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Java 在hibernatre中映射集合的简单值类型时出现异常_Java_Hibernate - Fatal编程技术网

Java 在hibernatre中映射集合的简单值类型时出现异常

Java 在hibernatre中映射集合的简单值类型时出现异常,java,hibernate,Java,Hibernate,我有一个名为Person的实体,它的name属性为String,Personpetnames具有集合。当映射到Hibernate时,我遇到异常。我如何解决这个问题 /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package com.myapp.struts; import java.io.Serializable; import

我有一个名为
Person
实体
,它的name属性为
String
,Person
petnames
具有集合。当映射到
Hibernate
时,我遇到异常。我如何解决这个问题

    /*
 * To change this template, choose Tools | Templates
 * and open the template in the editor.
 */
package com.myapp.struts;

import java.io.Serializable;

import java.util.Set;
import javax.persistence.CollectionTable;
import javax.persistence.ElementCollection;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.JoinColumn;

/**
 *
 * @author hyva
 */
@Entity
public class Person implements Serializable {

    private static final long serialVersionUID = 1L;
        private Long id;

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    public Long getId() {
        return id;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public void setPetname(Set<String> petname) {
        this.petname = petname;
    }

    public void setId(Long id) {
        this.id = id;
    }
    private String name;
    private Set<String> petname;

    @ElementCollection
    @CollectionTable(name = "petname", joinColumns =
            @JoinColumn(name = "PERSON_ID"))
    public Set<String> getPetname() {
        return petname;
    }
}
/*
*要更改此模板,请选择工具|模板
*然后在编辑器中打开模板。
*/
包com.myapp.struts;
导入java.io.Serializable;
导入java.util.Set;
导入javax.persistence.CollectionTable;
导入javax.persistence.ElementCollection;
导入javax.persistence.Entity;
导入javax.persistence.GeneratedValue;
导入javax.persistence.GenerationType;
导入javax.persistence.Id;
导入javax.persistence.JoinColumn;
/**
*
*@作者海娃
*/
@实体
公共类Person实现可序列化{
私有静态最终长serialVersionUID=1L;
私人长id;
@身份证
@GeneratedValue(策略=GenerationType.AUTO)
公共长getId(){
返回id;
}
公共字符串getName(){
返回名称;
}
公共void集合名(字符串名){
this.name=名称;
}
公共无效setPetname(Set petname){
this.petname=petname;
}
公共无效集合id(长id){
this.id=id;
}
私有字符串名称;
私有集名称;
@元素集合
@CollectionTable(name=“petname”,joinColumns=
@JoinColumn(name=“PERSON\u ID”))
公共集getPetname(){
返回petname;
}
}
*例外情况:

Initial SessionFactory creation failed.org.hibernate.MappingException: Could not determine type for: java.util.Set, for columns: [org.hibernate.mapping.Column(petname)]
Exception in thread "main" java.lang.ExceptionInInitializerError
    at com.myapp.struts.HibernateUtil.<clinit>(HibernateUtil.java:28)
    at com.myapp.struts.HibernateComplexValue.main(HibernateComplexValue.java:19)
Caused by: org.hibernate.MappingException: Could not determine type for: java.util.Set, for columns: [org.hibernate.mapping.Column(petname)]
    at org.hibernate.mapping.SimpleValue.getType(SimpleValue.java:266)
    aJava Result: 1
初始SessionFactory创建失败。org.hibernate.MappingException:无法确定以下列的类型:java.util.Set:[org.hibernate.mapping.Column(petname)]
线程“main”java.lang.ExceptionInInitializeError中出现异常
位于com.myapp.struts.HibernateUtil.(HibernateUtil.java:28)
位于com.myapp.struts.HibernateComplexValue.main(HibernateComplexValue.java:19)
原因:org.hibernate.MappingException:无法确定以下列的类型:java.util.Set:[org.hibernate.mapping.Column(petname)]
位于org.hibernate.mapping.SimpleValue.getType(SimpleValue.java:266)
阿贾瓦结果:1

@CollectionTable
移到
getPetname
上作为注释,如下所示:

private Set<String> petname;

@ElementCollection
@CollectionTable(name = "pets", joinColumns =@JoinColumn(name = "PERSON_ID"))
public Set<String> getPetname(){
      return petname;
}
private-Set-petname;
@元素集合
@CollectionTable(name=“pets”,joinColumns=@JoinColumn(name=“PERSON\u ID”))
公共集getPetname(){
返回petname;
}
您的注释@CollectionTable位于您的属性名称之后!是否存在复制/粘贴错误

您尚未映射petname列。默认属性名与表名相同(petname)…
此表中包含宠物名的列的名称应该是什么


尝试添加
@Column(name=“YOUR\u Column\u name”)
以强制映射到此列。

我没有将实体映射到实体。您发布的代码似乎不完整。你能发布所有这些吗?你的hibernate版本是什么?Person有哪些列?我正在使用hibernate 3.2.5。JPA版本呢?我仍然面临同样的问题。