Java 按第二个字对字符串数组排序

我有以下数据

1. John Smith
2. Tom Cruise
3. Chuck Norris
4. Bill Gates
5. Steve Jobs

如您所见，数据采用特定格式，

[ID]。[Firstname][Lastname]

。是否有一种方法可以按

Firstname

对该数组进行排序

输出应如下所示：

4. Bill Gates
3. Chuck Norris
1. John Smith
5. Steve Jobs
2. Tom Cruise

---

您可以提供自定义比较器，以便按名字进行排序

    List<String> data = Arrays.asList("1. John Smith", "2. Tom Cruise", "3. Chuck Norris", "4. Bill Gates", "5. Steve Jobs");
    Comparator<String> c = (s1, s2) -> s1.split("\\s+")[1].compareTo(s2.split("\\s+")[1]);
    List<String> sorted = data.stream().sorted(c).collect(Collectors.toList());
    System.out.println(sorted);

或者干脆

    Comparator<String> com = Comparator.comparing(s -> s.split("\\s+")[1]);

    Comparator<String> old = new Comparator<String>() {
        @Override
        public int compare(String s1, String s2) {
            return s1.split("\\s+")[1].compareTo(s2.split("\\s+")[1]);
        }
    };

---

您将需要一个自定义比较器

String[] names = new String[]{"1. John Smith","2. Tom Cruise","3. Chuck Norris","4. Bill Gates","5. Steve Jobs"};
List<String> nameList = Arrays.asList(names);
Collections.sort(nameList, new Comparator<String>() {

    @Override
    public int compare(String arg0, String arg1) {
        String firstName0 = arg0.split(". ")[1].split(" ")[0];
        String firstName1 = arg1.split(". ")[1].split(" ")[0];
        return firstName0.compareTo(firstName1);
    }
});

---

您可以使用lambda通过自己的比较标准

String[] names = {"1. John Smith", "2. Tom Cruise", "3. Chuck Norris", "4. Bill Gates", "5. Steve Jobs"};

ArrayList<String> namesList = new ArrayList<>();
for(int i=0; i<names.length; i++) {
    namesList.add(names[i]);
}

Collections.sort(namesList, (name1, name2) -> name1.split(" ")[1].compareTo(name2.split(" ")[1]));

for(String name : namesList) {
    System.out.println(name);
}

---

“有没有办法按名字对数组排序？”-是的，您可以使用自定义的

比较器
类。到目前为止你都做了些什么？没有什么，因为我不是一个专业人士，即使我的问题结构良好，而且问题本身非常简单，但留下不赞成票也不是很好。如果你访问并阅读，你将了解这里评估问题的规则。希望它以不同的方式工作并不能使它成为现实。@JimGarrison我在发布这篇文章之前已经访问过该页面，所有内容都是按照规则发布的，并且结构、格式、简单、输入和输出都很整洁。停止对社区的辱骂和对快乐的贬低——你没有表现出任何努力。你的问题是“有个问题，给我写代码”。那是离题的。
String[] names = new String[]{"1. John Smith","2. Tom Cruise","3. Chuck Norris","4. Bill Gates","5. Steve Jobs"};
List<String> nameList = Arrays.asList(names);
Collections.sort(nameList, new Comparator<String>() {

    @Override
    public int compare(String arg0, String arg1) {
        String firstName0 = arg0.split(". ")[1].split(" ")[0];
        String firstName1 = arg1.split(". ")[1].split(" ")[0];
        return firstName0.compareTo(firstName1);
    }
});

[4. Bill Gates, 3. Chuck Norris, 1. John Smith, 5. Steve Jobs, 2. Tom Cruise]

String[] names = {"1. John Smith", "2. Tom Cruise", "3. Chuck Norris", "4. Bill Gates", "5. Steve Jobs"};

ArrayList<String> namesList = new ArrayList<>();
for(int i=0; i<names.length; i++) {
    namesList.add(names[i]);
}

Collections.sort(namesList, (name1, name2) -> name1.split(" ")[1].compareTo(name2.split(" ")[1]));

for(String name : namesList) {
    System.out.println(name);
}

4. Bill Gates
3. Chuck Norris
1. John Smith
5. Steve Jobs
2. Tom Cruise