Java 格式化字符串以查找和替换段

我有以下Java字符串

String abc="My name 233:23 is Shefali MNT+2:199999' MNT+12:40 xyzpqrst";

我希望前面的数字后面跟着

MNT+2

，然后冒号（：）即199999应替换为1，字符串的其余部分应保持不变

i、 e。 O/p应该是

“我的名字233:23是Shefali MNT+2:1'MNT+12:40 xyzpqrst”

第二例>> 如果输入字符串是“ABC:MNT+232421:9'MNT+39191:hks”

O/p应为“ABC:MNT+232421:1'MNT+39191:hks”

我试了很多东西，但都没弄明白

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有人能帮忙吗？

您可以使用以下正则表达式：

（MNT\+\d+）:\d+'

并使用此替换字符串：

$1:1'

查看它的实际操作：

使用replaceAll（）

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您可以使用一些分组表达式，例如

String[] arr = { "My name 233:23 is Shefali MNT+2:199999' MNT+12:40 xyzpqrst",
        "ABC : MNT+232421:9' MNT+39191: hks" };
String[] out = { "My name 233:23 is Shefali MNT+2:1' MNT+12:40 xyzpqrst",
        "ABC : MNT+232421:1' MNT+39191: hks" };
Pattern p = Pattern.compile("(.*):(\\d+)'(.*)");
for (int i = 0; i < arr.length; i++) {
    Matcher m = p.matcher(arr[i]);
    if (m.matches()) {
        String t = m.group(1) + ":1'" + m.group(3);
        System.out.printf("%s = %s %s%n", t, out[i], t.equals(out[i]));
    }
}

使用正则表达式使用

replaceAll（）

String abc="My name 233:23 is Shefali MNT+2:199999' MNT+12:40 xyzpqrst";
abc.replaceAll("(MNT\\+\\d+):\\d+'", "$1:1'")

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它将取代给定模式的所有发生。

< P>一个正则表达式是比较简单的，但是为了比较，让我们看看另一种方式。

String abc="My name 233:23 is Shefali MNT+2:199999' MNT+12:40 xyzpqrst";

//get index of the start of first "MNT"
int mntIndex = abc.indexOf("MNT+2:");

//get index of the second "MNT" location
int mntIndex2 = abc.indexOf("' MNT", mntIndex);

//now set abc equal to a substring up to the end of "MNT+2:"
//adding 6 (the length of "MNT+2:")
//manually adding "1" 
//finishing with a substring of abc starting 
//from the "' MNT" index up to the end of abc (abc.length())
abc = abc.substring(0, mntIndex) + 1 + abc.substring(mntIndex2,abc.length());

String abc="My name 233:23 is Shefali MNT+2:199999' MNT+12:40 xyzpqrst";
abc.replaceAll("(MNT\\+\\d+):\\d+'", "$1:1'")

String abc="My name 233:23 is Shefali MNT+2:199999' MNT+12:40 xyzpqrst";

//get index of the start of first "MNT"
int mntIndex = abc.indexOf("MNT+2:");

//get index of the second "MNT" location
int mntIndex2 = abc.indexOf("' MNT", mntIndex);

//now set abc equal to a substring up to the end of "MNT+2:"
//adding 6 (the length of "MNT+2:")
//manually adding "1" 
//finishing with a substring of abc starting 
//from the "' MNT" index up to the end of abc (abc.length())
abc = abc.substring(0, mntIndex) + 1 + abc.substring(mntIndex2,abc.length());