Java 如何在二维数组中获取值 公共级A6{ 公共静态void main（字符串[]args）{ //字符串personInfo[][]=新字符串[][]{ 字符串personInfo[][]={ {“安德森”，“瓦莱乔”，“1125”}， {“Giorgi”，“Tevzadze”，“1125”}， {“威尔”，“樱桃”，“1225”}， {“威尔”、“Iams”、“12245”}， {“勒布朗”，“詹姆斯”，“6025”}， {“凯文”，“爱”，“2525”}， {“Kyrie”，“Livings”，“454”}， {“Kyrie”、“Botti”、“4544”}， {“克里斯”，“摩尔”，“425”}， {“Mot”，“Daniel”，“125”}， {“维克多”、“穆勒”、“145”}， {“Kiamran”，“Chris”，“1405”}， {“Zenia”，“Vaitehovic”，“1025”}， {“Marija”，“Grabauskaite”，“1471”}， {“Milda”，“Grabauskaite”，“1000”}， {“迪翁”，“侍者”，“625”}， {“迪翁”、“马尔堡”、“6250”} }; System.out.println（“列表中的人：”）； for（int i=0；i

我开始做新的自我控制练习。这里我有一个二维字符串数组，它保存着这些信息{“姓名”、“姓氏”、“薪水”}.我已经做了一部分练习，计算有多少人拥有我在命令行中输入的姓名。现在我需要编写一个代码，例如：我进入命令行Anderson Varejao并希望得到结果1125。换句话说，我输入姓名，并希望从personInfo字符串数组中获得某个人的工资。H我怎样才能拿到个人的薪水？

for（int I=0；Ipublic class A6{

    public static void main(String[] args){
        //String personInfo[][]=new String[][] { 
        String personInfo[][]={
                {"Anderson",  "Varejao",     "1125"},
                {"Giorgi",  "Tevzadze",      "1125"},
                {"Will",      "Cherry",      "1225"},
                {"Will",      "Iams",       "12245"},
                {"Lebron",    "James",       "6025"},
                {"Kevin",     "Love",        "2525"},
                {"Kyrie",     "Livings",      "454"},
                {"Kyrie",     "Botti",       "4544"},
                {"Chris",     "Mauer",        "425"},
                {"Mot",       "Daniel",       "125"},
                {"Viktor",    "Muller",       "145"},
                {"Kiamran",   "Chris",       "1405"},
                {"Zenia",     "Vaitehovic",  "1025"},
                {"Marija",    "Grabauskaite","1471"},
                {"Milda",    "Grabauskaite", "1000"},
                {"Dion",      "Waiters",     "625" },
                {"Dion",      "Malborg",    "6250" }
        };


        System.out.println("Peoples on the list:");
        for(int i = 0; i < personInfo.length; i++) {

            for(int j = 0; j < personInfo[i].length; j++) {
                System.out.print(" ");
                System.out.print(personInfo[i][j]);
            }

            System.out.println();
        }
        System.out.println("----------------------");

        //---------v XXX  - how many people have the first name XXX----------------

        String b = "v";

        if(args[0].equals(b))

        {

            System.out.println("Persons with entered name:");

            for(int i = 0; i < personInfo.length; i++) {

                for(int j = 0; j < personInfo[i].length; j++) {

                    if(personInfo[i][j].equals(args[1]))
                    {
                        System.out.println(args[1]);
                    }
                }
            }
            System.out.println();

        }
        //------vp XXX YYY - what is the salary of the person XXX YYY------
    }
}

if（personInfo[i][0].等于（args[1]）&& personInfo[i][1]。等于（args[2]）{ System.out.println（personInfo[i][2]）； } } System.out.println（）； 换句话说，我输入一个名字和姓氏，并希望获得的薪水为 personInfo字符串数组中的某个人。我如何够到并取下 一个人的薪水

