
      }
      return true;
    }
  } // and finally this is the end of FOR but it's too late

public boolean makeAppointment(String desc, int duration, int hour) {

  //...

  for (int i = booleanHour; i < booleanHour + duration; i++) { 
    if (!availability[i]) {
      System.out.println("This has hour been booked, please choose another time. We open at 9am, and close at 5pm.");
      return false;
    }
  } 

  for (int b = booleanHour; b < booleanHour + duration; b++) {
      availability[b] = false; // here we are making all hours booked no matter they are booked or not already
      Appointment appoint = new Appointment(desc, duration, b + 9);
      schedule.put(b + 9, appoint);
  }

  return true;

  //...

}