Java g、 在错误的位置？程序每次都关闭

你好，我想做一个测验应用程序，到目前为止我已经完成了

import java.util.Scanner;
public class Brotcrunsher {
  public static void main(String args[]){
    Scanner scan = new Scanner(System.in);

    System.out.println ("Hallo");
    System.out.println ("Welcome to the test");
    System.out.println ("If you are the admin of the test and would like to edit it please type the password now");
    System.out.println ("Otherwhise please say 'begin' to start");
    String c = scan.nextLine();
    if (c.equals ("edit")) {
      System.out.println ("Editor mode coming soon, please edit via code"); 
    } 
    else {
      if (c.equals ("begin")) {  
      } // end of if
      System.out.println ("A flag has more then 1 color right?");
      String a = scan.nextLine();
      if (a.equals("ja")) {
        System.out.println ("You arent dumb, nice.");
        System.out.println ("What is 352 + 223");
        int b = scan.nextInt(); 
        if (b == 575) {
          System.out.println ("That is correct nice");
          System.out.println ("You passed the basic questions, going to be tricky now");
          System.out.println ("What was the date when Donald Trump became president");
          String g = scan.nextLine();
          System.out.println ("A = 19.01 B = 20.01 C = 21.01 D= 22.01");
          if (g.equals ("B")){
            System.out.println ("You are right, lets move on.");
          } // end of if
          else {
            System.out.println ("That is wrong. Better luck next time");
          } // end of if-else  
        }  
        else {
          System.out.println("That isn't right, you failed.");
          System.out.println ("If you'd like to repeat the test, go ahead and do so");
        }  
      }
      else {
        System.out.println ("You arentn a genie");
      } 
    }
  } 
}

所以我的问题是，我需要把字符串g=scan.NextLine放在哪里才能让它工作？我没有得到任何编译错误，只是控制台出口的。

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我试着把它放在IF语句中的beggining和其他一些位置，但它只是停了下来。请提供帮助。

如果在运行应用程序时控制台关闭，则可能会出现运行时错误。尝试从已打开的命令外壳运行程序以查看错误

---

这应该是一个注释，但我没有足够的rep 0:）

如果在运行应用程序时控制台关闭，则可能会出现运行时错误。尝试从已打开的命令外壳运行程序以查看错误

---

这应该是一个注释，但我没有足够的rep 0:）

问题是当您到达代码的关键部分时，扫描仪不是空的。您需要清除缓冲区，例如：

public class Brotcrunsher {
      public static void main(String args[]){
        Scanner scan = new Scanner(System.in);

        System.out.println ("Hallo");
        System.out.println ("Welcome to the test");
        System.out.println ("If you are the admin of the test and would like to edit it please type the password now");
        System.out.println ("Otherwhise please say 'begin' to start");
        String c = scan.nextLine();
        if (c.equals ("edit")) {
          System.out.println ("Editor mode coming soon, please edit via code"); 
        } 
        else {
          if (c.equals ("begin")) {  
          } // end of if
          System.out.println ("A flag has more then 1 color right?");
          String a = scan.nextLine();
          if (a.equals("ja")) {
            System.out.println ("You arent dumb, nice.");
            System.out.println ("What is 352 + 223");
            int b = scan.nextInt(); 
            if (b == 575) {
              System.out.println ("That is correct nice");
              System.out.println ("You passed the basic questions, going to be tricky now");
              System.out.println ("What was the date when Donald Trump became president");
              System.out.println ("A = 19.01 B = 20.01 C = 21.01 D= 22.01");
              scan.nextLine();     // FEED the new-line character
              String g = scan.nextLine();
              if (g.equals ("B")){
                System.out.println ("You are right, lets move on.");
              } // end of if
              else {
                System.out.println ("That is wrong. Better luck next time");
              } // end of if-else  
            }  
            else {
              System.out.println("That isn't right, you failed.");
              System.out.println ("If you'd like to repeat the test, go ahead and do so");
            }  
          }
          else {
            System.out.println ("You arentn a genie");
          } 
        }
      } 
    }

更多详情：

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问题在于，当您到达代码的关键部分时，扫描仪不是空的。您需要清除缓冲区，例如：

public class Brotcrunsher {
      public static void main(String args[]){
        Scanner scan = new Scanner(System.in);

        System.out.println ("Hallo");
        System.out.println ("Welcome to the test");
        System.out.println ("If you are the admin of the test and would like to edit it please type the password now");
        System.out.println ("Otherwhise please say 'begin' to start");
        String c = scan.nextLine();
        if (c.equals ("edit")) {
          System.out.println ("Editor mode coming soon, please edit via code"); 
        } 
        else {
          if (c.equals ("begin")) {  
          } // end of if
          System.out.println ("A flag has more then 1 color right?");
          String a = scan.nextLine();
          if (a.equals("ja")) {
            System.out.println ("You arent dumb, nice.");
            System.out.println ("What is 352 + 223");
            int b = scan.nextInt(); 
            if (b == 575) {
              System.out.println ("That is correct nice");
              System.out.println ("You passed the basic questions, going to be tricky now");
              System.out.println ("What was the date when Donald Trump became president");
              System.out.println ("A = 19.01 B = 20.01 C = 21.01 D= 22.01");
              scan.nextLine();     // FEED the new-line character
              String g = scan.nextLine();
              if (g.equals ("B")){
                System.out.println ("You are right, lets move on.");
              } // end of if
              else {
                System.out.println ("That is wrong. Better luck next time");
              } // end of if-else  
            }  
            else {
              System.out.println("That isn't right, you failed.");
              System.out.println ("If you'd like to repeat the test, go ahead and do so");
            }  
          }
          else {
            System.out.println ("You arentn a genie");
          } 
        }
      } 
    }

更多详情：

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我尝试了您的代码，最后一次扫描。nextLine（）似乎被跳过。看看这篇文章。

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调用的位置不是问题。

我尝试了您的代码，最后一次扫描。nextLine（）似乎被跳过。看看这篇文章。

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您呼叫的位置不是问题。

我认为代码System.out.println（“A=19.01 B=20.01 C=21.01 D=22.01”）；应该在字符串g=scan.nextLine（）前面；因为您需要首先将选项提供给用户，然后用户将做出选择

我认为代码System.out.println（“A=19.01b=20.01c=21.01d=22.01”）；应该在字符串g=scan.nextLine（）前面；因为您需要首先将选项提供给用户，然后用户将做出选择

就像它不是关闭而是暂停。。。当我按下一个键时，它会关闭。然后它可能正在等待你的输入。当你的输入被给出（按下一个键）时，程序仍可能由于运行时错误而终止。试着从命令行运行应用程序：比如它没有关闭，但是它暂停了。。。当我按下一个键时，它会关闭。然后它可能正在等待你的输入。当你的输入被给出（按下一个键）时，程序仍可能由于运行时错误而终止。尝试从命令行运行应用程序：接受答案表示相同：）接受答案表示相同：）