Java 如何询问用户是否希望使用do while重复计算

这是我用java编写的一个基本计算器。一旦显示输出，我想询问用户是否要继续，如果他说是，然后重复这个过程。我已经检查了许多关于堆栈溢出的主题，但我仍然不知道如何通过do while循环实现我的目标，有人可以帮助吗

import java.util.Scanner;

public class SecondQuestion {

    public static void main(String[] args) {
        // TODO Auto-generated method stub

        double firstN; 
        double secondN; 
        char operator;

        Scanner readInput = new Scanner(System.in);

        System.out.printf("Type a number, operator, number --" + "separated by a space: "); 

        firstN = readInput.nextDouble();
        operator = readInput.next().charAt(0); 
        secondN = readInput.nextDouble();

        if (operator == '+')
            System.out.printf("%f + %f = %f", firstN, secondN, firstN + secondN); 

        else if (operator == '-') 
            System.out.printf("%f - %f = %f", firstN, secondN, firstN - secondN); 

        else if (operator == '*')
            System.out.printf("%f * %f = %f", firstN, secondN, firstN * secondN); 

        else if (operator == '/')
            System.out.printf("%f / %f = %f", firstN, secondN, firstN / secondN); 

        else if (operator == '%')
            System.out.printf("%f %% %f = %f", firstN, secondN,firstN % secondN); 

        else
            System.out.printf("Unknown operator"); 
        System.out.printf("\n\n");

        int loopCount = 0;
        char charResponse='y';
        Scanner readInput1 = new Scanner (System.in);
        while (charResponse !='y')
        {
            System.out.println("press y");
            charResponse = readInput1.next().charAt(0);
        }
    }

}

---

使用

do while

：

public static void main(String[] args) {
    // TODO Auto-generated method stub

    double firstN;
    double secondN;
    char operator;

    Scanner readInput = new Scanner(System.in);
    char charResponse = 'y';
    do {
        System.out.printf("Type a number, operator, number --" + "separated by a space: ");

        firstN = readInput.nextDouble();
        operator = readInput.next().charAt(0);
        secondN = readInput.nextDouble();

        if (operator == '+')
            System.out.printf("%f + %f = %f", firstN, secondN, firstN + secondN);

        else if (operator == '-')
            System.out.printf("%f - %f = %f", firstN, secondN, firstN - secondN);

        else if (operator == '*')
            System.out.printf("%f * %f = %f", firstN, secondN, firstN * secondN);

        else if (operator == '/')
            System.out.printf("%f / %f = %f", firstN, secondN, firstN / secondN);

        else if (operator == '%')
            System.out.printf("%f %% %f = %f", firstN, secondN, firstN % secondN);

        else
            System.out.printf("Unknown operator");
        System.out.printf("\n\n");

        int loopCount = 0;
        Scanner readInput1 = new Scanner(System.in);
        System.out.println("press y to continue");
        charResponse = readInput1.next().charAt(0);
    } while (charResponse == 'y');

}

---

do while

循环是一个增量后循环，因此它将首先执行，然后检查while中的条件。

问题说明如何明确使用

do while

。非常感谢您的回答。然而，你现在使用的方法超出了我的知识范围。我希望通过进一步的学习，我能理解你的答案。非常感谢你的帮助，我是Java新手，这真的很有帮助。我试过了，真的很管用。再次感谢！！！请考虑通过回答旁边的绿色刻痕来接受我的答案，我真的很感激。

public static void main(String[] args) {
    // TODO Auto-generated method stub

    double firstN;
    double secondN;
    char operator;

    Scanner readInput = new Scanner(System.in);
    char charResponse = 'y';
    do {
        System.out.printf("Type a number, operator, number --" + "separated by a space: ");

        firstN = readInput.nextDouble();
        operator = readInput.next().charAt(0);
        secondN = readInput.nextDouble();

        if (operator == '+')
            System.out.printf("%f + %f = %f", firstN, secondN, firstN + secondN);

        else if (operator == '-')
            System.out.printf("%f - %f = %f", firstN, secondN, firstN - secondN);

        else if (operator == '*')
            System.out.printf("%f * %f = %f", firstN, secondN, firstN * secondN);

        else if (operator == '/')
            System.out.printf("%f / %f = %f", firstN, secondN, firstN / secondN);

        else if (operator == '%')
            System.out.printf("%f %% %f = %f", firstN, secondN, firstN % secondN);

        else
            System.out.printf("Unknown operator");
        System.out.printf("\n\n");

        int loopCount = 0;
        Scanner readInput1 = new Scanner(System.in);
        System.out.println("press y to continue");
        charResponse = readInput1.next().charAt(0);
    } while (charResponse == 'y');

}