public class A6{

    public static void main(String[] args){
        //String personInfo[][]=new String[][] { 
        String personInfo[][]={
                {"Anderson",  "Varejao",     "1125"},
                {"Giorgi",  "Tevzadze",      "1125"},
                {"Will",      "Cherry",      "1225"},
                {"Will",      "Iams",       "12245"},
                {"Lebron",    "James",       "6025"},
                {"Kevin",     "Love",        "2525"},
                {"Kyrie",     "Livings",      "454"},
                {"Kyrie",     "Botti",       "4544"},
                {"Chris",     "Mauer",        "425"},
                {"Mot",       "Daniel",       "125"},
                {"Viktor",    "Muller",       "145"},
                {"Kiamran",   "Chris",       "1405"},
                {"Zenia",     "Vaitehovic",  "1025"},
                {"Marija",    "Grabauskaite","1471"},
                {"Milda",    "Grabauskaite", "1000"},
                {"Dion",      "Waiters",     "625" },
                {"Dion",      "Malborg",    "6250" }
        };


        System.out.println("Peoples on the list:");
        for(int i = 0; i < personInfo.length; i++) {

            for(int j = 0; j < personInfo[i].length; j++) {
                System.out.print(" ");
                System.out.print(personInfo[i][j]);
            }

            System.out.println();
        }
        System.out.println("----------------------");

        //---------v XXX  - how many people have the first name XXX----------------

        String b = "v";

        if(args[0].equals(b))

        {

            System.out.println("Persons with entered name:");

            for(int i = 0; i < personInfo.length; i++) {

                for(int j = 0; j < personInfo[i].length; j++) {

                    if(personInfo[i][j].equals(args[1]))
                    {
                        System.out.println(args[1]);
                    }
                }
            }
            System.out.println();

        }
        //------vp XXX YYY - what is the salary of the person XXX YYY------
    }
}

姓名存储在第一个索引中，薪资存储在第二个维度的第三个索引中。
因此，您可以定义一个

findSalary（）

方法，该方法依赖于：

for(int i = 0; i < personInfo.length; i++) {
    if(personInfo[i][0].equals(args[1]) &&
            personInfo[i][1].equals(args[2]) {
        System.out.println(personInfo[i][2]);
    }
}
System.out.println();

---

请注意，使用

String

来表示数字可能不是最好的方法。

按空间分割搜索条件，并将结果存储在数组中，例如：result[2]

---

选中a[i][j]=result[0]第一部分和&checka[i][j+1]=result[1]第二部分，然后打印期望值，如果您仍然希望使用这种方式，那么这里就是您想要的

String personInfo[][]={ ...};
String salary = findSalary(personInfo, "john");

这是用C写的，希望对你有帮助

class Person {
    String name = "";
    String surName = "";
    String salary = "";
    //setters and getters here
}

string[，]personInfo=新字符串[，]{
{“安德森”，“瓦莱乔”，“1125”}，
{“Giorgi”，“Tevzadze”，“1125”}，
{“威尔”，“樱桃”，“1225”}，
{“威尔”、“Iams”、“12245”}，
{“勒布朗”，“詹姆斯”，“6025”}，
{“凯文”，“爱”，“2525”}，
{“Kyrie”，“Livings”，“454”}，
{“Kyrie”、“Botti”、“4544”}，
{“克里斯”，“摩尔”，“425”}，
{“Mot”，“Daniel”，“125”}，
{“维克多”、“穆勒”、“145”}，
{“Kiamran”，“Chris”，“1405”}，
{“Zenia”，“Vaitehovic”，“1025”}，
{“Marija”，“Grabauskaite”，“1471”}，
{“Milda”，“Grabauskaite”，“1000”}，
{“迪翁”，“侍者”，“625”}，
{“迪翁”、“马尔堡”、“6250”}
};
string FirstName=“Milda”；
字符串LastName=“Grabauskaite”；
for（int i=0；i

