Java ListView返回相同的数据

我在应用程序中使用Parse进行了一次迷你聊天。我似乎遇到的唯一问题是当我写两次消息时：

正如你在这两张照片中所看到的，这将使两个聊天帖子显示相同的消息。我在想我可能做错了什么？以下是我认为涉及的代码：

MainActivity.java

public void onClick(View v){

    TimelineBaseAdapter myAdapter = new TimelineBaseAdapter(context, myList);

    lv = (ListView)findViewById(R.id.timelineListView);
    lv.setAdapter(new TimelineBaseAdapter(context, myList));

    EditText et = (EditText)findViewById(R.id.editText);

    String post = et.getText().toString();

    ParseObject po = new ParseObject("Posts");
    po.put("Comments", post);
    po.saveInBackground();

    this.retrievedPost = po.getString("Comments");

    getDataInList();

    myAdapter.notifyDataSetChanged();

}

private void getDataInList(){

   TimelineListData tld = new TimelineListData();
   tld.setPost(retrievedPost);

   myList.add(tld);

}

}

TimelineBaseAdapter.java

public class TimelineBaseAdapter extends BaseAdapter {

ArrayList<TimelineListData> myList = new ArrayList<>();
LayoutInflater inflater;
Context context;

public TimelineBaseAdapter(Context context, ArrayList myList){
    this.myList = myList;
    this.context = context;

    inflater = LayoutInflater.from(this.context);

}

@Override
public View getView(int position, View convertView, ViewGroup parent) {

    TimelineListData tld2 = getItem(position);

    String settingPost = tld2.post;

    MyViewHolder myViewHolder;

    if (convertView == null){

        convertView = inflater.inflate(R.layout.post, null);
        myViewHolder = new MyViewHolder();
        myViewHolder.chatpost = (TextView)convertView.findViewById(R.id.chatpost);
        convertView.setTag(myViewHolder);

    }

    else {

        myViewHolder = (MyViewHolder)convertView.getTag();

    }

    myViewHolder.chatpost.setText(settingPost);

    return convertView;

}

private static class MyViewHolder{
    TextView chatpost;

}
}

我们将非常感谢所有的帮助/建议。提前谢谢

在getView中，更改

 TimelineListData tld2 = new TimelineListData();

与

从ViewHolder图案的角度来看，以下行

 myViewHolder.chatpost = (TextView)convertView.findViewById(R.id.chatpost);

进入警卫室：

  if (convertView == null)

之后

myViewHolder = new MyViewHolder();

---

您正在为listview设置两个不同的适配器

TimelineBaseAdapter myAdapter = new TimelineBaseAdapter(context, myList);

改变这个

lv.setAdapter(new TimelineBaseAdapter(context, myList));

到

---

感谢您的帮助，但问题是TimelineListData.java中的字符串post是静态的。当我删除static时，它们不再重复相同的数据。

您能将代码减少到解决问题所需的最小值吗？这将使人们更容易发现问题并帮助你。我做了你建议的更改，看起来是这样的：但我似乎仍然得到了相同的结果

TimelineBaseAdapter myAdapter = new TimelineBaseAdapter(context, myList);

lv.setAdapter(new TimelineBaseAdapter(context, myList));

lv.setAdapter(myAdapter);