Java首次尝试使用简单计算器(发生了什么事?)
java主类Java首次尝试使用简单计算器(发生了什么事?),java,console,calculator,Java,Console,Calculator,java主类 package com.indie; import java.util.InputMismatchException; import java.util.Scanner; import static com.indie.Operations.*; public class Main { private static double Number1; private static double Number2; private static double
package com.indie;
import java.util.InputMismatchException;
import java.util.Scanner;
import static com.indie.Operations.*;
public class Main {
private static double Number1;
private static double Number2;
private static double Total;
private static String Symbol;
private static boolean noError;
private static boolean exceptioncaught;
public static void main(String[] args) throws InterruptedException{
noError = false;
while (!noError) {
exceptioncaught = false;
while (!exceptioncaught) {
Scanner scanner = new Scanner(System.in);
System.out.println("Enter your number:");
try {
Number1 = scanner.nextDouble();
} catch (InputMismatchException ex) {
System.out.println();
System.out.println("TypeERROR: You didn't input a vaild number!");
exceptioncaught = true;
System.out.println();
Thread.sleep(3000);
break;
}
System.out.println("What do you want to do:");
Symbol = scanner.next();
if (!Symbol.contains("+") && !Symbol.contains("-") && !Symbol.contains("*") && !Symbol.contains("x") && !Symbol.contains("/") && !Symbol.contains("÷")) {
System.out.println();
System.out.println("TypeERROR: You didn't input a valid symbol!");
exceptioncaught = true;
System.out.println();
Thread.sleep(3000);
break;
}
System.out.println("Enter your second number:");
try {
Number1 = scanner.nextDouble();
} catch (InputMismatchException ex) {
System.out.println();
System.out.println("TypeERROR: You didn't input a vaild number!");
exceptioncaught = true;
System.out.println();
Thread.sleep(3000);
break;
}
System.out.println();
if (Symbol.contains("+")) {
Total = Add(Number1, Number2);
noError = true;
break;
} else if (Symbol.contains("-")) {
Total = Subtract(Number1, Number2);
noError = true;
break;
} else if (Symbol.contains("*") || Symbol.contains("x")) {
Total = Multiply(Number1, Number2);
noError = true;
break;
} else if (Symbol.contains("/") || Symbol.contains("÷")) {
Total = Divide(Number1, Number2);
noError = true;
break;
}
}
}
System.out.println(String.valueOf(Number1)
+Symbol+String.valueOf(Number2)
+"="+String.valueOf(Total));
}
}
Operations.java第二类
package com.indie;
public class Operations {
public static double Add(double x, double y) { return x+y; }
public static double Subtract(double x, double y){ return x-y; }
public static double Multiply(double x, double y){ return x*y; }
public static double Divide(double x, double y){ return x/y; }
}
有办法解决吗?它是如何以2.0+20.0=2.0结束的?请帮忙。
有没有办法阻止它产生这种结果
其他结果:
结果1:
输入您的号码:
二,
您想做什么:
+五,
输入您的第二个号码:
56
56.0+50.0=56.0
结果2:
输入您的号码:
一,
您想做什么:
+一,
输入您的第二个号码:
一,
1.0+10.0=1.0
在代码的这一部分,您应该更改以下内容:
...
System.out.println("Enter your second number:");
try {
Number1 = scanner.nextDouble();
}
...
为此:
...
System.out.println("Enter your second number:");
try {
Number2 = scanner.nextDouble();
}
...
您永远不会更改代码中数字2的值。有第二双眼睛很好 在你的代码中,你从不给数字2赋值
System.out.println("Enter your second number:");
try {
Number2 = scanner.nextDouble();
你应该花些时间调试你的家庭作业。稍微挣扎一下没关系。输入您的号码:后跟Number1=scanner.nextDouble;然后输入第二个数字:后面是Number1=scanner.nextDouble;这应该是一个非常明显的打字错误,你应该能够发现你自己。虽然它可能不是唯一的一个。我知道这与问题无关,但Java工程师使用小写变量namescode review stack exchange可能会对您有所帮助,非常感谢,我已经改变了这一点,但如果符号变量包含实际输入运算符后的数字,我似乎仍然会得到奇怪的结果。。。你需要限制你的输入,只允许输入符号而不是数字字符串