关于如何在数组中定位元素，由于薪资始终在personInfo[2]中，我将一次迭代数组一行，检查firstName是否对应于peopleinfo[0]中的元素&lName对应于peopleinfo[1]。 看起来像这样：

string[,] personInfo = new string[,] { 
    {"Anderson",  "Varejao",     "1125"},
    {"Giorgi",  "Tevzadze",      "1125"},
    {"Will",      "Cherry",      "1225"},
    {"Will",      "Iams",       "12245"},
    {"Lebron",    "James",       "6025"},
    {"Kevin",     "Love",        "2525"},
    {"Kyrie",     "Livings",      "454"},
    {"Kyrie",     "Botti",       "4544"},
    {"Chris",     "Mauer",        "425"},
    {"Mot",       "Daniel",       "125"},
    {"Viktor",    "Muller",       "145"},
    {"Kiamran",   "Chris",       "1405"},
    {"Zenia",     "Vaitehovic",  "1025"},
    {"Marija",    "Grabauskaite","1471"},
    {"Milda",    "Grabauskaite", "1000"},
    {"Dion",      "Waiters",     "625" },
    {"Dion",      "Malborg",    "6250" } 
};

string FirstName = "Milda";
string LastName = "Grabauskaite";

for (int i = 0; i < personInfo.GetLength(0); i++)
{
    if(personInfo[i,0] == FirstName && personInfo[i,1] == LastName)
    {
        Console.WriteLine(FirstName + " " + LastName + " Salary Is: " + personInfo[i,2]);
    }
}

---

请重新格式化你的代码，这真的一点也不可读。但是对于你的问题：只需搜索一个名字合适的人并打印出薪水就可以了，或者？因此，从“搜索一个人”复制你的代码，只需打印出他们的薪水而不打印出此人。循环数组的外部维度，然后。。。。

string[,] personInfo = new string[,] { 
    {"Anderson",  "Varejao",     "1125"},
    {"Giorgi",  "Tevzadze",      "1125"},
    {"Will",      "Cherry",      "1225"},
    {"Will",      "Iams",       "12245"},
    {"Lebron",    "James",       "6025"},
    {"Kevin",     "Love",        "2525"},
    {"Kyrie",     "Livings",      "454"},
    {"Kyrie",     "Botti",       "4544"},
    {"Chris",     "Mauer",        "425"},
    {"Mot",       "Daniel",       "125"},
    {"Viktor",    "Muller",       "145"},
    {"Kiamran",   "Chris",       "1405"},
    {"Zenia",     "Vaitehovic",  "1025"},
    {"Marija",    "Grabauskaite","1471"},
    {"Milda",    "Grabauskaite", "1000"},
    {"Dion",      "Waiters",     "625" },
    {"Dion",      "Malborg",    "6250" } 
};

string FirstName = "Milda";
string LastName = "Grabauskaite";

for (int i = 0; i < personInfo.GetLength(0); i++)
{
    if(personInfo[i,0] == FirstName && personInfo[i,1] == LastName)
    {
        Console.WriteLine(FirstName + " " + LastName + " Salary Is: " + personInfo[i,2]);
    }
}

static Scanner sc = new Scanner(System.in);

static String personInfo[][] = {
    {"Anderson", "Varejao", "1125"},
    {"Giorgi", "Tevzadze", "1125"},
    {"Will", "Cherry", "1225"},
    {"Will", "Iams", "12245"},
    {"Lebron", "James", "6025"},
    {"Kevin", "Love", "2525"},
    {"Kyrie", "Livings", "454"},
    {"Kyrie", "Botti", "4544"},
    {"Chris", "Mauer", "425"},
    {"Mot", "Daniel", "125"},
    {"Viktor", "Muller", "145"},
    {"Kiamran", "Chris", "1405"},
    {"Zenia", "Vaitehovic", "1025"},
    {"Marija", "Grabauskaite", "1471"},
    {"Milda", "Grabauskaite", "1000"},
    {"Dion", "Waiters", "625"},
    {"Dion", "Malborg", "6250"}
};

public static void main(String[] args) {

    System.out.print("Enter First Name: ");
    String fName = sc.nextLine();
    System.out.print("Enter Last Name: ");
    String lName = sc.nextLine();
    System.out.println(fName + " " + lName + "' Salary: " + salaryLookUp(personInfo, fName, lName));

}

static String salaryLookUp(String[][] array, String fName, String lName) {
    String salary = "";

    for (String[] row : personInfo) {
        if (row[0].equalsIgnoreCase(fName) && row[1].equalsIgnoreCase(lName)) {
            salary = row[2];
            break;
        } else {
            salary = "Not Found";
        }
    }
    return salary;
}