Java 忽略字符串数组中的特定元素

我正在编写一个程序，它忽略了字符串中“/”和“/”符号之间的所有内容，就像真实场景中的IDE一样。我将字符串拆分为行并存储在数组中，然后使用while循环从当前行中的单个字符构建单词，忽略符号，但是我的输出不太正确

下面是我试图实现的一个例子

Phrase: The quick brown /* fox jumped over the */ lazy dog.

Desired output: The quick brown lazy dog.

基本上删除了注释之间的所有内容

这是我目前的尝试

public class Testing6 {

public static void main(String[] args) {
    String riddle = "The Quick \n" +
            " brown /* fox \n" +
            " jumped over \n" +
            " the  */ lazy \n" +
            " dog \n";

    String[] lines = riddle.split("\\r?\\n");

    for (String line : lines) {
        int n = line.length();
        int index = 0;
        String word = "";

        while (index < n) {

            char ch = line.charAt(index);

            word = word + ch;

            if (ch == ' ' )  //if ch is empty, word is complete, print word.
            {
                System.out.println(word);
                word = "";
            }
            if (ch == '/' || ch == '*') { // checking for symbols

                index++;
                if (ch == '*' || ch == '/')
                {
                    index++;
                    break; // breaking if symbols match
                }

            }

            index++;
        }

        }
    }

}

---

提前感谢您的反馈。

我正在修改您的答案，以便按照您的期望显示该行。这里没有对代码进行真正的增强

以下是代码中的问题：

您正在使用

println

，它在新行中打印每个字符串

您还可以打印空单词，从而在输出中看到字符串中的间隙

我修复了以上两个问题，现在它可以正常显示了

String riddle = "The Quick \n" +
                " brown /* fox \n" +
                " jumped over \n" +
                " the  */ lazy \n" +
                " dog \n";

String[] lines = riddle.split("\\r?\\n");
String word = "";
for (String line : lines) {
    int n = line.length();
    for (int index = 0; index < n; index++) {
        char ch = line.charAt(index);
        if (ch == ' ') { // if ch is empty, word is complete, print word.
            if (!word.isEmpty()) { // do not log empty word
                word = word + ch;
                System.out.print(word);
                word = "";
            }
            continue;
        }
        if (ch == '/' || ch == '*') { // checking for symbols
            index++;
            if (ch == '*' || ch == '/') {
                index++;
                break; // breaking if symbols match
            }
        }
        word = word + ch; // only non-empty chars are added here
    }
}

---

请注意，根据您的输入，最后一个单词可能包含额外的空格。但我想你可以从这里开始。

你的问题是什么？如果你只是想检查你的代码，去应聘者需要修改他的代码。这不是真正的代码审查。

String riddle = "The Quick \n" +
                " brown /* fox \n" +
                " jumped over \n" +
                " the  */ lazy \n" +
                " dog \n";

String[] lines = riddle.split("\\r?\\n");
String word = "";
for (String line : lines) {
    int n = line.length();
    for (int index = 0; index < n; index++) {
        char ch = line.charAt(index);
        if (ch == ' ') { // if ch is empty, word is complete, print word.
            if (!word.isEmpty()) { // do not log empty word
                word = word + ch;
                System.out.print(word);
                word = "";
            }
            continue;
        }
        if (ch == '/' || ch == '*') { // checking for symbols
            index++;
            if (ch == '*' || ch == '/') {
                index++;
                break; // breaking if symbols match
            }
        }
        word = word + ch; // only non-empty chars are added here
    }
}

The Quick brown jumped over the dog